我怎么能计算“_”的数量在一个字符串像“bla_bla_blabla_bla”?
当前回答
#include <algorithm>
std::string s = "a_b_c";
std::string::difference_type n = std::count(s.begin(), s.end(), '_');
其他回答
public static void main(String[] args) {
char[] array = "aabsbdcbdgratsbdbcfdgs".toCharArray();
char[][] countArr = new char[array.length][2];
int lastIndex = 0;
for (char c : array) {
int foundIndex = -1;
for (int i = 0; i < lastIndex; i++) {
if (countArr[i][0] == c) {
foundIndex = i;
break;
}
}
if (foundIndex >= 0) {
int a = countArr[foundIndex][1];
countArr[foundIndex][1] = (char) ++a;
} else {
countArr[lastIndex][0] = c;
countArr[lastIndex][1] = '1';
lastIndex++;
}
}
for (int i = 0; i < lastIndex; i++) {
System.out.println(countArr[i][0] + " " + countArr[i][1]);
}
}
计算字符串中出现的字符很简单:
#include <bits/stdc++.h>
using namespace std;
int main()
{
string s="Sakib Hossain";
int cou=count(s.begin(),s.end(),'a');
cout<<cou;
}
基于范围的for循环很方便
int countUnderScores(string str)
{
int count = 0;
for (char c: str)
if (c == '_') count++;
return count;
}
int main()
{
string str = "bla_bla_blabla_bla";
int count = countUnderScores(str);
cout << count << endl;
}
你可以使用字符串函数找出源字符串中'_'的出现情况。 Find()函数有两个参数,第一个参数是我们想要找出其出现的字符串,第二个参数是起始位置。While循环用于在源字符串结束之前查找发生的情况。
例子:
string str2 = "_";
string strData = "bla_bla_blabla_bla_";
size_t pos = 0,pos2;
while ((pos = strData.find(str2, pos)) < strData.length())
{
printf("\n%d", pos);
pos += str2.length();
}
#include <boost/range/algorithm/count.hpp>
std::string str = "a_b_c";
int cnt = boost::count(str, '_');