你可以使用我的库来访问多个应用程序中的文件。

您可以从nuget: install - package Xabe安装它。FileLock

如果你想了解更多信息，请检查 https://github.com/tomaszzmuda/Xabe.FileLock

ILock fileLock = new FileLock(file);
if(fileLock.Acquire(TimeSpan.FromSeconds(15), true))
{
    using(fileLock)
    {
        // file operations here
    }
}

fileLock。Acquire方法仅当可以锁定该对象的文件独占时才返回true。 但是上传文件的应用程序也必须在文件锁中进行上传。 如果对象不可访问，方法返回false。

尝试将文件移动/复制到临时目录。如果可以的话，它没有锁，您可以安全地在临时目录中工作而不需要锁。否则就在x秒内再移动一次。

static bool FileInUse(string path)
    {
        try
        {
            using (FileStream fs = new FileStream(path, FileMode.OpenOrCreate))
            {
                fs.CanWrite
            }
            return false;
        }
        catch (IOException ex)
        {
            return true;
        }
    }

string filePath = "C:\\Documents And Settings\\yourfilename";
bool isFileInUse;

isFileInUse = FileInUse(filePath);

// Then you can do some checking
if (isFileInUse)
   Console.WriteLine("File is in use");
else
   Console.WriteLine("File is not in use");

希望这能有所帮助!

除了工作3-liner，只是为了参考:如果你想要完整的信息-在微软开发中心有一个小项目:

https://code.msdn.microsoft.com/windowsapps/How-to-know-the-process-704839f4

现发现于: https://github.com/TacticalHorse/LockFinder/blob/master/LockFinder.cs

引言:

The C# sample code developed in .NET Framework 4.0 would help in finding out which is the process that is having a lock on a file. RmStartSession function which is included in rstrtmgr.dll has been used to create a restart manager session and according to the return result a new instance of Win32Exception object is created. After registering the resources to a Restart Manager session via RmRegisterRescources function, RmGetList function is invoked to check what are the applications are using a particular file by enumerating the RM_PROCESS_INFO array.

它通过连接到“重启管理器会话”来工作。

重启管理器使用向会话注册的资源列表 确定哪些应用程序和服务必须关闭并重新启动。 资源可以通过文件名、服务短名称或 描述正在运行的应用程序的RM_UNIQUE_PROCESS结构。

为了满足你的特殊需求，它可能有点过度设计了…… 但如果这是你想要的，那就去拿vs-project吧。

只要按预期使用异常即可。接受该文件正在使用，并再次尝试，直到操作完成。这也是最有效的，因为您不需要在执行之前浪费任何检查状态的周期。

例如，使用下面的函数

TimeoutFileAction(() => { System.IO.File.etc...; return null; } );

2秒后超时的可重用方法

private T TimeoutFileAction<T>(Func<T> func)
{
    var started = DateTime.UtcNow;
    while ((DateTime.UtcNow - started).TotalMilliseconds < 2000)
    {
        try
        {
            return func();                    
        }
        catch (System.IO.IOException exception)
        {
            //ignore, or log somewhere if you want to
        }
    }
    return default(T);
}

上面接受的答案遇到了一个问题，如果文件已被打开以使用FileShare写入。读取模式或如果文件具有只读属性，代码将无法工作。这个修改后的解决方案最可靠，需要记住两件事(对于公认的解决方案也是如此):

它将不适用于已以写共享模式打开的文件 这没有考虑到线程问题，所以你需要锁定它或单独处理线程问题。

记住上面的内容，这将检查文件是被写入锁定还是被阻止读取锁定:

public static bool FileLocked(string FileName)
{
    FileStream fs = null;

    try
    {
        // NOTE: This doesn't handle situations where file is opened for writing by another process but put into write shared mode, it will not throw an exception and won't show it as write locked
        fs = File.Open(FileName, FileMode.Open, FileAccess.ReadWrite, FileShare.None); // If we can't open file for reading and writing then it's locked by another process for writing
    }
    catch (UnauthorizedAccessException) // https://msdn.microsoft.com/en-us/library/y973b725(v=vs.110).aspx
    {
        // This is because the file is Read-Only and we tried to open in ReadWrite mode, now try to open in Read only mode
        try
        {
            fs = File.Open(FileName, FileMode.Open, FileAccess.Read, FileShare.None);
        }
        catch (Exception)
        {
            return true; // This file has been locked, we can't even open it to read
        }
    }
    catch (Exception)
    {
        return true; // This file has been locked
    }
    finally
    {
        if (fs != null)
            fs.Close();
    }
    return false;
}