我对PHP、JavaScript和许多其他脚本语言很有经验,但我对Java或Android没有太多经验。
我正在寻找一种方法将POST数据发送到PHP脚本并显示结果。
我对PHP、JavaScript和许多其他脚本语言很有经验,但我对Java或Android没有太多经验。
我正在寻找一种方法将POST数据发送到PHP脚本并显示结果。
当前回答
方法将数据作为HTTP请求发布,
public static InputStream callPostService(String Url,
List<NameValuePair> data) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(Url);
try {
httppost.setEntity(new UrlEncodedFormEntity(data));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
return entity.getContent();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
其他回答
方法将数据作为HTTP请求发布,
public static InputStream callPostService(String Url,
List<NameValuePair> data) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(Url);
try {
httppost.setEntity(new UrlEncodedFormEntity(data));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
return entity.getContent();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
注(2020年10月):以下答案中使用的AsyncTask已在Android API级别30中弃用。有关更新的示例,请参考官方文档或本博客文章
更新(2017年6月)答案,适用于Android 6.0+。感谢@Rohit Suthar, @Tamis Bolvari和@sudhiskr的评论。
public class CallAPI extends AsyncTask<String, String, String> {
public CallAPI(){
//set context variables if required
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected String doInBackground(String... params) {
String urlString = params[0]; // URL to call
String data = params[1]; //data to post
OutputStream out = null;
try {
URL url = new URL(urlString);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
out = new BufferedOutputStream(urlConnection.getOutputStream());
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
writer.write(data);
writer.flush();
writer.close();
out.close();
urlConnection.connect();
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
}
引用:
https://developer.android.com/reference/java/net/HttpURLConnection.html 如何使用NameValuePair使用POST添加参数到HttpURLConnection
原答案(2010年5月)
注意:此解决方案已过时。它只能在5.1版本以下的安卓设备上运行。Android 6.0及以上版本不包括本回答中使用的Apache http客户端。
来自Apache Commons的Http Client是可行的。它已经包含在android中。下面是一个简单的例子,说明如何使用它来执行HTTP Post。
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "Hi"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
最好使用Apache Commons HttpClient,它已经包含在android中了。 看一看 Android开发人员:Apache HTTP客户端包摘要 一般API信息。
@primpop的答案,我会添加如何转换字符串中的响应:
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream instream = entity.getContent();
String result = RestClient.convertStreamToString(instream);
Log.i("Read from server", result);
}
下面是一个convertStramToString的例子。
您可以使用WebServer类POST一个HttpRequest,并在其侦听器接口中跟踪响应。
WebServer server=new WebServer(getApplicationContext());
server.setOnServerStatusListner(new WebServer.OnServerStatusListner() {
@Override
public void onServerResponded(String responce) {
}
@Override
public void onServerRevoked() {
}
});
现在创建一个DataRack来绑定数据
List<DataRack> racks=new ArrayList<DataRack>();
racks.add(new DataRack("name","Simon"));
racks.add(new DataRack("age","40"));
racks.add(new DataRack("location","Canada"));
现在只需发送带有该机架的POST请求
server.connectWithPOST(MainActivity.this,"http://sangeethnandakumar.esy.es/PROJECTS/PUBLIC_SERVICE/posttest.php",racks);
你需要包括我的库。文件在这里