更改您的字符串如下所述。

string strToProcess = "fkdfdsfdflkdkfk"+ System.Environment.NewLine +" dfsdfjk72388389"+ System.Environment.NewLine +"kdkfkdfkkl"+ System.Environment.NewLine +"jkdjkfjd"+ System.Environment.NewLine +"jjjk"+ System.Environment.NewLine;

using System;
using System.IO;
using System.Text;

class Test
{
    public static void Main()
    {
             string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
            strToProcess.Replace("@", Environment.NewLine);
            Console.WriteLine(strToProcess);
    }
}

string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
str = str.Replace("@", Environment.NewLine);
richTextBox1.Text = str;

前面的答案很接近，但为了满足@符号保持接近的实际要求，您希望它是str.Replace("@"， "@" + System.Environment.NewLine)。这将保留@符号，并为当前平台添加适当的换行符。

然后将之前的答案修改为:

Console.Write(strToProcess.Replace("@", "@" + Environment.NewLine));

如果您不希望文本文件中出现换行符，那么就不要保存它。

根据你对其他人的回复，这就是你想要的。

string file = @"C:\file.txt";
string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
string[] lines = strToProcess.Split(new char[] { '@' }, StringSplitOptions.RemoveEmptyEntries);

using (StreamWriter writer = new StreamWriter(file))
{
    foreach (string line in lines)
    {
        writer.WriteLine(line + "@");
    }
}