我有一个非常简单的JavaScript对象,我将其用作关联数组。是否有一个简单的函数允许我获取值的键,或者我必须迭代对象并手动找到它?
当前回答
使用Underscore.js库:
var hash = {
foo: 1,
bar: 2
};
(_.invert(hash))[1]; // => 'foo'
其他回答
http://jsfiddle.net/rTazZ/2/
var a = new Array();
a.push({"1": "apple", "2": "banana"});
a.push({"3": "coconut", "4": "mango"});
GetIndexByValue(a, "coconut");
function GetIndexByValue(arrayName, value) {
var keyName = "";
var index = -1;
for (var i = 0; i < arrayName.length; i++) {
var obj = arrayName[i];
for (var key in obj) {
if (obj[key] == value) {
keyName = key;
index = i;
}
}
}
//console.log(index);
return index;
}
Non-iteratable解决方案
主要功能:
var keyByValue = function(value) {
var kArray = Object.keys(greetings); // Creating array of keys
var vArray = Object.values(greetings); // Creating array of values
var vIndex = vArray.indexOf(value); // Finding value index
return kArray[vIndex]; // Returning key by value index
}
对象的键和值:
var greetings = {
english : "hello",
ukranian : "привіт"
};
测试:
keyByValue("привіт");
// => "ukranian"
给定输入={"a":"x", "b":"y", "c":"x"}…
使用第一个值(如输出={“x”:“一”,“y”:“b”}):
输入= { “一个”:“x”, “b”:“y”, “c”:“x” } output = Object.keys(input)。reduceRight(函数(accum, key, i) { Accum [input[key]] = key; 返回accum; }, {}) console.log(输出)
使用最后一个值(例如输出={“x”:“c”、“y”:“b”}):
输入= { “一个”:“x”, “b”:“y”, “c”:“x” } output = Object.keys(input)。Reduce(函数(accum, key, i) { Accum [input[key]] = key; 返回accum; }, {}) console.log(输出)
为每个值数组的键(例如输出={“x”:“c”,“a”,“y”:[b]}):
输入= { “一个”:“x”, “b”:“y”, “c”:“x” } output = Object.keys(input)。reduceRight(函数(accum, key, i) { accum[输入[主要]]= (accum[输入[键 ]] || []). concat(关键); 返回accum; }, {}) console.log(输出)
下划线js解决方案
let samplLst = [{id:1,title:Lorem},{id:2,title:Ipsum}]
let sampleKey = _.findLastIndex(samplLst,{_id:2});
//result would be 1
console.log(samplLst[sampleKey])
//output - {id:2,title:Ipsum}
lodash way https://lodash.com/docs#findKey
Var用户= { 'barney':{'年龄':36,'活跃':true}, 'fred': {'age': 40, 'active': false}, '鹅卵石':{'年龄':1,'活动':true} }; _。findKey(users, {'age': 1, 'active': true}); //→'鹅卵石'