是否有比较版本号的标准习语?我不能直接使用String compareTo,因为我还不知道点释放的最大数量是多少。我需要比较版本,并有以下保持正确:

1.0 < 1.1
1.0.1 < 1.1
1.9 < 1.10

当前回答

由于本页上没有答案能很好地处理混合文本,我做了自己的版本:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

class Main {
    static double parseVersion(String v) {
        if (v.isEmpty()) {
            return 0;
        }
        Pattern p = Pattern.compile("^(\\D*)(\\d*)(\\D*)$");
        Matcher m = p.matcher(v);
        m.find();
        if (m.group(2).isEmpty()) {
            // v1.0.0.[preview]
            return -1;
        }
        double i = Integer.parseInt(m.group(2));
        if (!m.group(3).isEmpty()) {
            // v1.0.[0b]
            i -= 0.1;
        }
        return i;
    }

    public static int versionCompare(String str1, String str2) {
        String[] v1 = str1.split("\\.");
        String[] v2 = str2.split("\\.");
        int i = 0;
        for (; i < v1.length && i < v2.length; i++) {
            double iv1 = parseVersion(v1[i]);
            double iv2 = parseVersion(v2[i]);

            if (iv1 != iv2) {
                return iv1 - iv2 < 0 ? -1 : 1;
            }
        }
        if (i < v1.length) {
            // "1.0.1", "1.0"
            double iv1 = parseVersion(v1[i]);
            return iv1 < 0 ? -1 : (int) Math.ceil(iv1);
        }
        if (i < v2.length) {
            double iv2 = parseVersion(v2[i]);
            return -iv2 < 0 ? -1 : (int) Math.ceil(iv2);
        }
        return 0;
    }


    public static void main(String[] args) {
        System.out.println("versionCompare(v1.0.0, 1.0.0)");
        System.out.println(versionCompare("v1.0.0", "1.0.0")); // 0

        System.out.println("versionCompare(v1.0.0b, 1.0.0)");
        System.out.println(versionCompare("v1.0.0b", "1.0.0")); // -1

        System.out.println("versionCompare(v1.0.0.preview, 1.0.0)");
        System.out.println(versionCompare("v1.0.0.preview", "1.0.0")); // -1

        System.out.println("versionCompare(v1.0, 1.0.0)");
        System.out.println(versionCompare("v1.0", "1.0.0")); // 0

        System.out.println("versionCompare(ver1.0, 1.0.1)");
        System.out.println(versionCompare("ver1.0", "1.0.1")); // -1
    }
}

不过,在需要比较“alpha”和“beta”的情况下,它仍然不够。

其他回答

使用Java 9自带的Version类

import java.util.*;
import java.lang.module.ModuleDescriptor.Version;
class Main {
  public static void main(String[] args) {
    var versions = Arrays.asList(
      "1.0.2",
      "1.0.0-beta.2",
      "1.0.0",
      "1.0.0-beta",
      "1.0.0-alpha.12",
      "1.0.0-beta.11",
      "1.0.1",
      "1.0.11",
      "1.0.0-rc.1",
      "1.0.0-alpha.1",
      "1.1.0",
      "1.0.0-alpha.beta",
      "1.11.0",
      "1.0.0-alpha.12.ab-c",
      "0.0.1",
      "1.2.1",
      "1.0.0-alpha",
      "1.0.0.1",  // Also works with a number of sections different than 3
      "1.0.0.2",
      "2",
      "10",
      "1.0.0.10"
    );
    versions.stream()
      .map(Version::parse)
      .sorted()
      .forEach(System.out::println);
  }
}

在网上试试!

输出:

0.0.1
1.0.0-alpha
1.0.0-alpha.1
1.0.0-alpha.12
1.0.0-alpha.12.ab-c
1.0.0-alpha.beta
1.0.0-beta
1.0.0-beta.2
1.0.0-beta.11
1.0.0-rc.1
1.0.0
1.0.0.1
1.0.0.2
1.0.0.10
1.0.1
1.0.2
1.0.11
1.1.0
1.2.1
1.11.0
2
10

使用Java 8 Stream替换组件中的前导零。这段代码通过了interviewbit.com上的所有测试

public int compareVersion(String A, String B) {
    List<String> strList1 = Arrays.stream(A.split("\\."))
                                           .map(s -> s.replaceAll("^0+(?!$)", ""))
                                           .collect(Collectors.toList());
    List<String> strList2 = Arrays.stream(B.split("\\."))
                                           .map(s -> s.replaceAll("^0+(?!$)", ""))
                                           .collect(Collectors.toList());
    int len1 = strList1.size();
    int len2 = strList2.size();
    int i = 0;
    while(i < len1 && i < len2){
        if (strList1.get(i).length() > strList2.get(i).length()) return 1;
        if (strList1.get(i).length() < strList2.get(i).length()) return -1;
        int result = new Long(strList1.get(i)).compareTo(new Long(strList2.get(i)));
        if (result != 0) return result;
        i++;
    }
    while (i < len1){
        if (!strList1.get(i++).equals("0")) return 1;
    }
    while (i < len2){
        if (!strList2.get(i++).equals("0")) return -1;
    }
    return 0;
}
public class VersionComparator {

    /* loop through both version strings
     * then loop through the inner string to computer the val of the int
     * for each integer read, do num*10+<integer read>
     * and stop when stumbling upon '.'
     * When '.' is encountered...
     * see if '.' is encountered for both strings
     * if it is then compare num1 and num2 
     * if num1 == num2... iterate over p1++, p2++
     * else return (num1 > num2) ? 1 : -1
     * If both the string end then compare(num1, num2) return 0, 1, -1
     * else loop through the longer string and 
     * verify if it only has trailing zeros
     * If it only has trailing zeros then return 0
     * else it is greater than the other string
     */
    public static int compareVersions(String v1, String v2) {
        int num1 = 0;
        int num2 = 0;
        int p1 = 0;
        int p2 = 0;

        while (p1 < v1.length() && p2 < v2.length()) {
            num1 = Integer.parseInt(v1.charAt(p1) + "");
            num2 = Integer.parseInt(v2.charAt(p2) + "");
            p1++;
            p2++;

            while (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) != '.' && v2.charAt(p2) != '.') {
                if (p1 < v1.length()) num1 = num1 * 10 + Integer.parseInt(v1.charAt(p1) + "");
                if (p2 < v2.length()) num2 = num2 * 10 + Integer.parseInt(v2.charAt(p2) + "");
                p1++;
                p2++;
            }

            if (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) == '.' && v2.charAt(p2) == '.') {
                if ((num1 ^ num2) == 0) {
                    p1++;
                    p2++;
                }
                else return (num1 > num2) ? 1 : -1;
            }
            else if (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) == '.') return -1;
            else if (p1 < v1.length() && p2 < v2.length() && v2.charAt(p2) == '.') return 1;
        }

        if (p1 == v1.length() && p2 == v2.length()) {
            if ((num1 ^ num2) == 0) return 0;
            else return (num1 > num2) ? 1 : -1;
        }
        else if (p1 == v1.length()) {
            if ((num1 ^ num2) == 0) {
                while (p2 < v2.length()) {
                    if (v2.charAt(p2) != '.' && v2.charAt(p2) != '0') return -1;
                    p2++;
                }
                return 0;
            }
            else return (num1 > num2) ? 1 : -1;
        }
        else {
            if ((num1 ^ num2) == 0) {
                while (p1 < v1.length()) {
                    if (v1.charAt(p1) != '.' && v1.charAt(p1) != '0') return 1;
                    p1++;
                }
                return 0;
            }
            else return (num1 > num2) ? 1 : -1;
        }
    }

    public static void main(String[] args) {
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("11.21.1.0.0.1.0", "11.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.23.0.0.0.1.0") ^ -1);
        System.out.println(compareVersions("11.2", "11.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("1.21.1.0.0.1.0", "2.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("11.23.0.0.0.0.0", "11.23") ^ 0);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("1.5.1.3", "1.5.1.3.0") ^ 0);
        System.out.println(compareVersions("1.5.1.4", "1.5.1.3.0") ^ 1);
        System.out.println(compareVersions("1.2.1.3", "1.5.1.3.0") ^ -1);
        System.out.println(compareVersions("1.2.1.3", "1.22.1.3.0") ^ -1);
        System.out.println(compareVersions("1.222.1.3", "1.22.1.3.0") ^ 1);
    }
}
public static void main(String[] args) {

    String version1 = "1.0";
    String version2 = "1.0.0";
    String[] version1_splits = version1.split("\\.");
    String[] version2_splits = version2.split("\\.");
    int length = version1_splits.length >= version2_splits.length ? version1_splits.length : version2_splits.length;
    int i=0;
    for(;i<length;i++){
        int version1_int = getValue(version1_splits,i);
        int version2_int = getValue(version2_splits,i);
        if(version1_int > version2_int){
            System.out.println("version1 > version2");
            break;
        }
        else if(version1_int < version2_int){
            System.out.println("version2 > version1");
            break;
        }
        else{
            if(i == length-1)
            System.out.println("version1 = version2");
        }
    }
}

private static int getValue(String[] version1_splits, int i) {
    int temp;
    try{
        temp = Integer.valueOf(version1_splits[i]);
    }
    catch(IndexOutOfBoundsException e){
        temp=0;
    }

    return temp;
}

@alex在Kotlin上的帖子

class Version(inputVersion: String) : Comparable<Version> {

        var version: String
            private set

        override fun compareTo(other: Version) =
            (split() to other.split()).let {(thisParts, thatParts)->
                val length = max(thisParts.size, thatParts.size)
                for (i in 0 until length) {
                    val thisPart = if (i < thisParts.size) thisParts[i].toInt() else 0
                    val thatPart = if (i < thatParts.size) thatParts[i].toInt() else 0
                    if (thisPart < thatPart) return -1
                    if (thisPart > thatPart) return 1
                }
                 0
            }

        init {
            require(inputVersion.matches("[0-9]+(\\.[0-9]+)*".toRegex())) { "Invalid version format" }
            version = inputVersion
        }
    }

    fun Version.split() = version.split(".").toTypedArray()

用法:

Version("1.2.4").compareTo(Version("0.0.5")) //return 1