如何在c#中将数值转换为Excel列名,而不使用直接从Excel中获取值的自动化。
Excel 2007的范围可能是1到16384,这是它支持的列数。结果值应以excel列名的形式出现,例如A、AA、AAA等。
如何在c#中将数值转换为Excel列名,而不使用直接从Excel中获取值的自动化。
Excel 2007的范围可能是1到16384,这是它支持的列数。结果值应以excel列名的形式出现,例如A、AA、AAA等。
当前回答
static string[] ExcelColumnAlphabetIdentifiers = new string[] { "", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N",
"O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z" };
public static string ExcelColumnAlphabetIdentifier( int ColumnNumber)
{
StringBuilder sb = new StringBuilder();
int remainder = ColumnNumber;
do
{
sb.Append(ExcelColumnAlphabetIdentifiers[remainder % 26]);
remainder = remainder / 26;
}
while (remainder > 0);
return sb.ToString();
}
其他回答
这个答案是用javaScript写的:
function getCharFromNumber(columnNumber){
var dividend = columnNumber;
var columnName = "";
var modulo;
while (dividend > 0)
{
modulo = (dividend - 1) % 26;
columnName = String.fromCharCode(65 + modulo).toString() + columnName;
dividend = parseInt((dividend - modulo) / 26);
}
return columnName;
}
如果有人需要在没有VBA的Excel中做到这一点,这里有一种方法:
=SUBSTITUTE(ADDRESS(1;colNum;4);"1";"")
其中colNum是列号
在VBA中:
Function GetColumnName(colNum As Integer) As String
Dim d As Integer
Dim m As Integer
Dim name As String
d = colNum
name = ""
Do While (d > 0)
m = (d - 1) Mod 26
name = Chr(65 + m) + name
d = Int((d - m) / 26)
Loop
GetColumnName = name
End Function
这是一个javascript版本,根据格雷厄姆的代码
function (columnNumber) {
var dividend = columnNumber;
var columnName = "";
var modulo;
while (dividend > 0) {
modulo = (dividend - 1) % 26;
columnName = String.fromCharCode(65 + modulo) + columnName;
dividend = parseInt((dividend - modulo) / 26);
}
return columnName;
};
在Delphi (Pascal)中:
function GetExcelColumnName(columnNumber: integer): string;
var
dividend, modulo: integer;
begin
Result := '';
dividend := columnNumber;
while dividend > 0 do begin
modulo := (dividend - 1) mod 26;
Result := Chr(65 + modulo) + Result;
dividend := (dividend - modulo) div 26;
end;
end;
private String getColumn(int c) {
String s = "";
do {
s = (char)('A' + (c % 26)) + s;
c /= 26;
} while (c-- > 0);
return s;
}
它不是以26为底,系统中没有0。如果有的话,'Z'后面应该是'BA'而不是'AA'。