Android系统中是否有一种方法可以检测软件(也就是Android。“软”)键盘在屏幕上可见吗?
当前回答
There is a direct method to find this out. And, it does not require the layout changes. So it works in immersive fullscreen mode, too. But, unfortunately, it does not work on all devices. So you have to test it with your device(s). The trick is that you try to hide or show the soft keyboard and capture the result of that try. If it works correct then the keyboard is not really shown or hidden. We just ask for the state. To stay up-to-date, you simply repeat this operation, e.g. every 200 milliseconds, using a Handler. The implementation below does just a single check. If you do multiple checks, then you should enable all the (_keyboardVisible) tests.
public interface OnKeyboardShowHide
{
void onShowKeyboard( Object param );
void onHideKeyboard( Object param );
}
private static Handler _keyboardHandler = new Handler();
private boolean _keyboardVisible = false;
private OnKeyboardShowHide _keyboardCallback;
private Object _keyboardCallbackParam;
public void start( OnKeyboardShowHide callback, Object callbackParam )
{
_keyboardCallback = callback;
_keyboardCallbackParam = callbackParam;
//
View view = getCurrentFocus();
if (view != null)
{
InputMethodManager imm = (InputMethodManager) getSystemService( Activity.INPUT_METHOD_SERVICE );
imm.hideSoftInputFromWindow( view.getWindowToken(), InputMethodManager.HIDE_IMPLICIT_ONLY, _keyboardResultReceiver );
imm.showSoftInput( view, InputMethodManager.SHOW_IMPLICIT, _keyboardResultReceiver );
}
else // if (_keyboardVisible)
{
_keyboardVisible = false;
_keyboardCallback.onHideKeyboard( _keyboardCallbackParam );
}
}
private ResultReceiver _keyboardResultReceiver = new ResultReceiver( _keyboardHandler )
{
@Override
protected void onReceiveResult( int resultCode, Bundle resultData )
{
switch (resultCode)
{
case InputMethodManager.RESULT_SHOWN :
case InputMethodManager.RESULT_UNCHANGED_SHOWN :
// if (!_keyboardVisible)
{
_keyboardVisible = true;
_keyboardCallback.onShowKeyboard( _keyboardCallbackParam );
}
break;
case InputMethodManager.RESULT_HIDDEN :
case InputMethodManager.RESULT_UNCHANGED_HIDDEN :
// if (_keyboardVisible)
{
_keyboardVisible = false;
_keyboardCallback.onHideKeyboard( _keyboardCallbackParam );
}
break;
}
}
};
其他回答
试试这个,对我很有效
InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
if (imm.isActive())
//Keyboard is active
这里有一个工作区,以了解软键盘是否可见。
使用ActivityManager.getRunningServices(max_count_of_services)检查系统上正在运行的服务; 从返回的ActivityManager。运行ningserviceinfo实例,检查软键盘服务的clientCount值。 前面提到的clientCount将在每次显示软键盘时递增。例如,如果clientCount最初是1,那么在显示键盘时它将是2。 在键盘撤销时,clientCount递减。在本例中,它重置为1。
一些流行的键盘在它们的classname中有特定的关键字:
谷歌AOSP = IME Swype =输入法 Swiftkey = KeyboardService Fleksy =键盘 Adaptxt = IME (KPTAdaptxtIME) 智能=键盘(SmartKeyboard)
从ActivityManager。RunningServiceInfo,在ClassNames中检查上述模式。 同时,ActivityManager。RunningServiceInfo的clientPackage=android,表示键盘绑定到系统。
可以将上述信息进行严格的组合,以判断软键盘是否可见。
这是如何在一个片段中使用软键盘状态监听器(适用于API 21及以上)
private var currentWindowInsets: WindowInsetsCompat = WindowInsetsCompat.Builder().build()
override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
super.onViewCreated(view, savedInstanceState)
setWindowInsetsAnimationCallback(requireView().rootView, object : Callback(DISPATCH_MODE_CONTINUE_ON_SUBTREE) {
override fun onProgress(insets: WindowInsetsCompat, runningAnimations: MutableList<WindowInsetsAnimationCompat>): WindowInsetsCompat {
currentWindowInsets = insets
return insets
}
override fun onEnd(animation: WindowInsetsAnimationCompat) {
super.onEnd(animation)
val keyboardIsVisible = currentWindowInsets.isVisible(WindowInsetsCompat.Type.ime())
if (keyboardIsVisible) { //do your stuff }
}
})
}
在Android中,你可以通过ADB shell进行检测。我写下并使用了这个方法:
{
JSch jsch = new JSch();
try {
Session session = jsch.getSession("<userName>", "<IP>", 22);
session.setPassword("<Password>");
Properties config = new Properties();
config.put("StrictHostKeyChecking", "no");
session.setConfig(config);
session.connect();
ChannelExec channel = (ChannelExec)session.openChannel("exec");
BufferedReader in = new BufferedReader(new
InputStreamReader(channel.getInputStream()));
channel.setCommand("C:/Android/android-sdk/platform-tools/adb shell dumpsys window
InputMethod | findstr \"mHasSurface\"");
channel.connect();
String msg = null;
String msg2 = " mHasSurface=true";
while ((msg = in.readLine()) != null) {
Boolean isContain = msg.contains(msg2);
log.info(isContain);
if (isContain){
log.info("Hiding keyboard...");
driver.hideKeyboard();
}
else {
log.info("No need to hide keyboard.");
}
}
channel.disconnect();
session.disconnect();
} catch (JSchException | IOException | InterruptedException e) {
e.printStackTrace();
}
}
}
我通过设置一个GlobalLayoutListener来做到这一点,如下所示:
final View activityRootView = findViewById(R.id.activityRoot);
activityRootView.getViewTreeObserver().addOnGlobalLayoutListener(
new OnGlobalLayoutListener() {
@Override
public void onGlobalLayout() {
int heightView = activityRootView.getHeight();
int widthView = activityRootView.getWidth();
if (1.0 * widthView / heightView > 3) {
//Make changes for Keyboard not visible
} else {
//Make changes for keyboard visible
}
}
});
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