如何将整个输入流读到字节数组?
当前回答
Input Stream is ...
ByteArrayOutputStream bos = new ByteArrayOutputStream();
int next = in.read();
while (next > -1) {
bos.write(next);
next = in.read();
}
bos.flush();
byte[] result = bos.toByteArray();
bos.close();
其他回答
安全解决方案(正确关闭流):
Java 9及更新版本: 最终字节[]字节; try (inputStream) { 字节= inputStream.readAllBytes(); }
Java 8 and older: public static byte[] readAllBytes(InputStream inputStream) throws IOException { final int bufLen = 4 * 0x400; // 4KB byte[] buf = new byte[bufLen]; int readLen; IOException exception = null; try { try (ByteArrayOutputStream outputStream = new ByteArrayOutputStream()) { while ((readLen = inputStream.read(buf, 0, bufLen)) != -1) outputStream.write(buf, 0, readLen); return outputStream.toByteArray(); } } catch (IOException e) { exception = e; throw e; } finally { if (exception == null) inputStream.close(); else try { inputStream.close(); } catch (IOException e) { exception.addSuppressed(e); } } }
Kotlin(当Java 9+不可访问时): @Throws (IOException::类) fun InputStream.readAllBytes(): ByteArray { val bufLen = 4 * 0x400 // 4KB val buf = ByteArray(bufLen) var readLen: Int = 0 ByteArrayOutputStream()。使用{o -> 这一点。使用{I -> i.read(buf, 0, bufLen)。{readLen = it} != -1) o.write(buf, 0, readLen) } 返回o.toByteArray () } } 避免嵌套使用请看这里。
Scala(当Java 9+不可访问时)(By @Joan。Thx): def readAllBytes(inputStream: inputStream): Array[Byte] = Stream.continually (read)。takeWhile(_ != -1).map(_. tobyte).toArray . take (_
如果你使用ByteArrayOutputStream,你会做一个额外的拷贝。如果你在开始读取流之前知道它的长度(例如,InputStream实际上是FileInputStream,你可以在文件上调用file.length(),或者InputStream是一个zipfile条目InputStream,你可以调用zipEntry.length()),那么直接写入byte[]数组会更好——它使用一半的内存,并节省时间。
// Read the file contents into a byte[] array
byte[] buf = new byte[inputStreamLength];
int bytesRead = Math.max(0, inputStream.read(buf));
// If needed: for safety, truncate the array if the file may somehow get
// truncated during the read operation
byte[] contents = bytesRead == inputStreamLength ? buf
: Arrays.copyOf(buf, bytesRead);
注意:上面的最后一行处理的是在读取流时被截断的文件,如果你需要处理这种可能性,但是如果在读取流时文件变长了,byte[]数组中的内容将不会被延长以包括新的文件内容,数组将简单地被截断为旧的长度inputStreamLength。
你可以试试仙人掌:
byte[] array = new BytesOf(stream).bytes();
我试图编辑@numan的答案,修复了写垃圾数据,但编辑被拒绝。虽然这段简短的代码并不出色,但我看不到其他更好的答案。以下是我认为最有意义的建议:
ByteArrayOutputStream out = new ByteArrayOutputStream();
byte[] buffer = new byte[1024]; // you can configure the buffer size
int length;
while ((length = in.read(buffer)) != -1) out.write(buffer, 0, length); //copy streams
in.close(); // call this in a finally block
byte[] result = out.toByteArray();
ByteArrayOutputStream不需要关闭。为了可读性,省略了一些结构
请参阅InputStream.available()文档:
It is particularly important to realize that you must not use this method to size a container and assume that you can read the entirety of the stream without needing to resize the container. Such callers should probably write everything they read to a ByteArrayOutputStream and convert that to a byte array. Alternatively, if you're reading from a file, File.length returns the current length of the file (though assuming the file's length can't change may be incorrect, reading a file is inherently racy).
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