如果要更新一行，但信息太长而不能在一行上显示，则可能需要一些新行。我遇到过这个问题，下面是解决这个问题的一种方法。

public class DumpOutPutInforInSameLine
{

    //content show in how many lines
    int TotalLine = 0;

    //start cursor line
    int cursorTop = 0;

    // use to set  character number show in one line
    int OneLineCharNum = 75;

    public void DumpInformation(string content)
    {
        OutPutInSameLine(content);
        SetBackSpace();

    }
    static void backspace(int n)
    {
        for (var i = 0; i < n; ++i)
            Console.Write("\b \b");
    }

    public  void SetBackSpace()
    {

        if (TotalLine == 0)
        {
            backspace(OneLineCharNum);
        }
        else
        {
            TotalLine--;
            while (TotalLine >= 0)
            {
                backspace(OneLineCharNum);
                TotalLine--;
                if (TotalLine >= 0)
                {
                    Console.SetCursorPosition(OneLineCharNum, cursorTop + TotalLine);
                }
            }
        }

    }

    private void OutPutInSameLine(string content)
    {
        //Console.WriteLine(TotalNum);

        cursorTop = Console.CursorTop;

        TotalLine = content.Length / OneLineCharNum;

        if (content.Length % OneLineCharNum > 0)
        {
            TotalLine++;

        }

        if (TotalLine == 0)
        {
            Console.Write("{0}", content);

            return;

        }

        int i = 0;
        while (i < TotalLine)
        {
            int cNum = i * OneLineCharNum;
            if (i < TotalLine - 1)
            {
                Console.WriteLine("{0}", content.Substring(cNum, OneLineCharNum));
            }
            else
            {
                Console.Write("{0}", content.Substring(cNum, content.Length - cNum));
            }
            i++;

        }
    }

}
class Program
{
    static void Main(string[] args)
    {

        DumpOutPutInforInSameLine outPutInSameLine = new DumpOutPutInforInSameLine();

        outPutInSameLine.DumpInformation("");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");


        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");

        //need several lines
        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");

        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbb");

    }
}

如果你想让生成的文件看起来很酷，这是可行的。

                int num = 1;
                var spin = new ConsoleSpinner();
                Console.ForegroundColor = ConsoleColor.Green;
                Console.Write("");
                while (true)
                {
                    spin.Turn();
                    Console.Write("\r{0} Generating Files ", num);
                    num++;
                }

这是我从下面的一些答案得到的方法，并修改了它

public class ConsoleSpinner
    {
        int counter;

        public void Turn()
        {
            counter++;
            switch (counter % 4)
            {
                case 0: Console.Write("."); counter = 0; break;
                case 1: Console.Write(".."); break;
                case 2: Console.Write("..."); break;
                case 3: Console.Write("...."); break;
                case 4: Console.Write("\r"); break;
            }
            Thread.Sleep(100);
            Console.SetCursorPosition(23, Console.CursorTop);
        }
    }

到目前为止，我们有三个相互竞争的替代方案:

Console.Write("\r{0}   ", value);                      // Option 1: carriage return
Console.Write("\b\b\b\b\b{0}", value);                 // Option 2: backspace
{                                                      // Option 3 in two parts:
    Console.SetCursorPosition(0, Console.CursorTop);   // - Move cursor
    Console.Write(value);                              // - Rewrite
}

我一直使用控制台。CursorLeft = 0，第三个选项的变体，所以我决定做一些测试。下面是我使用的代码:

public static void CursorTest()
{
    int testsize = 1000000;

    Console.WriteLine("Testing cursor position");
    Stopwatch sw = new Stopwatch();
    sw.Start();
    for (int i = 0; i < testsize; i++)
    {
        Console.Write("\rCounting: {0}     ", i);
    }
    sw.Stop();
    Console.WriteLine("\nTime using \\r: {0}", sw.ElapsedMilliseconds);

    sw.Reset();
    sw.Start();
    int top = Console.CursorTop;
    for (int i = 0; i < testsize; i++)
    {
        Console.SetCursorPosition(0, top);        
        Console.Write("Counting: {0}     ", i);
    }
    sw.Stop();
    Console.WriteLine("\nTime using CursorLeft: {0}", sw.ElapsedMilliseconds);

    sw.Reset();
    sw.Start();
    Console.Write("Counting:          ");
    for (int i = 0; i < testsize; i++)
    {        
        Console.Write("\b\b\b\b\b\b\b\b{0,8}", i);
    }

    sw.Stop();
    Console.WriteLine("\nTime using \\b: {0}", sw.ElapsedMilliseconds);
}

在我的机器上，我得到了以下结果:

退格:25.0秒 回车:28.7秒 SetCursorPosition: 49.7秒

此外，SetCursorPosition引起了明显的闪烁，我没有观察到任何一个替代方案。所以，道德是尽可能使用退格或回车，谢谢你教我一个更快的方法来做到这一点，所以!

Update: In the comments, Joel suggests that SetCursorPosition is constant with respect to the distance moved while the other methods are linear. Further testing confirms that this is the case, however constant time and slow is still slow. In my tests, writing a long string of backspaces to the console is faster than SetCursorPosition until somewhere around 60 characters. So backspace is faster for replacing portions of the line shorter than 60 characters (or so), and it doesn't flicker, so I'm going to stand by my initial endorsement of \b over \r and SetCursorPosition.

你可以使用控制台。SetCursorPosition设置光标的位置，然后在当前位置写入。

下面是一个简单的“spinner”的例子:

static void Main(string[] args)
{
    var spin = new ConsoleSpinner();
    Console.Write("Working....");
    while (true) 
    {
        spin.Turn();
    }
}

public class ConsoleSpinner
{
    int counter;

    public void Turn()
    {
        counter++;        
        switch (counter % 4)
        {
            case 0: Console.Write("/"); counter = 0; break;
            case 1: Console.Write("-"); break;
            case 2: Console.Write("\\"); break;
            case 3: Console.Write("|"); break;
        }
        Thread.Sleep(100);
        Console.SetCursorPosition(Console.CursorLeft - 1, Console.CursorTop);
    }
}

请注意，您必须确保用新的输出或空白覆盖任何现有输出。

更新:因为它被批评的例子移动光标只向后一个字符，我将添加这个澄清:使用SetCursorPosition你可以设置光标到控制台窗口的任何位置。

Console.SetCursorPosition(0, Console.CursorTop);

将光标设置到当前行的开头(或者您可以使用Console。CursorLeft = 0直接)。

如果你只打印“\r”到控制台，光标会回到当前行的开头，然后你可以重写它。这应该可以达到目的:

for(int i = 0; i < 100; ++i)
{
    Console.Write("\r{0}%   ", i);
}

注意数字后面的几个空格，以确保之前的任何内容都被擦除。 还要注意使用Write()而不是WriteLine()，因为您不想在行末添加“\n”。

来自MSDN的控制台文档:

您可以通过设置 TextWriter。属性的NewLine 属性转移到另一行 终止的字符串。例如， c#语句，Console.Error.NewLine = “\r\n\r\n”;，设置行终止 字符串用于标准错误输出 流到两车厢返回并行 饲料序列。然后你就可以 显式调用WriteLine方法 错误输出流对象的 在c#语句中， Console.Error.WriteLine ();

所以，我这样做了:

Console.Out.Newline = String.Empty;

然后我就可以自己控制输出了;

Console.WriteLine("Starting item 1:");
    Item1();
Console.WriteLine("OK.\nStarting Item2:");

另一种方法。