你可以使用without或pull from Lodash:

const _ = require('lodash');
_.without([1, 2, 3, 2], 2); // -> [1, 3]

方法1

var ary = ['three', 'seven', 'eleven'];
var index = ary.indexOf('seven'); // get index if value found otherwise -1

if (index > -1) { //if found
  ary.splice(index, 1);
}

方法2

一条衬垫

var ary = ['three', 'seven', 'eleven'];
filteredArr = ary.filter(function(v) { return v !== 'seven' })


// Or using ECMA6:
filteredArr = ary.filter(v => v !== 'seven')

当你需要移除一个在数组中多次出现的值时(例如。[1,2,2,2,4,5,6])。

function removeFrmArr(array, element) {
  return array.filter(e => e !== element);
};
var exampleArray = [1,2,3,4,5];
removeFrmArr(exampleArray, 3);
// return value like this
//[1, 2, 4, 5]

可以使用splice从数组中删除单个元素，但splice不能从数组中删除多个相似的元素。

function singleArrayRemove(array, value){
  var index = array.indexOf(value);
  if (index > -1) array.splice(index, 1);
  return array;
}
var exampleArray = [1,2,3,4,5,5];
singleArrayRemove(exampleArray, 5);
// return value like this
//[1, 2, 3, 4, 5]

最简单的解决方案是:

array—用于删除某些元素的数组valueForRemove; valueForRemove—用于删除的元素;

array.filter(arrayItem => !array.includes(valueForRemove));

更简单:

array.filter(arrayItem => arrayItem !== valueForRemove);

不漂亮，但有用:

array.filter(arrayItem => array.indexOf(arrayItem) != array.indexOf(valueForRemove))

不漂亮，但有用:

while(array.indexOf(valueForRemove) !== -1) {
  array.splice(array.indexOf(valueForRemove), 1)
}

附注:filter()方法创建一个包含所有通过所提供函数实现的测试的元素的新数组。参见https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

在全局函数中，我们不能直接传递自定义值，但有很多方法，如下所示

 var ary = ['three', 'seven', 'eleven'];
 var index = ary.indexOf(item);//item: the value which you want to remove

 //Method 1
 ary.splice(index,1);

 //Method 2
 delete ary[index]; //in this method the deleted element will be undefined

let arr = [5, 15, 25, 30, 35];
console.log(arr); //result [5, 15, 25, 30, 35]
let index = arr.indexOf(30);

if (index > -1) {
   arr.splice(index, 1);
}
console.log(arr); //result [5, 15, 25, 35]