我有以下JSON文本。我如何解析它以获得pageName, pagePic, post_id等的值?

{
  "pageInfo": {
    "pageName": "abc",
    "pagePic": "http://example.com/content.jpg"
  },
  "posts": [
    {
      "post_id": "123456789012_123456789012",
      "actor_id": "1234567890",
      "picOfPersonWhoPosted": "http://example.com/photo.jpg",
      "nameOfPersonWhoPosted": "Jane Doe",
      "message": "Sounds cool. Can't wait to see it!",
      "likesCount": "2",
      "comments": [],
      "timeOfPost": "1234567890"
    }
  ]
}

当前回答

如果你有maven项目,那么添加下面的依赖项或普通项目添加json-simple jar。

<dependency>
    <groupId>org.json</groupId>
    <artifactId>json</artifactId>
    <version>20180813</version>
</dependency>

写下面的java代码转换JSON字符串到JSON数组。

JSONArray ja = new JSONArray(String jsonString);

其他回答

{
   "pageInfo": {
         "pageName": "abc",
         "pagePic": "http://example.com/content.jpg"
    },
    "posts": [
         {
              "post_id": "123456789012_123456789012",
              "actor_id": "1234567890",
              "picOfPersonWhoPosted": "http://example.com/photo.jpg",
              "nameOfPersonWhoPosted": "Jane Doe",
              "message": "Sounds cool. Can't wait to see it!",
              "likesCount": "2",
              "comments": [],
              "timeOfPost": "1234567890"
         }
    ]
}

Java code :

JSONObject obj = new JSONObject(responsejsonobj);
String pageName = obj.getJSONObject("pageInfo").getString("pageName");

JSONArray arr = obj.getJSONArray("posts");
for (int i = 0; i < arr.length(); i++)
{
    String post_id = arr.getJSONObject(i).getString("post_id");
    ......etc
}

Quick-json解析器非常简单,灵活,快速,可定制。试一试

特点:

Compliant with JSON specification (RFC4627) High-Performance JSON parser Supports Flexible/Configurable parsing approach Configurable validation of key/value pairs of any JSON Hierarchy Easy to use # Very small footprint Raises developer friendly and easy to trace exceptions Pluggable Custom Validation support - Keys/Values can be validated by configuring custom validators as and when encountered Validating and Non-Validating parser support Support for two types of configuration (JSON/XML) for using quick-JSON validating parser Requires JDK 1.5 No dependency on external libraries Support for JSON Generation through object serialisation Support for collection type selection during parsing process

它可以这样使用:

JsonParserFactory factory=JsonParserFactory.getInstance();
JSONParser parser=factory.newJsonParser();
Map jsonMap=parser.parseJson(jsonString);

我相信最好的做法应该是通过仍在开发中的官方Java JSON API。

If one wants to create Java object from JSON and vice versa, use GSON or JACKSON third party jars etc. //from object to JSON Gson gson = new Gson(); gson.toJson(yourObject); // from JSON to object yourObject o = gson.fromJson(JSONString,yourObject.class); But if one just want to parse a JSON string and get some values, (OR create a JSON string from scratch to send over wire) just use JaveEE jar which contains JsonReader, JsonArray, JsonObject etc. You may want to download the implementation of that spec like javax.json. With these two jars I am able to parse the json and use the values. These APIs actually follow the DOM/SAX parsing model of XML. Response response = request.get(); // REST call JsonReader jsonReader = Json.createReader(new StringReader(response.readEntity(String.class))); JsonArray jsonArray = jsonReader.readArray(); ListIterator l = jsonArray.listIterator(); while ( l.hasNext() ) { JsonObject j = (JsonObject)l.next(); JsonObject ciAttr = j.getJsonObject("ciAttributes");

你可以用谷歌Gson。

使用这个库,您只需要创建一个具有相同JSON结构的模型。然后自动填充模型。你必须调用你的变量作为你的JSON键,或者使用@SerializedName如果你想使用不同的名字。

JSON

从你的例子中:

{
    "pageInfo": {
        "pageName": "abc",
        "pagePic": "http://example.com/content.jpg"
    }
    "posts": [
        {
            "post_id": "123456789012_123456789012",
            "actor_id": "1234567890",
            "picOfPersonWhoPosted": "http://example.com/photo.jpg",
            "nameOfPersonWhoPosted": "Jane Doe",
            "message": "Sounds cool. Can't wait to see it!",
            "likesCount": "2",
            "comments": [],
            "timeOfPost": "1234567890"
        }
    ]
}

模型

class MyModel {

    private PageInfo pageInfo;
    private ArrayList<Post> posts = new ArrayList<>();
}

class PageInfo {

    private String pageName;
    private String pagePic;
}

class Post {

    private String post_id;

    @SerializedName("actor_id") // <- example SerializedName
    private String actorId;

    private String picOfPersonWhoPosted;
    private String nameOfPersonWhoPosted;
    private String message;
    private String likesCount;
    private ArrayList<String> comments;
    private String timeOfPost;
}

解析

现在你可以使用Gson库进行解析:

MyModel model = gson.fromJson(jsonString, MyModel.class);

Gradle进口

记得在应用的Gradle文件中导入这个库

implementation 'com.google.code.gson:gson:2.8.6' // or earlier versions

自动生成模型

您可以使用这样的在线工具从JSON自动生成模型。