我有一个非常简单的JavaScript对象,我将其用作关联数组。是否有一个简单的函数允许我获取值的键,或者我必须迭代对象并手动找到它?
当前回答
lodash way https://lodash.com/docs#findKey
Var用户= { 'barney':{'年龄':36,'活跃':true}, 'fred': {'age': 40, 'active': false}, '鹅卵石':{'年龄':1,'活动':true} }; _。findKey(users, {'age': 1, 'active': true}); //→'鹅卵石'
其他回答
以下是我的解决方案:
例如,我假设我们有一个包含三个值对的对象:
function findKey(object, value) {
for (let key in object)
if (object[key] === value) return key;
return "key is not found";
}
const object = { id_1: "apple", id_2: "pear", id_3: "peach" };
console.log(findKey(object, "pear"));
//expected output: id_2
我们可以简单地编写一个findKey(数组,value),它接受两个参数,一个是对象,一个是你正在寻找的键的值。因此,该方法是可重用的,您不需要每次都手动迭代对象,只需为该函数传递两个参数。
我知道我迟到了,但是你觉得我今天做的这个EMCMAScript 2017解决方案怎么样?它处理多个匹配,因为如果两个键有相同的值会发生什么?这就是我创建这个小片段的原因。
当有一个匹配时,它只返回一个字符串,但当有几个匹配时,它返回一个数组。
let object = { nine_eleven_was_a_inside_job: false, javascript_isnt_useful: false } // Complex, dirty but useful. Handle mutiple matchs which is the main difficulty. Object.prototype.getKeyByValue = function (val) { let array = []; let array2 = []; // Get all the key in the object. for(const [key] of Object.entries(this)) { if (this[key] == val) { // Putting them in the 1st array. array.push(key) } } // List all the value of the 1st array. for(key of array) { // "If one of the key in the array is equal to the value passed in the function (val), it means that 'val' correspond to it." if(this[key] == val) { // Push all the matchs. array2.push(key); } } // Check the lenght of the array. if (array2.length < 2) { // If it's under 2, only return the single value but not in the array. return array2[0]; } else { // If it's above or equal to 2, return the entire array. return array2; } } /* Basic way to do it wich doesn't handle multiple matchs. let getKeyByValue = function (object, val) { for(const [key, content] of Object.entries(object)) { if (object[key] === val) { return key } } } */ console.log(object.getKeyByValue(false))
我们可以使用简单的函数来获取传递的值
const getKeyByValue = (object, value) => Object.keys(object).find(key => object[key] === value)
function extractKeyValue(obj, value) {
return Object.keys(obj)[Object.values(obj).indexOf(value)];
}
用于闭包编译器提取编译后未知的键名
更性感的版本,但使用未来对象。项功能
function objectKeyByValue (obj, val) {
return Object.entries(obj).find(i => i[1] === val);
}
ES6方法:
Object.fromEntries(Object.entries(a).map(b => b.reverse()))['value_you_look_for']