我有一根绳子。

string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";

我需要在字符串中每次出现“@”符号后添加换行符。

我的输出应该像这样

fkdfdsfdflkdkfk@
dfsdfjk72388389@
kdkfkdfkkl@
jkdjkfjd@
jjjk@

当前回答

protected void Button1_Click(object sender, EventArgs e)
{
    string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
    str = str.Replace("@", "@" + "<br/>");
    Response.Write(str);       
}

其他回答

然后将之前的答案修改为:

Console.Write(strToProcess.Replace("@", "@" + Environment.NewLine));

如果您不希望文本文件中出现换行符,那么就不要保存它。

前面的答案很接近,但为了满足@符号保持接近的实际要求,您希望它是str.Replace("@", "@" + System.Environment.NewLine)。这将保留@符号,并为当前平台添加适当的换行符。

string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
var result = strToProcess.Replace("@", "@ \r\n");
Console.WriteLine(result);

输出

更改您的字符串如下所述。

string strToProcess = "fkdfdsfdflkdkfk"+ System.Environment.NewLine +" dfsdfjk72388389"+ System.Environment.NewLine +"kdkfkdfkkl"+ System.Environment.NewLine +"jkdjkfjd"+ System.Environment.NewLine +"jjjk"+ System.Environment.NewLine;

根据你对其他人的回复,这就是你想要的。

string file = @"C:\file.txt";
string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
string[] lines = strToProcess.Split(new char[] { '@' }, StringSplitOptions.RemoveEmptyEntries);

using (StreamWriter writer = new StreamWriter(file))
{
    foreach (string line in lines)
    {
        writer.WriteLine(line + "@");
    }
}