你可以使用下面的代码来使用字典对象更新类属性:

class ExampleClass():
    def __init__(self, argv):
        for key, val in argv.items():
            self.__dict__[key] = val

if __name__ == '__main__':
    argv = {'intro': 'Hello World!'}
    instance = ExampleClass(argv)
    print instance.intro

下面是以编程方式创建属性对象的简单示例。

#!/usr/bin/python3

class Counter:
    def __init__(self):
        cls = self.__class__
        self._count = 0
        cls.count = self.count_ref()

    def count_get(self):
        print(f'count_get: {self._count}')
        return self._count

    def count_set(self, value):
        self._count = value
        print(f'count_set: {self._count}')

    def count_del(self):
        print(f'count_del: {self._count}')

    def count_ref(self):
        cls = self.__class__
        return property(fget=cls.count_get, fset=cls.count_set, fdel=cls.count_del)

counter = Counter()

counter.count
for i in range(5):
    counter.count = i
del counter.count

'''
output
======
count_get: 0
count_set: 0
count_set: 1
count_set: 2
count_set: 3
count_set: 4
count_del: 4
'''

最好的方法是定义__slots__。这样你的实例就不能有新的属性。

ks = ['ab', 'cd']
vs = [12, 34]

class C(dict):
    __slots__ = []
    def __init__(self, ks, vs): self.update(zip(ks, vs))
    def __getattr__(self, key): return self[key]

if __name__ == "__main__":
    c = C(ks, vs)
    print c.ab

打印12

    c.ab = 33

'C'对象没有属性'ab'

不能在运行时向实例添加新的属性()，因为属性是数据描述符。相反，你必须动态地创建一个新类，或者重载__getattribute__以处理实例上的数据描述符。

这和OP想要的有点不同，但我绞尽脑汁，直到我得到了一个可行的解决方案，所以我把它放在这里给下一个男人/女孩

我需要一种方法来指定动态setter和getter。

class X:
    def __init__(self, a=0, b=0, c=0):
        self.a = a
        self.b = b
        self.c = c

    @classmethod
    def _make_properties(cls, field_name, inc):
        _inc = inc

        def _get_properties(self):
            if not hasattr(self, '_%s_inc' % field_name):
                setattr(self, '_%s_inc' % field_name, _inc)
                inc = _inc
            else:
                inc = getattr(self, '_%s_inc' % field_name)

            return getattr(self, field_name) + inc

        def _set_properties(self, value):
            setattr(self, '_%s_inc' % field_name, value)

        return property(_get_properties, _set_properties)

我知道我的字段提前，所以我要创建我的属性。注意:你不能在每个实例中这样做，这些属性将存在于类中!!

for inc, field in enumerate(['a', 'b', 'c']):
    setattr(X, '%s_summed' % field, X._make_properties(field, inc))

现在让我们来测试一下。

x = X()
assert x.a == 0
assert x.b == 0
assert x.c == 0

assert x.a_summed == 0  # enumerate() set inc to 0 + 0 = 0
assert x.b_summed == 1  # enumerate() set inc to 1 + 0 = 1
assert x.c_summed == 2  # enumerate() set inc to 2 + 0 = 2

# we set the variables to something
x.a = 1
x.b = 2
x.c = 3

assert x.a_summed == 1  # enumerate() set inc to 0 + 1 = 1
assert x.b_summed == 3  # enumerate() set inc to 1 + 2 = 3
assert x.c_summed == 5  # enumerate() set inc to 2 + 3 = 5

# we're changing the inc now
x.a_summed = 1 
x.b_summed = 3 
x.c_summed = 5

assert x.a_summed == 2  # we set inc to 1 + the property was 1 = 2
assert x.b_summed == 5  # we set inc to 3 + the property was 2 = 5
assert x.c_summed == 8  # we set inc to 5 + the property was 3 = 8

会让人困惑吗?是的，很抱歉我无法举出任何有意义的现实例子。另外，这也不适合轻松的人。

似乎您可以更简单地使用namedtuple来解决这个问题，因为您提前知道整个字段列表。

from collections import namedtuple

Foo = namedtuple('Foo', ['bar', 'quux'])

foo = Foo(bar=13, quux=74)
print foo.bar, foo.quux

foo2 = Foo()  # error

如果你绝对需要编写自己的setter，你将不得不在类级别上进行元编程;Property()在实例上不起作用。