查询:

search = productName

参数:

page = 1 

// Pagination
router.get("/search/:page", (req, res, next) => {
    const resultsPerPage = 5;
    let page = req.params.page >= 1 ? req.params.page : 1;
    const query = req.query.search;

    page = page - 1

    Product.find({ name: query })
        .select("name")
        .sort({ name: "asc" })
        .limit(resultsPerPage)
        .skip(resultsPerPage * page)
        .then((results) => {
            return res.status(200).send(results);
        })
        .catch((err) => {
            return res.status(500).send(err);
        });
});

使用猫鼬，快递和翡翠的分页-这里有一个链接到我的博客与更多的细节

var perPage = 10
  , page = Math.max(0, req.params.page)

Event.find()
    .select('name')
    .limit(perPage)
    .skip(perPage * page)
    .sort({
        name: 'asc'
    })
    .exec(function(err, events) {
        Event.count().exec(function(err, count) {
            res.render('events', {
                events: events,
                page: page,
                pages: count / perPage
            })
        })
    })

app.get("/:page",(req,res)=>{
        post.find({}).then((data)=>{
            let per_page = 5;
            let num_page = Number(req.params.page);
            let max_pages = Math.ceil(data.length/per_page);
            if(num_page == 0 || num_page > max_pages){
                res.render('404');
            }else{
                let starting = per_page*(num_page-1)
                let ending = per_page+starting
                res.render('posts', {posts:data.slice(starting,ending), pages: max_pages, current_page: num_page});
            }
        });
});

简单而强大的分页解决方案

async getNextDocs(no_of_docs_required: number = 5, last_doc_id?: string) {
    let docs

    if (!last_doc_id) {
        // get first 5 docs
        docs = await MySchema.find().sort({ _id: -1 }).limit(no_of_docs_required)
    }
    else {
        // get next 5 docs according to that last document id
        docs = await MySchema.find({_id: {$lt: last_doc_id}})
                                    .sort({ _id: -1 }).limit(no_of_docs_required)
    }
    return docs
}

Last_doc_id:您获得的最后一个文档id

No_of_docs_required:你想要获取的文档数量，例如5、10、50等。

如果你不提供last_doc_id给方法，你会得到5个最新的文档 如果你提供了last_doc_id，那么你会得到下一个，即5个文档。

也可以用async/await实现结果。

下面的代码示例使用hapi v17和mongoose v5的异步处理程序

{
            method: 'GET',
            path: '/api/v1/paintings',
            config: {
                description: 'Get all the paintings',
                tags: ['api', 'v1', 'all paintings']
            },
            handler: async (request, reply) => {
                /*
                 * Grab the querystring parameters
                 * page and limit to handle our pagination
                */
                var pageOptions = {
                    page: parseInt(request.query.page) - 1 || 0, 
                    limit: parseInt(request.query.limit) || 10
                }
                /*
                 * Apply our sort and limit
                */
               try {
                    return await Painting.find()
                        .sort({dateCreated: 1, dateModified: -1})
                        .skip(pageOptions.page * pageOptions.limit)
                        .limit(pageOptions.limit)
                        .exec();
               } catch(err) {
                   return err;
               }

            }
        }

有一些很好的答案给出了使用skip()和limit()的解决方案，但是，在某些情况下，我们还需要文档计数来生成分页。以下是我们在项目中所做的:

const PaginatePlugin = (schema, options) => {
  options = options || {}
  schema.query.paginate = async function(params) {
    const pagination = {
      limit: options.limit || 10,
      page: 1,
      count: 0
    }
    pagination.limit = parseInt(params.limit) || pagination.limit
    const page = parseInt(params.page)
    pagination.page = page > 0 ? page : pagination.page
    const offset = (pagination.page - 1) * pagination.limit

    const [data, count] = await Promise.all([
      this.limit(pagination.limit).skip(offset),
      this.model.countDocuments(this.getQuery())
    ]);
    pagination.count = count;
    return { data, pagination }
  }
}

mySchema.plugin(PaginatePlugin, { limit: DEFAULT_LIMIT })

// using async/await
const { data, pagination } = await MyModel.find(...)
  .populate(...)
  .sort(...)
  .paginate({ page: 1, limit: 10 })

// or using Promise
MyModel.find(...).paginate(req.query)
  .then(({ data, pagination }) => {

  })
  .catch(err => {

  })