是否有比较版本号的标准习语?我不能直接使用String compareTo,因为我还不知道点释放的最大数量是多少。我需要比较版本,并有以下保持正确:

1.0 < 1.1
1.0.1 < 1.1
1.9 < 1.10

当前回答

public class VersionComparator {

    /* loop through both version strings
     * then loop through the inner string to computer the val of the int
     * for each integer read, do num*10+<integer read>
     * and stop when stumbling upon '.'
     * When '.' is encountered...
     * see if '.' is encountered for both strings
     * if it is then compare num1 and num2 
     * if num1 == num2... iterate over p1++, p2++
     * else return (num1 > num2) ? 1 : -1
     * If both the string end then compare(num1, num2) return 0, 1, -1
     * else loop through the longer string and 
     * verify if it only has trailing zeros
     * If it only has trailing zeros then return 0
     * else it is greater than the other string
     */
    public static int compareVersions(String v1, String v2) {
        int num1 = 0;
        int num2 = 0;
        int p1 = 0;
        int p2 = 0;

        while (p1 < v1.length() && p2 < v2.length()) {
            num1 = Integer.parseInt(v1.charAt(p1) + "");
            num2 = Integer.parseInt(v2.charAt(p2) + "");
            p1++;
            p2++;

            while (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) != '.' && v2.charAt(p2) != '.') {
                if (p1 < v1.length()) num1 = num1 * 10 + Integer.parseInt(v1.charAt(p1) + "");
                if (p2 < v2.length()) num2 = num2 * 10 + Integer.parseInt(v2.charAt(p2) + "");
                p1++;
                p2++;
            }

            if (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) == '.' && v2.charAt(p2) == '.') {
                if ((num1 ^ num2) == 0) {
                    p1++;
                    p2++;
                }
                else return (num1 > num2) ? 1 : -1;
            }
            else if (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) == '.') return -1;
            else if (p1 < v1.length() && p2 < v2.length() && v2.charAt(p2) == '.') return 1;
        }

        if (p1 == v1.length() && p2 == v2.length()) {
            if ((num1 ^ num2) == 0) return 0;
            else return (num1 > num2) ? 1 : -1;
        }
        else if (p1 == v1.length()) {
            if ((num1 ^ num2) == 0) {
                while (p2 < v2.length()) {
                    if (v2.charAt(p2) != '.' && v2.charAt(p2) != '0') return -1;
                    p2++;
                }
                return 0;
            }
            else return (num1 > num2) ? 1 : -1;
        }
        else {
            if ((num1 ^ num2) == 0) {
                while (p1 < v1.length()) {
                    if (v1.charAt(p1) != '.' && v1.charAt(p1) != '0') return 1;
                    p1++;
                }
                return 0;
            }
            else return (num1 > num2) ? 1 : -1;
        }
    }

    public static void main(String[] args) {
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("11.21.1.0.0.1.0", "11.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.23.0.0.0.1.0") ^ -1);
        System.out.println(compareVersions("11.2", "11.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("1.21.1.0.0.1.0", "2.23") ^ -1);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("11.23.0.0.0.0.0", "11.23") ^ 0);
        System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
        System.out.println(compareVersions("1.5.1.3", "1.5.1.3.0") ^ 0);
        System.out.println(compareVersions("1.5.1.4", "1.5.1.3.0") ^ 1);
        System.out.println(compareVersions("1.2.1.3", "1.5.1.3.0") ^ -1);
        System.out.println(compareVersions("1.2.1.3", "1.22.1.3.0") ^ -1);
        System.out.println(compareVersions("1.222.1.3", "1.22.1.3.0") ^ 1);
    }
}

其他回答

public static void main(String[] args) {

    String version1 = "1.0";
    String version2 = "1.0.0";
    String[] version1_splits = version1.split("\\.");
    String[] version2_splits = version2.split("\\.");
    int length = version1_splits.length >= version2_splits.length ? version1_splits.length : version2_splits.length;
    int i=0;
    for(;i<length;i++){
        int version1_int = getValue(version1_splits,i);
        int version2_int = getValue(version2_splits,i);
        if(version1_int > version2_int){
            System.out.println("version1 > version2");
            break;
        }
        else if(version1_int < version2_int){
            System.out.println("version2 > version1");
            break;
        }
        else{
            if(i == length-1)
            System.out.println("version1 = version2");
        }
    }
}

private static int getValue(String[] version1_splits, int i) {
    int temp;
    try{
        temp = Integer.valueOf(version1_splits[i]);
    }
    catch(IndexOutOfBoundsException e){
        temp=0;
    }

    return temp;
}

使用Java 9自带的Version类

import java.util.*;
import java.lang.module.ModuleDescriptor.Version;
class Main {
  public static void main(String[] args) {
    var versions = Arrays.asList(
      "1.0.2",
      "1.0.0-beta.2",
      "1.0.0",
      "1.0.0-beta",
      "1.0.0-alpha.12",
      "1.0.0-beta.11",
      "1.0.1",
      "1.0.11",
      "1.0.0-rc.1",
      "1.0.0-alpha.1",
      "1.1.0",
      "1.0.0-alpha.beta",
      "1.11.0",
      "1.0.0-alpha.12.ab-c",
      "0.0.1",
      "1.2.1",
      "1.0.0-alpha",
      "1.0.0.1",  // Also works with a number of sections different than 3
      "1.0.0.2",
      "2",
      "10",
      "1.0.0.10"
    );
    versions.stream()
      .map(Version::parse)
      .sorted()
      .forEach(System.out::println);
  }
}

在网上试试!

输出:

0.0.1
1.0.0-alpha
1.0.0-alpha.1
1.0.0-alpha.12
1.0.0-alpha.12.ab-c
1.0.0-alpha.beta
1.0.0-beta
1.0.0-beta.2
1.0.0-beta.11
1.0.0-rc.1
1.0.0
1.0.0.1
1.0.0.2
1.0.0.10
1.0.1
1.0.2
1.0.11
1.1.0
1.2.1
1.11.0
2
10

用点作为分隔符对字符串进行标记,然后从左边开始并排比较整数转换。

我喜欢@Peter Lawrey的想法,我把它扩展到更远的范围:

    /**
    * Normalize string array, 
    * Appends zeros if string from the array
    * has length smaller than the maxLen.
    **/
    private String normalize(String[] split, int maxLen){
        StringBuilder sb = new StringBuilder("");
        for(String s : split) {
            for(int i = 0; i<maxLen-s.length(); i++) sb.append('0');
            sb.append(s);
        }
        return sb.toString();
    }

    /**
    * Removes trailing zeros of the form '.00.0...00'
    * (and does not remove zeros from, say, '4.1.100')
    **/
    public String removeTrailingZeros(String s){
        int i = s.length()-1;
        int k = s.length()-1;
        while(i >= 0 && (s.charAt(i) == '.' || s.charAt(i) == '0')){
          if(s.charAt(i) == '.') k = i-1;
          i--;  
        } 
        return s.substring(0,k+1);
    }

    /**
    * Compares two versions(works for alphabets too),
    * Returns 1 if v1 > v2, returns 0 if v1 == v2,
    * and returns -1 if v1 < v2.
    **/
    public int compareVersion(String v1, String v2) {

        // Uncomment below two lines if for you, say, 4.1.0 is equal to 4.1
        // v1 = removeTrailingZeros(v1);
        // v2 = removeTrailingZeros(v2);

        String[] splitv1 = v1.split("\\.");
        String[] splitv2 = v2.split("\\.");
        int maxLen = 0;
        for(String str : splitv1) maxLen = Math.max(maxLen, str.length());
        for(String str : splitv2) maxLen = Math.max(maxLen, str.length());
        int cmp = normalize(splitv1, maxLen).compareTo(normalize(splitv2, maxLen));
        return cmp > 0 ? 1 : (cmp < 0 ? -1 : 0);
    }

希望它能帮助到别人。它通过了interviewbit和leetcode中的所有测试用例(需要取消compareVersion函数中的两行注释)。

很容易测试!

如果你的项目中已经有Jackson,你可以使用com.fasterxml.jackson.core.Version:

import com.fasterxml.jackson.core.Version;
import org.junit.Test;

import static org.junit.Assert.assertTrue;

public class VersionTest {

    @Test
    public void shouldCompareVersion() {
        Version version1 = new Version(1, 11, 1, null, null, null);
        Version version2 = new Version(1, 12, 1, null, null, null);
        assertTrue(version1.compareTo(version2) < 0);
    }
}