根據一條線:
s = "Test abc test test abc test test test abc test test abc";
这似乎只是在上面的行中删除ABC的第一次出现:
s = s.replace('abc', '');
如何替代所有事件?
根據一條線:
s = "Test abc test test abc test test test abc test test abc";
这似乎只是在上面的行中删除ABC的第一次出现:
s = s.replace('abc', '');
如何替代所有事件?
当前回答
str = "Test abc test test abc test test test abc test test abc"
str.split(' ').join().replace(/abc/g,'').replace(/,/g, ' ')
其他回答
重复,直到你已经取代了所有:
const regex = /^>.*/im;
while (regex.test(cadena)) {
cadena = cadena.replace(regex, '*');
}
function replaceAll(str, find, replace) {
var $r="";
while($r!=str){
$r = str;
str = str.replace(find, replace);
}
return str;
}
'a cat is not a caterpillar'.replace(/\bcat\b/gi,'dog');
//"a dog is not a caterpillar"
這是一個簡單的雷格斯,避免在大多數情況下取代字的部分. 然而,一個<unk> - 仍然被認為是字的邊界. 所以條件可以用在這種情況下,以避免取代線,如冷貓:
'a cat is not a cool-cat'.replace(/\bcat\b/gi,'dog');//wrong
//"a dog is not a cool-dog" -- nips
'a cat is not a cool-cat'.replace(/(?:\b([^-]))cat(?:\b([^-]))/gi,'$1dog$2');
//"a dog is not a cool-cat"
Regexp 不是唯一的替代多种现象的方法,远离它,思考灵活,思考分裂!
var newText = "the cat looks like a cat".split('cat').join('dog');
否则,要防止替代词部分 - 批准的答案也会做什么! 你可以通过常规的表达方式来围绕这个问题,我承认,有点复杂,并且作为一个惊喜,一个缓慢的,也:
var regText = "the cat looks like a cat".replace(/(?:(^|[^a-z]))(([^a-z]*)(?=cat)cat)(?![a-z])/gi,"$1dog");
结果与接受的答案相同,但是,在这个行上使用 /cat/g 表达式:
var oops = 'the cat looks like a cat, not a caterpillar or coolcat'.replace(/cat/g,'dog');
//returns "the dog looks like a dog, not a dogerpillar or cooldog" ??
var caterpillar = 'the cat looks like a cat, not a caterpillar or coolcat'.replace(/(?:(^|[^a-z]))(([^a-z]*)(?=cat)cat)(?![a-z])/gi,"$1dog");
//return "the dog looks like a dog, not a caterpillar or coolcat"
RegExp(常规表达式)对象 Regular-Expressions.info
在这种情况下,它显著简化表达,并提供更多的灵活性,如用正确的资本化替换或在一个行中替换两只猫和猫:
'Two cats are not 1 Cat! They\'re just cool-cats, you caterpillar'
.replace(/(^|.\b)(cat)(s?\b.|$)/gi,function(all,char1,cat,char2)
{
// Check 1st, capitalize if required
var replacement = (cat.charAt(0) === 'C' ? 'D' : 'd') + 'og';
if (char1 === ' ' && char2 === 's')
{ // Replace plurals, too
cat = replacement + 's';
}
else
{ // Do not replace if dashes are matched
cat = char1 === '-' || char2 === '-' ? cat : replacement;
}
return char1 + cat + char2;//return replacement string
});
//returns:
//Two dogs are not 1 Dog! They're just cool-cats, you caterpillar
试试这:
String.prototype.replaceAll = function (sfind, sreplace) {
var str = this;
while (str.indexOf(sfind) > -1) {
str = str.replace(sfind, sreplace);
}
return str;
};
虽然人们已经提到使用regex,如果你想取代文本的情况下,有一个更好的方法。
// Consider the below example
originalString.replace(/stringToBeReplaced/gi, '');
// The output will be all the occurrences removed irrespective of casing.
你可以在这里提到详细的例子。