可替代的独特价值

String.prototype.replaceAll = function(search_array, replacement_array) { // var target = this; // search_array.forEach(function(substr, index) { if (typeof replacement_array[index]!= "undefined") { target = target.replace(new RegExp(substr, 'g'), replacement_array[index] ) }); // return target; }; // Use: var replacedString = "This topic commented o

这是最常见、最可读的方法。

var str = "Test abc test test abc test test test abc test test abc"

方法1:

str = str.replace(/abc/g, "replaced text");

方法2:

str = str.split("abc").join("replaced text");

方法3:

str = str.replace(new RegExp("abc", "g"), "replaced text");

方法4:

while(str.includes("abc")){
   str = str.replace("abc", "replaced text");
}

出口:

console.log(str);
// Test replaced text test test replaced text test test test replaced text test test replaced text

重复,直到你已经取代了所有:

const regex = /^>.*/im;
while (regex.test(cadena)) {
    cadena = cadena.replace(regex, '*');
}

可以用常见的表达方式实现这一点,有几种可以帮助某人:

var word = "this,\\ .is*a*test,    '.and? / only /     'a \ test?";
var stri = "This      is    a test         and only a        test";

取代所有非阿尔法字符,

console.log(word.replace(/([^a-z])/g,' ').replace(/ +/g, ' '));
Result: [this is a test and only a test]

用一个空间替换多个连续空间,

console.log(stri.replace(/  +/g,' '));
Result: [This is a test and only a test]

取代所有 * 字符,

console.log(word.replace(/\*/g,''));
Result: [this,\ .isatest,    '.and? / only /     'a  test?]

取代问题标志(?)

console.log(word.replace(/\?/g,'#'));
Result: [this,\ .is*a*test,    '.and# / only /     'a  test#]

取代引用标志,

console.log(word.replace(/'/g,'#'));
Result: [this,\ .is*a*test,    #.and? / only /     #a  test?]

要取代所有“字符”,

console.log(word.replace(/,/g,''));
Result: [this\ .is*a*test    '.and? / only /     'a  test?]

替换一个特定的词,

console.log(word.replace(/test/g,''));
Result: [this,\ .is*a*,    '.and? / only /     'a  ?]

取代Backslash。

console.log(word.replace(/\\/g,''));
Result: [this, .is*a*test,    '.and? / only /     'a  test?]

以替代前滑,

console.log(word.replace(/\//g,''));
Result: [this,\ .is*a*test,    '.and?  only      'a  test?]

替换所有空间,

console.log(word.replace(/ /g,'#'));
Result: [this,\#.is*a*test,####'.and?#/#only#/#####'a##test?]

替换点,

console.log(word.replace(/\./g,'#'));
Result: [this,\ #is*a*test,    '#and? / only /     'a  test?]

'a cat is not a caterpillar'.replace(/\bcat\b/gi,'dog');
//"a dog is not a caterpillar"

這是一個簡單的雷格斯,避免在大多數情況下取代字的部分. 然而,一個<unk> - 仍然被認為是字的邊界. 所以條件可以用在這種情況下,以避免取代線,如冷貓:

'a cat is not a cool-cat'.replace(/\bcat\b/gi,'dog');//wrong
//"a dog is not a cool-dog" -- nips
'a cat is not a cool-cat'.replace(/(?:\b([^-]))cat(?:\b([^-]))/gi,'$1dog$2');
//"a dog is not a cool-cat"

Regexp 不是唯一的替代多种现象的方法,远离它,思考灵活,思考分裂!

var newText = "the cat looks like a cat".split('cat').join('dog');

否则,要防止替代词部分 - 批准的答案也会做什么! 你可以通过常规的表达方式来围绕这个问题,我承认,有点复杂,并且作为一个惊喜,一个缓慢的,也:

var regText = "the cat looks like a cat".replace(/(?:(^|[^a-z]))(([^a-z]*)(?=cat)cat)(?![a-z])/gi,"$1dog");

结果与接受的答案相同,但是,在这个行上使用 /cat/g 表达式:

var oops = 'the cat looks like a cat, not a caterpillar or coolcat'.replace(/cat/g,'dog');
//returns "the dog looks like a dog, not a dogerpillar or cooldog" ??

var caterpillar = 'the cat looks like a cat, not a caterpillar or coolcat'.replace(/(?:(^|[^a-z]))(([^a-z]*)(?=cat)cat)(?![a-z])/gi,"$1dog");
//return "the dog looks like a dog, not a caterpillar or coolcat"

RegExp(常规表达式)对象 Regular-Expressions.info

在这种情况下,它显著简化表达,并提供更多的灵活性,如用正确的资本化替换或在一个行中替换两只猫和猫:

'Two cats are not 1 Cat! They\'re just cool-cats, you caterpillar'
   .replace(/(^|.\b)(cat)(s?\b.|$)/gi,function(all,char1,cat,char2)
    {
       // Check 1st, capitalize if required
       var replacement = (cat.charAt(0) === 'C' ? 'D' : 'd') + 'og';
       if (char1 === ' ' && char2 === 's')
       { // Replace plurals, too
           cat = replacement + 's';
       }
       else
       { // Do not replace if dashes are matched
           cat = char1 === '-' || char2 === '-' ? cat : replacement;
       }
       return char1 + cat + char2;//return replacement string
    });
//returns:
//Two dogs are not 1 Dog! They're just cool-cats, you caterpillar

2019年11月,新功能被添加到JavaScript, string.prototype.replaceAll()。

目前它仅支持巴比伦,但也许在未来它可以在所有浏览器中实施。