不能在运行时向实例添加新的属性()，因为属性是数据描述符。相反，你必须动态地创建一个新类，或者重载__getattribute__以处理实例上的数据描述符。

动态附加属性的唯一方法是用新属性创建一个新类及其实例。

class Holder: p = property(lambda x: vs[i], self.fn_readonly)
setattr(self, k, Holder().p)

class atdict(dict):
  def __init__(self, value, **kwargs):
    super().__init__(**kwargs)
    self.__dict = value

  def __getattr__(self, name):
    for key in self.__dict:
      if type(self.__dict[key]) is list:
        for idx, item in enumerate(self.__dict[key]):
          if type(item) is dict:
            self.__dict[key][idx] = atdict(item)
      if type(self.__dict[key]) is dict:
        self.__dict[key] = atdict(self.__dict[key])
    return self.__dict[name]



d1 = atdict({'a' : {'b': [{'c': 1}, 2]}})

print(d1.a.b[0].c)

输出为:

>> 1

这和OP想要的有点不同，但我绞尽脑汁，直到我得到了一个可行的解决方案，所以我把它放在这里给下一个男人/女孩

我需要一种方法来指定动态setter和getter。

class X:
    def __init__(self, a=0, b=0, c=0):
        self.a = a
        self.b = b
        self.c = c

    @classmethod
    def _make_properties(cls, field_name, inc):
        _inc = inc

        def _get_properties(self):
            if not hasattr(self, '_%s_inc' % field_name):
                setattr(self, '_%s_inc' % field_name, _inc)
                inc = _inc
            else:
                inc = getattr(self, '_%s_inc' % field_name)

            return getattr(self, field_name) + inc

        def _set_properties(self, value):
            setattr(self, '_%s_inc' % field_name, value)

        return property(_get_properties, _set_properties)

我知道我的字段提前，所以我要创建我的属性。注意:你不能在每个实例中这样做，这些属性将存在于类中!!

for inc, field in enumerate(['a', 'b', 'c']):
    setattr(X, '%s_summed' % field, X._make_properties(field, inc))

现在让我们来测试一下。

x = X()
assert x.a == 0
assert x.b == 0
assert x.c == 0

assert x.a_summed == 0  # enumerate() set inc to 0 + 0 = 0
assert x.b_summed == 1  # enumerate() set inc to 1 + 0 = 1
assert x.c_summed == 2  # enumerate() set inc to 2 + 0 = 2

# we set the variables to something
x.a = 1
x.b = 2
x.c = 3

assert x.a_summed == 1  # enumerate() set inc to 0 + 1 = 1
assert x.b_summed == 3  # enumerate() set inc to 1 + 2 = 3
assert x.c_summed == 5  # enumerate() set inc to 2 + 3 = 5

# we're changing the inc now
x.a_summed = 1 
x.b_summed = 3 
x.c_summed = 5

assert x.a_summed == 2  # we set inc to 1 + the property was 1 = 2
assert x.b_summed == 5  # we set inc to 3 + the property was 2 = 5
assert x.c_summed == 8  # we set inc to 5 + the property was 3 = 8

会让人困惑吗?是的，很抱歉我无法举出任何有意义的现实例子。另外，这也不适合轻松的人。

目标是创建一个行为类似db结果集的模拟类。

所以你想要的是一本可以把a['b']拼成a.b的字典?

这很简单:

class atdict(dict):
    __getattr__= dict.__getitem__
    __setattr__= dict.__setitem__
    __delattr__= dict.__delitem__

对我有用的是:

class C:
    def __init__(self):
        self._x=None

    def g(self):
        return self._x

    def s(self, x):
        self._x = x

    def d(self):
        del self._x

    def s2(self,x):
        self._x=x+x

    x=property(g,s,d)


c = C()
c.x="a"
print(c.x)

C.x=property(C.g, C.s2)
C.x=C.x.deleter(C.d)
c2 = C()
c2.x="a"
print(c2.x)

输出

a
aa