你也可以使用void操作符来获得一个未定义的值:

if (input !== void 0) {
    // do stuff    
}

(是的，正如另一个答案所指出的，如果变量没有声明，这将抛出一个错误，但这种情况通常可以通过代码检查或代码重构来排除，例如使用window。输入!== void 0测试全局变量或添加var输入)

(function(){ var a= b = 3; var ed = 103; })(); //console.log(ed); //ed is not defined console.log("a defined? " + (typeof a !== 'undefined')); //no define console.log("b defined? " + (typeof b !== 'undefined')); //yes define console.log(typeof(b)); //number console.log(typeof(4+7)); //number console.log(b); //3 console.log(typeof("4"+"7")); //string var e= "ggg"; console.log(typeof(e)); //string var ty=typeof(b); console.log(ty); //number console.log(typeof false); //boolean console.log(typeof 1); //number console.log(typeof 0); //number console.log(typeof true); //boolean console.log(typeof Math.tan); //function console.log(typeof function(){}); //function if(typeof neverDeclared == "undefined") //no errors if(typeof neverDeclared === "undefined") //no errors //if(neverDeclared == null) //showing error console.log(typeof {a:1}); //object console.log(typeof null); //object console.log(typeof JSON); //object console.log(typeof Math); //object console.log(typeof /a-z/); //object console.log(typeof new Date()); //object console.log(typeof afbc); //undefined //console.log(typeof new);//error document.write("<br> * oprator as math "); var r=14*"4"; document.write(r); document.write("<br> + oprator as string "); var r=14+"44"; document.write(r); document.write("<br> Minus Operator work as mathematic "); var r=64-"44"; document.write(r); document.write("<br>"); console.log(typeof(4*"7")); //returns number console.log(typeof(4+"7")); //returns string Interview Question in JavaScript

function greet(name, greeting) { name = (typeof name !== 'undefined') ? name : 'Student'; greeting = (typeof greeting !== 'undefined') ? greeting : 'Welcome'; console.log(greeting,name); } greet(); // Welcome Student! greet('James'); // Welcome James! greet('Richard', 'Howdy'); // Howdy Richard! //ES6 provides new ways of introducing default function parameters this way: function greet2(name = 'Student', greeting = 'Welcome') { // return '${greeting} ${name}!'; console.log(greeting,name); } greet2(); // Welcome Student! greet2('James'); // Welcome James! greet2('Richard', 'Howdy'); // Howdy Richard!

var bar = null; console.log(typeof bar === "object"); //true yes //because null a datatype of object var barf = "dff"; console.log(typeof barf.constructor);//function console.log(Array.isArray(bar));//falsss console.log((bar !== null) && (bar.constructor === Object)); //false console.log((bar !== null) && (typeof bar === "object")); // logs false //because bar!==null, bar is a object console.log((bar !== null) && ((typeof bar === "object") || (typeof bar === "function"))); //false console.log(typeof bar === typeof object); //false console.log(typeof bar2 === typeof undefined); //true console.log(typeof bar3 === typeof undefinedff); //true console.log(typeof bar2 == typeof undefined); //true console.log((bar !== null) && (typeof bar === "object") && (toString.call(bar) !== "[object Array]")); //false

如果声明了变量(使用var关键字，作为函数参数，或作为全局变量)，我认为最好的方法是:

if (my_variable === undefined)

jQuery做到了，所以它对我来说足够好了:-)

否则，你必须使用typeof来避免ReferenceError。

如果你希望undefined被重新定义，你可以像这样包装你的代码:

(function(undefined){
    // undefined is now what it's supposed to be
})();

或者通过void操作符获取:

const undefined = void 0;
// also safe

我实际上遇到过if (typeof input !== 'undefined')在这个场景中，它被用来提供默认的函数参数:

function greet(name, greeting) {
  name = (typeof name !== 'undefined') ?  name : 'Student';
  greeting = (typeof greeting !== 'undefined') ?  greeting : 'Welcome';

  return `${greeting} ${name}!`;
}

greet(); // Welcome Student!
greet('James'); // Welcome James!
greet('Richard', 'Howdy'); // Howdy Richard!

ES6提供了引入默认函数参数的新方法:

function greet(name = 'Student', greeting = 'Welcome') {
  return `${greeting} ${name}!`;
}

greet(); // Welcome Student!
greet('James'); // Welcome James!
greet('Richard', 'Howdy'); // Howdy Richard!

这比第一个选项更简洁。