我对PHP、JavaScript和许多其他脚本语言很有经验，但我对Java或Android没有太多经验。
我正在寻找一种方法将POST数据发送到PHP脚本并显示结果。
当前回答
注(2020年10月):以下答案中使用的AsyncTask已在Android API级别30中弃用。有关更新的示例，请参考官方文档或本博客文章
更新(2017年6月)答案，适用于Android 6.0+。感谢@Rohit Suthar， @Tamis Bolvari和@sudhiskr的评论。
public class CallAPI extends AsyncTask<String, String, String> {
public CallAPI(){
//set context variables if required
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected String doInBackground(String... params) {
String urlString = params[0]; // URL to call
String data = params[1]; //data to post
OutputStream out = null;
try {
URL url = new URL(urlString);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
out = new BufferedOutputStream(urlConnection.getOutputStream());
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
writer.write(data);
writer.flush();
writer.close();
out.close();
urlConnection.connect();
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
}
引用:
https://developer.android.com/reference/java/net/HttpURLConnection.html 如何使用NameValuePair使用POST添加参数到HttpURLConnection
原答案(2010年5月)
注意:此解决方案已过时。它只能在5.1版本以下的安卓设备上运行。Android 6.0及以上版本不包括本回答中使用的Apache http客户端。
来自Apache Commons的Http Client是可行的。它已经包含在android中。下面是一个简单的例子，说明如何使用它来执行HTTP Post。
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "Hi"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
其他回答
@primpop的答案，我会添加如何转换字符串中的响应:
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream instream = entity.getContent();
String result = RestClient.convertStreamToString(instream);
Log.i("Read from server", result);
}
下面是一个convertStramToString的例子。
注(2020年10月):以下答案中使用的AsyncTask已在Android API级别30中弃用。有关更新的示例，请参考官方文档或本博客文章
更新(2017年6月)答案，适用于Android 6.0+。感谢@Rohit Suthar， @Tamis Bolvari和@sudhiskr的评论。
public class CallAPI extends AsyncTask<String, String, String> {
public CallAPI(){
//set context variables if required
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected String doInBackground(String... params) {
String urlString = params[0]; // URL to call
String data = params[1]; //data to post
OutputStream out = null;
try {
URL url = new URL(urlString);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
out = new BufferedOutputStream(urlConnection.getOutputStream());
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
writer.write(data);
writer.flush();
writer.close();
out.close();
urlConnection.connect();
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
}
引用:
https://developer.android.com/reference/java/net/HttpURLConnection.html 如何使用NameValuePair使用POST添加参数到HttpURLConnection
原答案(2010年5月)
注意:此解决方案已过时。它只能在5.1版本以下的安卓设备上运行。Android 6.0及以上版本不包括本回答中使用的Apache http客户端。
来自Apache Commons的Http Client是可行的。它已经包含在android中。下面是一个简单的例子，说明如何使用它来执行HTTP Post。
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "Hi"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
最好使用Apache Commons HttpClient，它已经包含在android中了。 看一看 Android开发人员:Apache HTTP客户端包摘要 一般API信息。
您可以使用WebServer类POST一个HttpRequest，并在其侦听器接口中跟踪响应。
WebServer server=new WebServer(getApplicationContext());
server.setOnServerStatusListner(new WebServer.OnServerStatusListner() {
@Override
public void onServerResponded(String responce) {
}
@Override
public void onServerRevoked() {
}
});
现在创建一个DataRack来绑定数据
List<DataRack> racks=new ArrayList<DataRack>();
racks.add(new DataRack("name","Simon"));
racks.add(new DataRack("age","40"));
racks.add(new DataRack("location","Canada"));
现在只需发送带有该机架的POST请求
server.connectWithPOST(MainActivity.this,"http://sangeethnandakumar.esy.es/PROJECTS/PUBLIC_SERVICE/posttest.php",racks);
你需要包括我的库。文件在这里
这是一个如何在不使用外部Apache库的情况下POST多部分数据的例子:
byte[] buffer = getBuffer();
if(buffer.length > 0) {
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "RQdzAAihJq7Xp1kjraqf";
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
// Send parameter #1
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param1\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain; charset=US-ASCII" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: 8bit" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(myStringData + lineEnd);
// Send parameter #2
//dos.writeBytes(twoHyphens + boundary + lineEnd);
//dos.writeBytes("Content-Disposition: form-data; name=\"param2\"" + lineEnd + lineEnd);
//dos.writeBytes("foo2" + lineEnd);
// Send a binary file
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param3\";filename=\"test_file.dat\"" + lineEnd);
dos.writeBytes("Content-Type: application/octet-stream" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: binary" + lineEnd);
dos.writeBytes(lineEnd);
dos.write(buffer);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.flush();
dos.close();
ByteArrayInputStream content = new ByteArrayInputStream(baos.toByteArray());
BasicHttpEntity entity = new BasicHttpEntity();
entity.setContent(content);
HttpPost httpPost = new HttpPost(myURL);
httpPost.addHeader("Connection", "Keep-Alive");
httpPost.addHeader("Content-Type", "multipart/form-data; boundary="+boundary);
//MultipartEntity entity = new MultipartEntity();
//entity.addPart("param3", new ByteArrayBody(buffer, "test_file.dat"));
//entity.addPart("param1", new StringBody(myStringData));
httpPost.setEntity(entity);
/*
String httpData = "";
ByteArrayOutputStream baos1 = new ByteArrayOutputStream();
entity.writeTo(baos1);
httpData = baos1.toString("UTF-8");
*/
/*
Header[] hdrs = httpPost.getAllHeaders();
for(Header hdr: hdrs) {
httpData += hdr.getName() + " | " + hdr.getValue() + " |_| ";
}
*/
//Log.e(TAG, "httpPost data: " + httpData);
response = httpClient.execute(httpPost);
}
推荐文章
- 带有返回类型的Java方法在没有返回语句的情况下编译
- Java“此语言级别不支持lambda表达式”
- “Java”不能被识别为内部或外部命令
- 使用PHP获取客户端IP地址
- JPA:如何将本机查询结果集转换为POJO类集合
- 日历日期为yyyy-MM-dd格式的java
- 在IntelliJ IDEA中导入Maven依赖项
- 如何防止回到以前的活动?
- 在Java中转换float为String和String为float
- Android模拟器没有启动，显示“无效的命令行参数”
- 获取PHP中的URL参数
- 将double类型转换为字符串
- Android防止双击按钮
- 在Android上理解颜色(6个字符)
- Java关联数组
