mohamed Hamouday' Answer的扩展将填补缺失的关键

function Object_Manager(obj, Path, value, Action, strict) 
{
    try
    {
        if(Array.isArray(Path) == false)
        {
            Path = [Path];
        }

        let level = 0;
        var Return_Value;
        Path.reduce((a, b)=>{
            console.log(level,':',a, '|||',b)
            if (!strict){
              if (!(b in a)) a[b] = {}
            }


            level++;
            if (level === Path.length)
            {
                if(Action === 'Set')
                {
                    a[b] = value;
                    return value;
                }
                else if(Action === 'Get')
                {
                    Return_Value = a[b];
                }
                else if(Action === 'Unset')
                {
                    delete a[b];
                }
            } 
            else 
            {
                return a[b];
            }
        }, obj);
        return Return_Value;
    }

    catch(err)
    {
        console.error(err);
        return obj;
    }
}

例子

obja = {
  "a": {
    "b":"nom"
  }
}

// Set
path = "c.b" // Path does not exist
Object_Manager(obja,path.split('.'), 'test_new_val', 'Set', false);

// Expected Output: Object { a: Object { b: "nom" }, c: Object { b: "test_new_value" } }

根据阿尔尼塔克的回答。

我把填充材料包在格子里，将函数简化为单链还原。

如果对象。byPath === undefined) { 对象。byPath = (obj, path) =>路径 .replace (/ \ [(\ w +) \] / g, 1美元。) .replace(/ ^ \。/”) .split (/ \ / g)。 .reduce((ref, key) => key in ref ?Ref [key]: Ref, obj) ｝ Const data = { foo: { 酒吧:[{ 记者:1 }) ｝ ｝ console.log(对象。小路(数据,foo.bar [0] .baz '))

基于前面的回答，我创建了一个也可以处理括号的函数。但由于裂开，里面没有点。

function get(obj, str) {
  return str.split(/\.|\[/g).map(function(crumb) {
    return crumb.replace(/\]$/, '').trim().replace(/^(["'])((?:(?!\1)[^\\]|\\.)*?)\1$/, (match, quote, str) => str.replace(/\\(\\)?/g, "$1"));
  }).reduce(function(obj, prop) {
    return obj ? obj[prop] : undefined;
  }, obj);
}

数组可以代替字符串来处理嵌套对象和数组，例如:["my_field"， "another_field"， 0， "last_field"， 10]

下面是一个基于该数组表示方式更改字段的示例。我在react.js中使用类似的东西来控制输入字段，改变嵌套结构的状态。

let state = {
        test: "test_value",
        nested: {
            level1: "level1 value"
        },
        arr: [1, 2, 3],
        nested_arr: {
            arr: ["buh", "bah", "foo"]
        }
    }

function handleChange(value, fields) {
    let update_field = state;
    for(var i = 0; i < fields.length - 1; i++){
        update_field = update_field[fields[i]];
    }
    update_field[fields[fields.length-1]] = value;
}

handleChange("update", ["test"]);
handleChange("update_nested", ["nested","level1"]);
handleChange(100, ["arr",0]);
handleChange('changed_foo', ["nested_arr", "arr", 3]);
console.log(state);

// (IE9+) Two steps var pathString = "[0]['property'].others[3].next['final']"; var obj = [{ property: { others: [1, 2, 3, { next: { final: "SUCCESS" } }] } }]; // Turn string to path array var pathArray = pathString .replace(/\[["']?([\w]+)["']?\]/g,".$1") .split(".") .splice(1); // Add object prototype method Object.prototype.path = function (path) { try { return [this].concat(path).reduce(function (f, l) { return f[l]; }); } catch (e) { console.error(e); } }; // usage console.log(obj.path(pathArray)); console.log(obj.path([0,"doesNotExist"]));

简单的函数，允许字符串或数组路径。

function get(obj, path) {
  if(typeof path === 'string') path = path.split('.');

  if(path.length === 0) return obj;
  return get(obj[path[0]], path.slice(1));
}

const obj = {a: {b: {c: 'foo'}}};

console.log(get(obj, 'a.b.c')); //foo

OR

console.log(get(obj, ['a', 'b', 'c'])); //foo