根據一條線:
s = "Test abc test test abc test test test abc test test abc";
这似乎只是在上面的行中删除ABC的第一次出现:
s = s.replace('abc', '');
如何替代所有事件?
根據一條線:
s = "Test abc test test abc test test test abc test test abc";
这似乎只是在上面的行中删除ABC的第一次出现:
s = s.replace('abc', '');
如何替代所有事件?
当前回答
从 v85 开始,Chrome 现在支持 String.prototype.replaceAll 原始。 请注意,这一点超越了所有其他提议的解决方案,并且应该使用一次主要支持。
功能状态: https://chromestatus.com/feature/6040389083463680
var s = “Hello hello world”; s = s.replaceAll(“Hello”,“”); // s 现在是“世界” console.log(s)
其他回答
下面是工作代码与原型:
String.prototype.replaceAll = function(find, replace) {
var str = this;
return str.replace(new RegExp(find.replace(/([.*+?^=!:${}()|\[\]\/\\])/g, "\\$1"), 'g'), replace);
};
这个解决方案结合了一些以前的答案,并更好地符合建议的2020年8月标准解决方案,这个解决方案在2020年9月对我来说仍然可行,因为String.replaceAll不在我使用的Node.js二进制中。
RegExp.escape 是一个单独的问题处理,但它在这里很重要,因为官方提出的解决方案将自动逃脱基于链条的查找输入。
如果你需要准确的标准符合,对于一个应用程序,它是严格依赖于标准实施,那么我建议使用Babel或其他工具,你得到“正确的答案”每次而不是Stack Overflow。
代码:
if (!Object.prototype.hasOwnProperty.call(RegExp, 'escape')) {
RegExp.escape = function(string) {
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Regular_Expressions#Escaping
// https://github.com/benjamingr/RegExp.escape/issues/37
return string.replace(/[.*+\-?^${}()|[\]\\]/g, '\\$&'); // $& means the whole matched string
};
}
if (!Object.prototype.hasOwnProperty.call(String, 'replaceAll')) {
String.prototype.replaceAll = function(find, replace) {
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replaceAll
// If you pass a RegExp to 'find', you _MUST_ include 'g' as a flag.
// TypeError: "replaceAll must be called with a global RegExp" not included, will silently cause significant errors. _MUST_ include 'g' as a flag for RegExp.
// String parameters to 'find' do not require special handling.
// Does not conform to "special replacement patterns" when "Specifying a string as a parameter" for replace
// Does not conform to "Specifying a function as a parameter" for replace
return this.replace(
Object.prototype.toString.call(find) == '[object RegExp]' ?
find :
new RegExp(RegExp.escape(find), 'g'),
replace
);
}
}
编码,小型:
Object.prototype.hasOwnProperty.call(RegExp,"escape")||(RegExp.escape=function(e){return e.replace(/[.*+\-?^${}()|[\]\\]/g,"\\$&")}),Object.prototype.hasOwnProperty.call(String,"replaceAll")||(String.prototype.replaceAll=function(e,t){return this.replace("[object RegExp]"==Object.prototype.toString.call(e)?e:new RegExp(RegExp.escape(e),"g"),t)});
例子:
console.log(
't*.STVAL'
.replaceAll(
new RegExp(RegExp.escape('T*.ST'), 'ig'),
'TEST'
)
);
console.log(
't*.STVAL'
.replaceAll(
't*.ST',
'TEST'
);
);
没有 RegExp.Escape 的代码:
if (!Object.prototype.hasOwnProperty.call(String, 'replaceAll')) {
String.prototype.replaceAll = function(find, replace) {
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replaceAll
// If you pass a RegExp to 'find', you _MUST_ include 'g' as a flag.
// TypeError: "replaceAll must be called with a global RegExp" not included, will silently cause significant errors. _MUST_ include 'g' as a flag for RegExp.
// String parameters to 'find' do not require special handling.
// Does not conform to "special replacement patterns" when "Specifying a string as a parameter" for replace
// Does not conform to "Specifying a function as a parameter" for replace
return this.replace(
Object.prototype.toString.call(find) == '[object RegExp]' ?
find :
new RegExp(find.replace(/[.*+\-?^${}()|[\]\\]/g, '\\$&'), 'g'),
replace
);
}
}
代码没有 RegExp.Escape,小型:
Object.prototype.hasOwnProperty.call(String,"replaceAll")||(String.prototype.replaceAll=function(e,t){return this.replace("[object RegExp]"==Object.prototype.toString.call(e)?e:new RegExp(e.replace(/[.*+\-?^${}()|[\]\\]/g,"\\$&"),"g"),t)});
方法1
尝试执行一个常见的表达式:
“测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试
方法2
与ABC分开并加入空空间。
“测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试ABC测试
// Try this way
const str = "Test abc test test abc test test test abc test test abc";
const result = str.split('abc').join('');
console.log(result);
您可以使用下面的方法
/**
* Replace all the occerencess of $find by $replace in $originalString
* @param {originalString} input - Raw string.
* @param {find} input - Target key word or regex that need to be replaced.
* @param {replace} input - Replacement key word
* @return {String} Output string
*/
function replaceAll(originalString, find, replace) {
return originalString.replace(new RegExp(find, 'g'), replace);
};