我正在创造自己的iPhone游戏的免费版本。我想在免费版本中添加一个按钮,引导用户进入应用商店中的付费版本。如果我使用标准链接
http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=300136119&mt=8
iPhone首先打开Safari,然后打开应用商店。我使用过其他直接打开应用程序商店的应用程序,所以我知道这是可能的。
什么好主意吗?应用商店的URL方案是什么?
我正在创造自己的iPhone游戏的免费版本。我想在免费版本中添加一个按钮,引导用户进入应用商店中的付费版本。如果我使用标准链接
http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=300136119&mt=8
iPhone首先打开Safari,然后打开应用商店。我使用过其他直接打开应用程序商店的应用程序,所以我知道这是可能的。
什么好主意吗?应用商店的URL方案是什么?
当前回答
尽管这里有很多答案,但没有一个链接到开发者应用程序的建议似乎已经不管用了。
当我上次访问时,我能够使用以下格式让它工作:
itms-apps://itunes.apple.com/developer/developer-name/id123456789
这不再有效,但删除开发人员名称可以:
itms-apps://itunes.apple.com/developer/id123456789
其他回答
如果你有应用商店id,你最好使用它。特别是当您将来可能更改应用程序的名称时。
http://itunes.apple.com/app/id378458261
如果你没有应用商店id,你可以根据这个文档创建一个url https://developer.apple.com/library/ios/qa/qa1633/_index.html
+ (NSURL *)appStoreURL
{
static NSURL *appStoreURL;
static dispatch_once_t onceToken;
dispatch_once(&onceToken, ^{
appStoreURL = [self appStoreURLFromBundleName:[[NSBundle mainBundle] objectForInfoDictionaryKey:@"CFBundleName"]];
});
return appStoreURL;
}
+ (NSURL *)appStoreURLFromBundleName:(NSString *)bundleName
{
NSURL *appStoreURL = [NSURL URLWithString:[NSString stringWithFormat:@"itms-apps://itunes.com/app/%@", [self sanitizeAppStoreResourceSpecifier:bundleName]]];
return appStoreURL;
}
+ (NSString *)sanitizeAppStoreResourceSpecifier:(NSString *)resourceSpecifier
{
/*
https://developer.apple.com/library/ios/qa/qa1633/_index.html
To create an App Store Short Link, apply the following rules to your company or app name:
Remove all whitespace
Convert all characters to lower-case
Remove all copyright (©), trademark (™) and registered mark (®) symbols
Replace ampersands ("&") with "and"
Remove most punctuation (See Listing 2 for the set)
Replace accented and other "decorated" characters (ü, å, etc.) with their elemental character (u, a, etc.)
Leave all other characters as-is.
*/
resourceSpecifier = [resourceSpecifier stringByReplacingOccurrencesOfString:@"&" withString:@"and"];
resourceSpecifier = [[NSString alloc] initWithData:[resourceSpecifier dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES] encoding:NSASCIIStringEncoding];
resourceSpecifier = [resourceSpecifier stringByReplacingOccurrencesOfString:@"[!¡\"#$%'()*+,-./:;<=>¿?@\\[\\]\\^_`{|}~\\s\\t\\n]" withString:@"" options:NSRegularExpressionSearch range:NSMakeRange(0, resourceSpecifier.length)];
resourceSpecifier = [resourceSpecifier lowercaseString];
return resourceSpecifier;
}
通过测试
- (void)testAppStoreURLFromBundleName
{
STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Nuclear™"].absoluteString, @"itms-apps://itunes.com/app/nuclear", nil);
STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Magazine+"].absoluteString, @"itms-apps://itunes.com/app/magazine", nil);
STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Karl & CO"].absoluteString, @"itms-apps://itunes.com/app/karlandco", nil);
STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"[Fluppy fuck]"].absoluteString, @"itms-apps://itunes.com/app/fluppyfuck", nil);
STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Pollos Hérmanos"].absoluteString, @"itms-apps://itunes.com/app/polloshermanos", nil);
STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Niños and niñas"].absoluteString, @"itms-apps://itunes.com/app/ninosandninas", nil);
STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"Trond, MobizMag"].absoluteString, @"itms-apps://itunes.com/app/trondmobizmag", nil);
STAssertEqualObjects([AGApplicationHelper appStoreURLFromBundleName:@"!__SPECIAL-PLIZES__!"].absoluteString, @"itms-apps://itunes.com/app/specialplizes", nil);
}
如果你想链接到开发商的应用,而开发商的名字中有标点符号或空格(例如Development Company, LLC),你的URL是这样的:
itms-apps://itunes.com/apps/DevelopmentCompanyLLC
否则它在iOS 4.3.3上返回“此请求不能被处理”
至少iOS 9及以上版本
直接在App Store打开
一个应用程序
itms-apps://itunes.apple.com/app/[appName]/[appID]
开发者的应用程序列表
itms-apps://itunes.apple.com/developer/[developerName]/[developerID]
直接链接:没有重定向而有直接链接:
使用苹果服务营销工具:https://tools.applemediaservices.com/获得真正的直接链接 将https://替换为itms-apps:// 用UIApplication.shared打开链接。打开(url,选项:[:])
注意,这些链接只在实际设备上工作,而不是在模拟器中。
来源:
评论:新的链接归功于@rwcorbett 苹果文档:https://developer.apple.com/library/ios/#qa/qa2008/qa1629.html
在SwiftUI - IOS 15.0
//
// Test.swift
// PharmaCodex
//
import SwiftUI
struct Test: View {
var body: some View {
VStack {
Button(action: {
guard let writeReviewURL = URL(string: "https://apps.apple.com/app/id1629135515?action=write-review") else {
fatalError("Expected a valid URL")
}
UIApplication.shared.open(writeReviewURL, options: [:], completionHandler: nil)
}) {
Text("Rate/Review")
}
}
}
}
struct Test_Previews: PreviewProvider {
static var previews: some View {
Test()
}
}