我正在创造自己的iPhone游戏的免费版本。我想在免费版本中添加一个按钮,引导用户进入应用商店中的付费版本。如果我使用标准链接

http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=300136119&mt=8

iPhone首先打开Safari,然后打开应用商店。我使用过其他直接打开应用程序商店的应用程序,所以我知道这是可能的。

什么好主意吗?应用商店的URL方案是什么?


当前回答

如果你有应用商店id,你最好使用它。特别是当您将来可能更改应用程序的名称时。

http://itunes.apple.com/app/id378458261

如果你没有应用商店id,你可以根据这个文档创建一个url https://developer.apple.com/library/ios/qa/qa1633/_index.html

+ (NSURL *)appStoreURL
{
    static NSURL *appStoreURL;
    static dispatch_once_t onceToken;
    dispatch_once(&onceToken, ^{
        appStoreURL = [self appStoreURLFromBundleName:[[NSBundle mainBundle] objectForInfoDictionaryKey:@"CFBundleName"]];
    });
    return appStoreURL;
}

+ (NSURL *)appStoreURLFromBundleName:(NSString *)bundleName
{
    NSURL *appStoreURL = [NSURL URLWithString:[NSString stringWithFormat:@"itms-apps://itunes.com/app/%@", [self sanitizeAppStoreResourceSpecifier:bundleName]]];
    return appStoreURL;
}

+ (NSString *)sanitizeAppStoreResourceSpecifier:(NSString *)resourceSpecifier
{
    /*
     https://developer.apple.com/library/ios/qa/qa1633/_index.html
     To create an App Store Short Link, apply the following rules to your company or app name:

     Remove all whitespace
     Convert all characters to lower-case
     Remove all copyright (©), trademark (™) and registered mark (®) symbols
     Replace ampersands ("&") with "and"
     Remove most punctuation (See Listing 2 for the set)
     Replace accented and other "decorated" characters (ü, å, etc.) with their elemental character (u, a, etc.)
     Leave all other characters as-is.
     */
    resourceSpecifier = [resourceSpecifier stringByReplacingOccurrencesOfString:@"&" withString:@"and"];
    resourceSpecifier = [[NSString alloc] initWithData:[resourceSpecifier dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES] encoding:NSASCIIStringEncoding];
    resourceSpecifier = [resourceSpecifier stringByReplacingOccurrencesOfString:@"[!¡\"#$%'()*+,-./:;<=>¿?@\\[\\]\\^_`{|}~\\s\\t\\n]" withString:@"" options:NSRegularExpressionSearch range:NSMakeRange(0, resourceSpecifier.length)];
    resourceSpecifier = [resourceSpecifier lowercaseString];
    return resourceSpecifier;
}

通过测试

- (void)testAppStoreURLFromBundleName
{
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Nuclear™"].absoluteString, @"itms-apps://itunes.com/app/nuclear", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Magazine+"].absoluteString, @"itms-apps://itunes.com/app/magazine", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Karl & CO"].absoluteString, @"itms-apps://itunes.com/app/karlandco", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"[Fluppy fuck]"].absoluteString, @"itms-apps://itunes.com/app/fluppyfuck", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Pollos Hérmanos"].absoluteString, @"itms-apps://itunes.com/app/polloshermanos", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Niños and niñas"].absoluteString, @"itms-apps://itunes.com/app/ninosandninas", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Trond, MobizMag"].absoluteString, @"itms-apps://itunes.com/app/trondmobizmag", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"!__SPECIAL-PLIZES__!"].absoluteString, @"itms-apps://itunes.com/app/specialplizes", nil);
}

其他回答

我可以确认,如果你在iTunes connect上创建应用,你会在提交应用之前获得应用id。

因此. .

itms-apps://itunes.apple.com/app/id123456789

NSURL *appStoreURL = [NSURL URLWithString:@"itms-apps://itunes.apple.com/app/id123456789"];
    if ([[UIApplication sharedApplication]canOpenURL:appStoreURL])
        [[UIApplication sharedApplication]openURL:appStoreURL];

工作是一种享受

我认为苹果已经为应用程序链接提供了一个新的链接: https://apps.apple.com/app/id1445530088或https://apps.apple.com/app/ {your_app_id}

直接链接:没有重定向而有直接链接:

使用苹果服务营销工具:https://tools.applemediaservices.com/获得真正的直接链接 将https://替换为itms-apps:// 用UIApplication.shared打开链接。打开(url,选项:[:])

注意,这些链接只在实际设备上工作,而不是在模拟器中。

来源:

评论:新的链接归功于@rwcorbett 苹果文档:https://developer.apple.com/library/ios/#qa/qa2008/qa1629.html

这对我来说非常有效,只使用APP ID:

 NSString *urlString = [NSString stringWithFormat:@"http://itunes.apple.com/app/id%@",YOUR_APP_ID];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];

重定向的数量为0。

试试这个方法

http://itunes.apple.com/lookup?id=“你的应用ID在这里”返回json。从这里,找到键“trackViewUrl”和值是所需的url。使用这个url(只需将https://替换为itms-apps://)。这工作得很好。

例如,如果你的应用ID是xyz,那么就转到这个链接 http://itunes.apple.com/lookup?id=xyz

然后找到“trackViewUrl”键的url。这是你的应用程序在应用商店的url,在xcode中使用这个url试试这个

NSString *iTunesLink = @"itms-apps://itunes.apple.com/us/app/Your app name/id Your app ID?mt=8&uo=4";
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:iTunesLink]];

谢谢