虽然我在这方面姗姗来迟，但格雷厄姆的答案远非最佳。特别是，你不需要使用模数，调用ToString()和apply (int)强制转换。考虑到在c#世界中的大多数情况下，您将从0开始编号，以下是我的修订:

public static string GetColumnName(int index) // zero-based
{
    const byte BASE = 'Z' - 'A' + 1;
    string name = String.Empty;

    do
    {
        name = Convert.ToChar('A' + index % BASE) + name;
        index = index / BASE - 1;
    }
    while (index >= 0);

    return name;
}

在Java中实现相同

public String getExcelColumnName (int columnNumber) 
    {     
        int dividend = columnNumber;   
        int i;
        String columnName = "";     
        int modulo;     
        while (dividend > 0)     
        {        
            modulo = (dividend - 1) % 26;         
            i = 65 + modulo;
            columnName = new Character((char)i).toString() + columnName;        
            dividend = (int)((dividend - modulo) / 26);    
        }       
        return columnName; 
    }  

我正在尝试在Java中做同样的事情… 我写了以下代码:

private String getExcelColumnName(int columnNumber) {

    int dividend = columnNumber;
    String columnName = "";
    int modulo;

    while (dividend > 0)
    {
        modulo = (dividend - 1) % 26;

        char val = Character.valueOf((char)(65 + modulo));

        columnName += val;

        dividend = (int)((dividend - modulo) / 26);
    } 

    return columnName;
}

现在，一旦我用columnNumber = 29运行它，它给我的结果=“CA”(而不是“AC”) 有什么意见吗? 我知道我可以通过StringBuilder....反转它但看着格雷厄姆的回答，我有点困惑....

我的解决方案基于Graham, Herman Kan和desseim的回答，使用StringBuilder:

internal class Program
{
    #region get_excel_col_name
    /// <summary>
    /// Returns the name of the column by its number
    /// </summary>
    /// <param name="col_num">Column number</param>
    /// <returns>Column name</returns>
    /// <remarks>Numbering columns from zero</remarks>
    private static string get_excel_col_name(int col_num)
    {
        StringBuilder sb = new StringBuilder(2);
        if (col_num >= 0)
        {
            do
            {
                sb.Insert(0, (char)(col_num % 26 + 65));
                col_num /= 26;
            }
            while (--col_num >= 0);
        }
        return sb.ToString();
    }
    #endregion

    private static void Main(string[] args)
    {
        Console.WriteLine(get_excel_col_name(34));//outputs AI
        Console.ReadKey(true);
    }
}

在Delphi (Pascal)中:

function GetExcelColumnName(columnNumber: integer): string;
var
  dividend, modulo: integer;
begin
  Result := '';
  dividend := columnNumber;
  while dividend > 0 do begin
    modulo := (dividend - 1) mod 26;
    Result := Chr(65 + modulo) + Result;
    dividend := (dividend - modulo) div 26;
  end;
end;

在查看了这里提供的所有版本后，我决定自己使用递归来做一个。

这是我的vb.net版本:

Function CL(ByVal x As Integer) As String
    If x >= 1 And x <= 26 Then
        CL = Chr(x + 64)
    Else
        CL = CL((x - x Mod 26) / 26) & Chr((x Mod 26) + 1 + 64)
    End If
End Function