我正在创造自己的iPhone游戏的免费版本。我想在免费版本中添加一个按钮,引导用户进入应用商店中的付费版本。如果我使用标准链接

http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=300136119&mt=8

iPhone首先打开Safari,然后打开应用商店。我使用过其他直接打开应用程序商店的应用程序,所以我知道这是可能的。

什么好主意吗?应用商店的URL方案是什么?


当前回答

如果你有应用商店id,你最好使用它。特别是当您将来可能更改应用程序的名称时。

http://itunes.apple.com/app/id378458261

如果你没有应用商店id,你可以根据这个文档创建一个url https://developer.apple.com/library/ios/qa/qa1633/_index.html

+ (NSURL *)appStoreURL
{
    static NSURL *appStoreURL;
    static dispatch_once_t onceToken;
    dispatch_once(&onceToken, ^{
        appStoreURL = [self appStoreURLFromBundleName:[[NSBundle mainBundle] objectForInfoDictionaryKey:@"CFBundleName"]];
    });
    return appStoreURL;
}

+ (NSURL *)appStoreURLFromBundleName:(NSString *)bundleName
{
    NSURL *appStoreURL = [NSURL URLWithString:[NSString stringWithFormat:@"itms-apps://itunes.com/app/%@", [self sanitizeAppStoreResourceSpecifier:bundleName]]];
    return appStoreURL;
}

+ (NSString *)sanitizeAppStoreResourceSpecifier:(NSString *)resourceSpecifier
{
    /*
     https://developer.apple.com/library/ios/qa/qa1633/_index.html
     To create an App Store Short Link, apply the following rules to your company or app name:

     Remove all whitespace
     Convert all characters to lower-case
     Remove all copyright (©), trademark (™) and registered mark (®) symbols
     Replace ampersands ("&") with "and"
     Remove most punctuation (See Listing 2 for the set)
     Replace accented and other "decorated" characters (ü, å, etc.) with their elemental character (u, a, etc.)
     Leave all other characters as-is.
     */
    resourceSpecifier = [resourceSpecifier stringByReplacingOccurrencesOfString:@"&" withString:@"and"];
    resourceSpecifier = [[NSString alloc] initWithData:[resourceSpecifier dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES] encoding:NSASCIIStringEncoding];
    resourceSpecifier = [resourceSpecifier stringByReplacingOccurrencesOfString:@"[!¡\"#$%'()*+,-./:;<=>¿?@\\[\\]\\^_`{|}~\\s\\t\\n]" withString:@"" options:NSRegularExpressionSearch range:NSMakeRange(0, resourceSpecifier.length)];
    resourceSpecifier = [resourceSpecifier lowercaseString];
    return resourceSpecifier;
}

通过测试

- (void)testAppStoreURLFromBundleName
{
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Nuclear™"].absoluteString, @"itms-apps://itunes.com/app/nuclear", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Magazine+"].absoluteString, @"itms-apps://itunes.com/app/magazine", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Karl & CO"].absoluteString, @"itms-apps://itunes.com/app/karlandco", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"[Fluppy fuck]"].absoluteString, @"itms-apps://itunes.com/app/fluppyfuck", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Pollos Hérmanos"].absoluteString, @"itms-apps://itunes.com/app/polloshermanos", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Niños and niñas"].absoluteString, @"itms-apps://itunes.com/app/ninosandninas", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Trond, MobizMag"].absoluteString, @"itms-apps://itunes.com/app/trondmobizmag", nil);
    STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"!__SPECIAL-PLIZES__!"].absoluteString, @"itms-apps://itunes.com/app/specialplizes", nil);
}

其他回答

对于Xcode 9.1和Swift 4:

进口StoreKit:

进口StoreKit

2.遵守协议

SKStoreProductViewControllerDelegate

3.实现协议

func openStoreProductWithiTunesItemIdentifier(identifier: String) {
    let storeViewController = SKStoreProductViewController()
    storeViewController.delegate = self

    let parameters = [ SKStoreProductParameterITunesItemIdentifier : identifier]
    storeViewController.loadProduct(withParameters: parameters) { [weak self] (loaded, error) -> Void in

        if loaded {
            // Parent class of self is UIViewContorller
            self?.present(storeViewController, animated: true, completion: nil)
        }
    }   
}

3.1

func productViewControllerDidFinish(_ viewController: SKStoreProductViewController) {
    viewController.dismiss(animated: true, completion: nil)
}

使用方法:

openStoreProductWithiTunesItemIdentifier(标识符:“here_put_your_App_id”)

注意:

输入你的APP的确切ID是非常重要的。因为这会导致错误(不显示错误日志,但没有任何工作正常,因为这个)

只需在应用程序链接中将“itunes”改为“phobos”即可。

http://phobos.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=300136119&mt=8

现在它会直接打开应用商店

它会直接打开应用商店

NSString *iTunesLink = @"itms-apps://itunes.apple.com/app/ebl- 
skybanking/id1171655193?mt=8";

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:iTunesLink]];

我认为苹果已经为应用程序链接提供了一个新的链接: https://apps.apple.com/app/id1445530088或https://apps.apple.com/app/ {your_app_id}

这里的大多数解决方案都过时了

为那些寻找更新的工作解决方案

// let appStoreLink = "https://apps.apple.com/app/{app-name}/{app-id}"

guard let url = URL(string: Constants.App.appStoreLink) else { return }
UIApplication.shared.open(url)