如果你想让生成的文件看起来很酷，这是可行的。

                int num = 1;
                var spin = new ConsoleSpinner();
                Console.ForegroundColor = ConsoleColor.Green;
                Console.Write("");
                while (true)
                {
                    spin.Turn();
                    Console.Write("\r{0} Generating Files ", num);
                    num++;
                }

这是我从下面的一些答案得到的方法，并修改了它

public class ConsoleSpinner
    {
        int counter;

        public void Turn()
        {
            counter++;
            switch (counter % 4)
            {
                case 0: Console.Write("."); counter = 0; break;
                case 1: Console.Write(".."); break;
                case 2: Console.Write("..."); break;
                case 3: Console.Write("...."); break;
                case 4: Console.Write("\r"); break;
            }
            Thread.Sleep(100);
            Console.SetCursorPosition(23, Console.CursorTop);
        }
    }

如果你只打印“\r”到控制台，光标会回到当前行的开头，然后你可以重写它。这应该可以达到目的:

for(int i = 0; i < 100; ++i)
{
    Console.Write("\r{0}%   ", i);
}

注意数字后面的几个空格，以确保之前的任何内容都被擦除。 还要注意使用Write()而不是WriteLine()，因为您不想在行末添加“\n”。

这是另一个选项:D

class Program
{
    static void Main(string[] args)
    {
        Console.Write("Working... ");
        int spinIndex = 0;
        while (true)
        {
            // obfuscate FTW! Let's hope overflow is disabled or testers are impatient
            Console.Write("\b" + @"/-\|"[(spinIndex++) & 3]);
        }
    }
}

在行首显式地使用Carrage Return (\r)，而不是(隐式或显式地)在行尾使用New line (\n)，应该得到你想要的结果。例如:

void demoPercentDone() {
    for(int i = 0; i < 100; i++) {
        System.Console.Write( "\rProcessing {0}%...", i );
        System.Threading.Thread.Sleep( 1000 );
    }
    System.Console.WriteLine();    
}

你可以使用控制台。SetCursorPosition设置光标的位置，然后在当前位置写入。

下面是一个简单的“spinner”的例子:

static void Main(string[] args)
{
    var spin = new ConsoleSpinner();
    Console.Write("Working....");
    while (true) 
    {
        spin.Turn();
    }
}

public class ConsoleSpinner
{
    int counter;

    public void Turn()
    {
        counter++;        
        switch (counter % 4)
        {
            case 0: Console.Write("/"); counter = 0; break;
            case 1: Console.Write("-"); break;
            case 2: Console.Write("\\"); break;
            case 3: Console.Write("|"); break;
        }
        Thread.Sleep(100);
        Console.SetCursorPosition(Console.CursorLeft - 1, Console.CursorTop);
    }
}

请注意，您必须确保用新的输出或空白覆盖任何现有输出。

更新:因为它被批评的例子移动光标只向后一个字符，我将添加这个澄清:使用SetCursorPosition你可以设置光标到控制台窗口的任何位置。

Console.SetCursorPosition(0, Console.CursorTop);

将光标设置到当前行的开头(或者您可以使用Console。CursorLeft = 0直接)。

到目前为止，我们有三个相互竞争的替代方案:

Console.Write("\r{0}   ", value);                      // Option 1: carriage return
Console.Write("\b\b\b\b\b{0}", value);                 // Option 2: backspace
{                                                      // Option 3 in two parts:
    Console.SetCursorPosition(0, Console.CursorTop);   // - Move cursor
    Console.Write(value);                              // - Rewrite
}

我一直使用控制台。CursorLeft = 0，第三个选项的变体，所以我决定做一些测试。下面是我使用的代码:

public static void CursorTest()
{
    int testsize = 1000000;

    Console.WriteLine("Testing cursor position");
    Stopwatch sw = new Stopwatch();
    sw.Start();
    for (int i = 0; i < testsize; i++)
    {
        Console.Write("\rCounting: {0}     ", i);
    }
    sw.Stop();
    Console.WriteLine("\nTime using \\r: {0}", sw.ElapsedMilliseconds);

    sw.Reset();
    sw.Start();
    int top = Console.CursorTop;
    for (int i = 0; i < testsize; i++)
    {
        Console.SetCursorPosition(0, top);        
        Console.Write("Counting: {0}     ", i);
    }
    sw.Stop();
    Console.WriteLine("\nTime using CursorLeft: {0}", sw.ElapsedMilliseconds);

    sw.Reset();
    sw.Start();
    Console.Write("Counting:          ");
    for (int i = 0; i < testsize; i++)
    {        
        Console.Write("\b\b\b\b\b\b\b\b{0,8}", i);
    }

    sw.Stop();
    Console.WriteLine("\nTime using \\b: {0}", sw.ElapsedMilliseconds);
}

在我的机器上，我得到了以下结果:

退格:25.0秒 回车:28.7秒 SetCursorPosition: 49.7秒

此外，SetCursorPosition引起了明显的闪烁，我没有观察到任何一个替代方案。所以，道德是尽可能使用退格或回车，谢谢你教我一个更快的方法来做到这一点，所以!

Update: In the comments, Joel suggests that SetCursorPosition is constant with respect to the distance moved while the other methods are linear. Further testing confirms that this is the case, however constant time and slow is still slow. In my tests, writing a long string of backspaces to the console is faster than SetCursorPosition until somewhere around 60 characters. So backspace is faster for replacing portions of the line shorter than 60 characters (or so), and it doesn't flicker, so I'm going to stand by my initial endorsement of \b over \r and SetCursorPosition.