我在vb.net上寻找同样的解决方案，我发现了这个，它很棒。

然而，@JohnOdom建议了一个更好的方法来处理空格，如果前一个空格比当前空格大。

我在vb.net做了一个函数，认为有人可以得到帮助。

这是我的代码:

Private Sub sPrintStatus(strTextToPrint As String, Optional boolIsNewLine As Boolean = False)
    REM intLastLength is declared as public variable on global scope like below
    REM intLastLength As Integer
    If boolIsNewLine = True Then
        intLastLength = 0
    End If
    If intLastLength > strTextToPrint.Length Then
        Console.Write(Convert.ToChar(13) & strTextToPrint.PadRight(strTextToPrint.Length + (intLastLength - strTextToPrint.Length), Convert.ToChar(" ")))
    Else
        Console.Write(Convert.ToChar(13) & strTextToPrint)
    End If
    intLastLength = strTextToPrint.Length
End Sub

如果要更新一行，但信息太长而不能在一行上显示，则可能需要一些新行。我遇到过这个问题，下面是解决这个问题的一种方法。

public class DumpOutPutInforInSameLine
{

    //content show in how many lines
    int TotalLine = 0;

    //start cursor line
    int cursorTop = 0;

    // use to set  character number show in one line
    int OneLineCharNum = 75;

    public void DumpInformation(string content)
    {
        OutPutInSameLine(content);
        SetBackSpace();

    }
    static void backspace(int n)
    {
        for (var i = 0; i < n; ++i)
            Console.Write("\b \b");
    }

    public  void SetBackSpace()
    {

        if (TotalLine == 0)
        {
            backspace(OneLineCharNum);
        }
        else
        {
            TotalLine--;
            while (TotalLine >= 0)
            {
                backspace(OneLineCharNum);
                TotalLine--;
                if (TotalLine >= 0)
                {
                    Console.SetCursorPosition(OneLineCharNum, cursorTop + TotalLine);
                }
            }
        }

    }

    private void OutPutInSameLine(string content)
    {
        //Console.WriteLine(TotalNum);

        cursorTop = Console.CursorTop;

        TotalLine = content.Length / OneLineCharNum;

        if (content.Length % OneLineCharNum > 0)
        {
            TotalLine++;

        }

        if (TotalLine == 0)
        {
            Console.Write("{0}", content);

            return;

        }

        int i = 0;
        while (i < TotalLine)
        {
            int cNum = i * OneLineCharNum;
            if (i < TotalLine - 1)
            {
                Console.WriteLine("{0}", content.Substring(cNum, OneLineCharNum));
            }
            else
            {
                Console.Write("{0}", content.Substring(cNum, content.Length - cNum));
            }
            i++;

        }
    }

}
class Program
{
    static void Main(string[] args)
    {

        DumpOutPutInforInSameLine outPutInSameLine = new DumpOutPutInforInSameLine();

        outPutInSameLine.DumpInformation("");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");


        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");

        //need several lines
        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");

        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbb");

    }
}

我只需要使用divo的ConsoleSpinner类。我的远没有那么简洁，但我不喜欢这个类的用户必须编写自己的while(true)循环。我追求的是这样的经历:

static void Main(string[] args)
{
    Console.Write("Working....");
    ConsoleSpinner spin = new ConsoleSpinner();
    spin.Start();

    // Do some work...

    spin.Stop(); 
}

我用下面的代码实现了它。由于我不希望Start()方法阻塞，我不希望用户不得不担心编写while(spinFlag)类循环，并且我希望同时允许多个旋转器，因此我必须生成一个单独的线程来处理旋转。这意味着代码要复杂得多。

此外，我没有做那么多多线程，所以有可能(甚至可能)我在那里留下了一个或三个微妙的错误。但到目前为止，它似乎运行得很好:

public class ConsoleSpinner : IDisposable
{       
    public ConsoleSpinner()
    {
        CursorLeft = Console.CursorLeft;
        CursorTop = Console.CursorTop;  
    }

    public ConsoleSpinner(bool start)
        : this()
    {
        if (start) Start();
    }

    public void Start()
    {
        // prevent two conflicting Start() calls ot the same instance
        lock (instanceLocker) 
        {
            if (!running )
            {
                running = true;
                turner = new Thread(Turn);
                turner.Start();
            }
        }
    }

    public void StartHere()
    {
        SetPosition();
        Start();
    }

    public void Stop()
    {
        lock (instanceLocker)
        {
            if (!running) return;

            running = false;
            if (! turner.Join(250))
                turner.Abort();
        }
    }

    public void SetPosition()
    {
        SetPosition(Console.CursorLeft, Console.CursorTop);
    }

    public void SetPosition(int left, int top)
    {
        bool wasRunning;
        //prevent other start/stops during move
        lock (instanceLocker)
        {
            wasRunning = running;
            Stop();

            CursorLeft = left;
            CursorTop = top;

            if (wasRunning) Start();
        } 
    }

    public bool IsSpinning { get { return running;} }

    /* ---  PRIVATE --- */

    private int counter=-1;
    private Thread turner; 
    private bool running = false;
    private int rate = 100;
    private int CursorLeft;
    private int CursorTop;
    private Object instanceLocker = new Object();
    private static Object console = new Object();

    private void Turn()
    {
        while (running)
        {
            counter++;

            // prevent two instances from overlapping cursor position updates
            // weird things can still happen if the main ui thread moves the cursor during an update and context switch
            lock (console)
            {                  
                int OldLeft = Console.CursorLeft;
                int OldTop = Console.CursorTop;
                Console.SetCursorPosition(CursorLeft, CursorTop);

                switch (counter)
                {
                    case 0: Console.Write("/"); break;
                    case 1: Console.Write("-"); break;
                    case 2: Console.Write("\\"); break;
                    case 3: Console.Write("|"); counter = -1; break;
                }
                Console.SetCursorPosition(OldLeft, OldTop);
            }

            Thread.Sleep(rate);
        }
        lock (console)
        {   // clean up
            int OldLeft = Console.CursorLeft;
            int OldTop = Console.CursorTop;
            Console.SetCursorPosition(CursorLeft, CursorTop);
            Console.Write(' ');
            Console.SetCursorPosition(OldLeft, OldTop);
        }
    }

    public void Dispose()
    {
        Stop();
    }
}

我在vb.net上寻找同样的解决方案，我发现了这个，它很棒。

然而，@JohnOdom建议了一个更好的方法来处理空格，如果前一个空格比当前空格大。

我在vb.net做了一个函数，认为有人可以得到帮助。

这是我的代码:

Private Sub sPrintStatus(strTextToPrint As String, Optional boolIsNewLine As Boolean = False)
    REM intLastLength is declared as public variable on global scope like below
    REM intLastLength As Integer
    If boolIsNewLine = True Then
        intLastLength = 0
    End If
    If intLastLength > strTextToPrint.Length Then
        Console.Write(Convert.ToChar(13) & strTextToPrint.PadRight(strTextToPrint.Length + (intLastLength - strTextToPrint.Length), Convert.ToChar(" ")))
    Else
        Console.Write(Convert.ToChar(13) & strTextToPrint)
    End If
    intLastLength = strTextToPrint.Length
End Sub

来自MSDN的控制台文档:

您可以通过设置 TextWriter。属性的NewLine 属性转移到另一行 终止的字符串。例如， c#语句，Console.Error.NewLine = “\r\n\r\n”;，设置行终止 字符串用于标准错误输出 流到两车厢返回并行 饲料序列。然后你就可以 显式调用WriteLine方法 错误输出流对象的 在c#语句中， Console.Error.WriteLine ();

所以，我这样做了:

Console.Out.Newline = String.Empty;

然后我就可以自己控制输出了;

Console.WriteLine("Starting item 1:");
    Item1();
Console.WriteLine("OK.\nStarting Item2:");

另一种方法。

如果你想让生成的文件看起来很酷，这是可行的。

                int num = 1;
                var spin = new ConsoleSpinner();
                Console.ForegroundColor = ConsoleColor.Green;
                Console.Write("");
                while (true)
                {
                    spin.Turn();
                    Console.Write("\r{0} Generating Files ", num);
                    num++;
                }

这是我从下面的一些答案得到的方法，并修改了它

public class ConsoleSpinner
    {
        int counter;

        public void Turn()
        {
            counter++;
            switch (counter % 4)
            {
                case 0: Console.Write("."); counter = 0; break;
                case 1: Console.Write(".."); break;
                case 2: Console.Write("..."); break;
                case 3: Console.Write("...."); break;
                case 4: Console.Write("\r"); break;
            }
            Thread.Sleep(100);
            Console.SetCursorPosition(23, Console.CursorTop);
        }
    }