下面的代码给出了一个错误——“没有从DBnull到int的隐式转换”。

SqlParameter[] parameters = new SqlParameter[1];    
SqlParameter planIndexParameter = new SqlParameter("@AgeIndex", SqlDbType.Int);
planIndexParameter.Value = (AgeItem.AgeIndex== null) ? DBNull.Value : AgeItem.AgeIndex;
parameters[0] = planIndexParameter;

当前回答

我的代码,在实际项目中工作 在创建sqlparameter之前查看三元操作符 这对我来说是最好的方式,没有问题:

    public bool Key_AddExisting
    (
          string clave
        , int? idHito_FileServer
        , int? idTipoDocumental_Almacen
        , string tipoExp_CHJ
        , int idTipoExp_Verti2
        , int idMov_Verti2
    )
    {
        List<SqlParameter> pars = new List<SqlParameter>()
        {
              new SqlParameter { ParameterName = "@Clave", Value = clave }
    LOOK -> , idHito_FileServer == null ? new SqlParameter { ParameterName = "@IdHito_FileServer", Value = DBNull.Value } : new SqlParameter { ParameterName = "@IdHito_FileServer", Value = idHito_FileServer }
    LOOK -> , idTipoDocumental_Almacen == null ? new SqlParameter { ParameterName = "@IdTipoDocumental_Almacen", Value = DBNull.Value } : new SqlParameter { ParameterName = "@IdTipoDocumental_Almacen", Value = idTipoDocumental_Almacen }
            , new SqlParameter { ParameterName = "@TipoExp_CHJ", Value = tipoExp_CHJ }
            , new SqlParameter { ParameterName = "@IdTipoExp_Verti2", Value = idTipoExp_Verti2 }
            , new SqlParameter { ParameterName = "@IdMov_Verti2", Value = idMov_Verti2 }
        };

        string sql = "INSERT INTO [dbo].[Enlaces_ClavesCHJ_MovimientosVerti2] " +
            "( " +
            "  [Clave] " +
            ", [IdHito_FileServer] " +
            ", [IdTipoDocumental_Almacen] " +
            ", [TipoExp_CHJ] " +
            ", [IdTipoExp_Verti2] " +
            ", [IdMov_Verti2] " +
            ") " +
            "VALUES" +
            "( " +
            "  @Clave" +
            ", @IdHito_FileServer" +
            ", @IdTipoDocumental_Almacen" +
            ", @TipoExp_CHJ" +
            ", @IdTipoExp_Verti2" +
            ", @IdMov_Verti2" +
            ")";

        return DbBasic.ExecNonQuery(ref this.conn, sql, pars);
    }

其他回答

考虑使用可用的Nullable(T)结构。它将允许您仅在拥有值时设置值,SQL Command对象将识别可为空的值并进行相应的处理,而不会给您带来麻烦。

如果使用条件(三元)操作符,编译器需要在两种类型之间进行隐式转换,否则会出现异常。

所以你可以通过将两者之一强制转换为系统来修复它。对象:

planIndexParameter.Value = (AgeItem.AgeIndex== null) ? DBNull.Value : (object) AgeItem.AgeIndex;

但是因为结果不是很漂亮,你总是要记住这个类型转换,你可以使用这样一个扩展方法:

public static object GetDBNullOrValue<T>(this T val)
{
    bool isDbNull = true;
    Type t = typeof(T);

    if (Nullable.GetUnderlyingType(t) != null)
        isDbNull = EqualityComparer<T>.Default.Equals(default(T), val);
    else if (t.IsValueType)
        isDbNull = false;
    else
        isDbNull = val == null;

    return isDbNull ? DBNull.Value : (object) val;
}

然后你可以使用以下简洁的代码:

planIndexParameter.Value = AgeItem.AgeIndex.GetDBNullOrValue();
if (_id_categoria_padre > 0)
{
    objComando.Parameters.Add("id_categoria_padre", SqlDbType.Int).Value = _id_categoria_padre;
}
else
{
    objComando.Parameters.Add("id_categoria_padre", DBNull.Value).Value = DBNull.Value;
}

这就是我所做的…

        var PhoneParam = new SqlParameter("@Phone", DBNull.Value);
        if (user.User_Info_Phone != null)
        {
            PhoneParam.SqlValue = user.User_Info_Phone;
        }

        return this.Database.SqlQuery<CustLogonDM>("UpdateUserInfo @UserName, @NameLast, @NameMiddle, @NameFirst, @Address, @City, @State, @PostalCode, @Phone",
            UserNameParam, NameLastParam, NameMiddleParam, NameFirstParam, AddressParam, CityParam, StateParam, PostalParam, PhoneParam).Single();

试试这样做:

if (_id_categoria_padre > 0)
{
    objComando.Parameters.Add("id_categoria_padre", SqlDbType.Int).Value = _id_categoria_padre;
}
else
{
    objComando.Parameters.Add("id_categoria_padre", DBNull.Value).Value = DBNull.Value;
}