上面接受的答案遇到了一个问题，如果文件已被打开以使用FileShare写入。读取模式或如果文件具有只读属性，代码将无法工作。这个修改后的解决方案最可靠，需要记住两件事(对于公认的解决方案也是如此):

它将不适用于已以写共享模式打开的文件 这没有考虑到线程问题，所以你需要锁定它或单独处理线程问题。

记住上面的内容，这将检查文件是被写入锁定还是被阻止读取锁定:

public static bool FileLocked(string FileName)
{
    FileStream fs = null;

    try
    {
        // NOTE: This doesn't handle situations where file is opened for writing by another process but put into write shared mode, it will not throw an exception and won't show it as write locked
        fs = File.Open(FileName, FileMode.Open, FileAccess.ReadWrite, FileShare.None); // If we can't open file for reading and writing then it's locked by another process for writing
    }
    catch (UnauthorizedAccessException) // https://msdn.microsoft.com/en-us/library/y973b725(v=vs.110).aspx
    {
        // This is because the file is Read-Only and we tried to open in ReadWrite mode, now try to open in Read only mode
        try
        {
            fs = File.Open(FileName, FileMode.Open, FileAccess.Read, FileShare.None);
        }
        catch (Exception)
        {
            return true; // This file has been locked, we can't even open it to read
        }
    }
    catch (Exception)
    {
        return true; // This file has been locked
    }
    finally
    {
        if (fs != null)
            fs.Close();
    }
    return false;
}

您可以返回一个任务，它会在流可用时立即提供给您。这是一个简化的解决方案，但却是一个很好的起点。是线程安全的。

private async Task<Stream> GetStreamAsync()
{
    try
    {
        return new FileStream("sample.mp3", FileMode.Open, FileAccess.Write);
    }
    catch (IOException)
    {
        await Task.Delay(TimeSpan.FromSeconds(1));
        return await GetStreamAsync();
    }
}

你可以像往常一样使用这个流:

using (var stream = await FileStreamGetter.GetStreamAsync())
{
    Console.WriteLine(stream.Length);
}

上面接受的答案遇到了一个问题，如果文件已被打开以使用FileShare写入。读取模式或如果文件具有只读属性，代码将无法工作。这个修改后的解决方案最可靠，需要记住两件事(对于公认的解决方案也是如此):

它将不适用于已以写共享模式打开的文件 这没有考虑到线程问题，所以你需要锁定它或单独处理线程问题。

记住上面的内容，这将检查文件是被写入锁定还是被阻止读取锁定:

public static bool FileLocked(string FileName)
{
    FileStream fs = null;

    try
    {
        // NOTE: This doesn't handle situations where file is opened for writing by another process but put into write shared mode, it will not throw an exception and won't show it as write locked
        fs = File.Open(FileName, FileMode.Open, FileAccess.ReadWrite, FileShare.None); // If we can't open file for reading and writing then it's locked by another process for writing
    }
    catch (UnauthorizedAccessException) // https://msdn.microsoft.com/en-us/library/y973b725(v=vs.110).aspx
    {
        // This is because the file is Read-Only and we tried to open in ReadWrite mode, now try to open in Read only mode
        try
        {
            fs = File.Open(FileName, FileMode.Open, FileAccess.Read, FileShare.None);
        }
        catch (Exception)
        {
            return true; // This file has been locked, we can't even open it to read
        }
    }
    catch (Exception)
    {
        return true; // This file has been locked
    }
    finally
    {
        if (fs != null)
            fs.Close();
    }
    return false;
}

I once needed to upload PDFs to an online backup archive. But the backup would fail if the user had the file open in another program (such as PDF reader). In my haste, I attempted a few of the top answers in this thread but could not get them to work. What did work for me was trying to move the PDF file to its own directory. I found that this would fail if the file was open in another program, and if the move were successful there would be no restore-operation required as there would be if it were moved to a separate directory. I want to post my basic solution in case it may be useful for others' specific use cases.

string str_path_and_name = str_path + '\\' + str_filename;
FileInfo fInfo = new FileInfo(str_path_and_name);
bool open_elsewhere = false;
try
{
    fInfo.MoveTo(str_path_and_name);
}
catch (Exception ex)
{
    open_elsewhere = true;
}

if (open_elsewhere)
{
    //handle case
}

下面是一些代码，据我所知，它与接受的答案相同，但代码更少:

    public static bool IsFileLocked(string file)
    {
        try
        {
            using (var stream = File.OpenRead(file))
                return false;
        }
        catch (IOException)
        {
            return true;
        }        
    }

然而，我认为用以下方式来做会更稳健:

    public static void TryToDoWithFileStream(string file, Action<FileStream> action, 
        int count, int msecTimeOut)
    {
        FileStream stream = null;
        for (var i = 0; i < count; ++i)
        {
            try
            {
                stream = File.OpenRead(file);
                break;
            }
            catch (IOException)
            {
                Thread.Sleep(msecTimeOut);
            }
        }
        action(stream);
    }

只要按预期使用异常即可。接受该文件正在使用，并再次尝试，直到操作完成。这也是最有效的，因为您不需要在执行之前浪费任何检查状态的周期。

例如，使用下面的函数

TimeoutFileAction(() => { System.IO.File.etc...; return null; } );

2秒后超时的可重用方法

private T TimeoutFileAction<T>(Func<T> func)
{
    var started = DateTime.UtcNow;
    while ((DateTime.UtcNow - started).TotalMilliseconds < 2000)
    {
        try
        {
            return func();                    
        }
        catch (System.IO.IOException exception)
        {
            //ignore, or log somewhere if you want to
        }
    }
    return default(T);
}