在解析字符串之前,如何检查它是否是一个数字?
当前回答
正则表达式匹配
这里是另一个例子升级了“CraigTP”正则表达式匹配更多的验证。
public static boolean isNumeric(String str)
{
return str.matches("^(?:(?:\\-{1})?\\d+(?:\\.{1}\\d+)?)$");
}
只有一个负号——允许且必须在开头。 负号后面必须有数字。 只有一个小数符号。允许的。 小数点后必须有数字。
正则表达式测试
1 -- **VALID**
1. -- INVALID
1.. -- INVALID
1.1 -- **VALID**
1.1.1 -- INVALID
-1 -- **VALID**
--1 -- INVALID
-1. -- INVALID
-1.1 -- **VALID**
-1.1.1 -- INVALID
其他回答
异常开销很大,但在这种情况下,RegEx需要更长的时间。下面的代码显示了两个函数的简单测试——一个使用异常,一个使用正则表达式。在我的机器上,RegEx版本比异常慢10倍。
import java.util.Date;
public class IsNumeric {
public static boolean isNumericOne(String s) {
return s.matches("-?\\d+(\\.\\d+)?"); //match a number with optional '-' and decimal.
}
public static boolean isNumericTwo(String s) {
try {
Double.parseDouble(s);
return true;
} catch (Exception e) {
return false;
}
}
public static void main(String [] args) {
String test = "12345.F";
long before = new Date().getTime();
for(int x=0;x<1000000;++x) {
//isNumericTwo(test);
isNumericOne(test);
}
long after = new Date().getTime();
System.out.println(after-before);
}
}
这是我对这个问题的回答。
一个方便的方法,你可以使用任何类型的解析器来解析任何字符串:isParsable(对象解析器,字符串str)。解析器可以是Class或对象。这也将允许你使用你写的自定义解析器,应该适用于任何场景,例如:
isParsable(Integer.class, "11");
isParsable(Double.class, "11.11");
Object dateFormater = new java.text.SimpleDateFormat("yyyy.MM.dd G 'at' HH:mm:ss z");
isParsable(dateFormater, "2001.07.04 AD at 12:08:56 PDT");
下面是我的代码和方法描述。
import java.lang.reflect.*;
/**
* METHOD: isParsable<p><p>
*
* This method will look through the methods of the specified <code>from</code> parameter
* looking for a public method name starting with "parse" which has only one String
* parameter.<p>
*
* The <code>parser</code> parameter can be a class or an instantiated object, eg:
* <code>Integer.class</code> or <code>new Integer(1)</code>. If you use a
* <code>Class</code> type then only static methods are considered.<p>
*
* When looping through potential methods, it first looks at the <code>Class</code> associated
* with the <code>parser</code> parameter, then looks through the methods of the parent's class
* followed by subsequent ancestors, using the first method that matches the criteria specified
* above.<p>
*
* This method will hide any normal parse exceptions, but throws any exceptions due to
* programmatic errors, eg: NullPointerExceptions, etc. If you specify a <code>parser</code>
* parameter which has no matching parse methods, a NoSuchMethodException will be thrown
* embedded within a RuntimeException.<p><p>
*
* Example:<br>
* <code>isParsable(Boolean.class, "true");<br>
* isParsable(Integer.class, "11");<br>
* isParsable(Double.class, "11.11");<br>
* Object dateFormater = new java.text.SimpleDateFormat("yyyy.MM.dd G 'at' HH:mm:ss z");<br>
* isParsable(dateFormater, "2001.07.04 AD at 12:08:56 PDT");<br></code>
* <p>
*
* @param parser The Class type or instantiated Object to find a parse method in.
* @param str The String you want to parse
*
* @return true if a parse method was found and completed without exception
* @throws java.lang.NoSuchMethodException If no such method is accessible
*/
public static boolean isParsable(Object parser, String str) {
Class theClass = (parser instanceof Class? (Class)parser: parser.getClass());
boolean staticOnly = (parser == theClass), foundAtLeastOne = false;
Method[] methods = theClass.getMethods();
// Loop over methods
for (int index = 0; index < methods.length; index++) {
Method method = methods[index];
// If method starts with parse, is public and has one String parameter.
// If the parser parameter was a Class, then also ensure the method is static.
if(method.getName().startsWith("parse") &&
(!staticOnly || Modifier.isStatic(method.getModifiers())) &&
Modifier.isPublic(method.getModifiers()) &&
method.getGenericParameterTypes().length == 1 &&
method.getGenericParameterTypes()[0] == String.class)
{
try {
foundAtLeastOne = true;
method.invoke(parser, str);
return true; // Successfully parsed without exception
} catch (Exception exception) {
// If invoke problem, try a different method
/*if(!(exception instanceof IllegalArgumentException) &&
!(exception instanceof IllegalAccessException) &&
!(exception instanceof InvocationTargetException))
continue; // Look for other parse methods*/
// Parse method refuses to parse, look for another different method
continue; // Look for other parse methods
}
}
}
// No more accessible parse method could be found.
if(foundAtLeastOne) return false;
else throw new RuntimeException(new NoSuchMethodException());
}
/**
* METHOD: willParse<p><p>
*
* A convienence method which calls the isParseable method, but does not throw any exceptions
* which could be thrown through programatic errors.<p>
*
* Use of {@link #isParseable(Object, String) isParseable} is recommended for use so programatic
* errors can be caught in development, unless the value of the <code>parser</code> parameter is
* unpredictable, or normal programtic exceptions should be ignored.<p>
*
* See {@link #isParseable(Object, String) isParseable} for full description of method
* usability.<p>
*
* @param parser The Class type or instantiated Object to find a parse method in.
* @param str The String you want to parse
*
* @return true if a parse method was found and completed without exception
* @see #isParseable(Object, String) for full description of method usability
*/
public static boolean willParse(Object parser, String str) {
try {
return isParsable(parser, str);
} catch(Throwable exception) {
return false;
}
}
这就是为什么我喜欢。net中的Try*方法。除了像Java一样的传统Parse方法之外,还有一个TryParse方法。我不擅长Java语法(输出参数?),所以请将以下内容视为某种伪代码。但它应该让概念变得清晰。
boolean parseInteger(String s, out int number)
{
try {
number = Integer.parseInt(myString);
return true;
} catch(NumberFormatException e) {
return false;
}
}
用法:
int num;
if (parseInteger("23", out num)) {
// Do something with num.
}
//请检查下面的代码
public static boolean isDigitsOnly(CharSequence str) {
final int len = str.length();
for (int i = 0; i < len; i++) {
if (!Character.isDigit(str.charAt(i))) {
return false;
}
}
return true;
}
您可以使用Apache Commons Lang中的NumberUtils.isCreatable()。
因为NumberUtils。isNumber将在4.0中被弃用,所以使用NumberUtils.isCreatable()代替。
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