如果要更新一行，但信息太长而不能在一行上显示，则可能需要一些新行。我遇到过这个问题，下面是解决这个问题的一种方法。

public class DumpOutPutInforInSameLine
{

    //content show in how many lines
    int TotalLine = 0;

    //start cursor line
    int cursorTop = 0;

    // use to set  character number show in one line
    int OneLineCharNum = 75;

    public void DumpInformation(string content)
    {
        OutPutInSameLine(content);
        SetBackSpace();

    }
    static void backspace(int n)
    {
        for (var i = 0; i < n; ++i)
            Console.Write("\b \b");
    }

    public  void SetBackSpace()
    {

        if (TotalLine == 0)
        {
            backspace(OneLineCharNum);
        }
        else
        {
            TotalLine--;
            while (TotalLine >= 0)
            {
                backspace(OneLineCharNum);
                TotalLine--;
                if (TotalLine >= 0)
                {
                    Console.SetCursorPosition(OneLineCharNum, cursorTop + TotalLine);
                }
            }
        }

    }

    private void OutPutInSameLine(string content)
    {
        //Console.WriteLine(TotalNum);

        cursorTop = Console.CursorTop;

        TotalLine = content.Length / OneLineCharNum;

        if (content.Length % OneLineCharNum > 0)
        {
            TotalLine++;

        }

        if (TotalLine == 0)
        {
            Console.Write("{0}", content);

            return;

        }

        int i = 0;
        while (i < TotalLine)
        {
            int cNum = i * OneLineCharNum;
            if (i < TotalLine - 1)
            {
                Console.WriteLine("{0}", content.Substring(cNum, OneLineCharNum));
            }
            else
            {
                Console.Write("{0}", content.Substring(cNum, content.Length - cNum));
            }
            i++;

        }
    }

}
class Program
{
    static void Main(string[] args)
    {

        DumpOutPutInforInSameLine outPutInSameLine = new DumpOutPutInforInSameLine();

        outPutInSameLine.DumpInformation("");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");


        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");

        //need several lines
        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb");

        outPutInSameLine.DumpInformation("aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa");
        outPutInSameLine.DumpInformation("bbbbbbbbbbbbbbbbbbbbbbbbbbb");

    }
}

    public void Update(string data)
    {
        Console.Write(string.Format("\r{0}", "".PadLeft(Console.CursorLeft, ' ')));
        Console.Write(string.Format("\r{0}", data));
    }

我做了一个搜索，看看我写的解决方案是否可以优化速度。我想要的是一个倒数计时器，而不仅仅是更新当前行。 这是我想到的。可能对某人有用

            int sleepTime = 5 * 60;    // 5 minutes

            for (int secondsRemaining = sleepTime; secondsRemaining > 0; secondsRemaining --)
            {
                double minutesPrecise = secondsRemaining / 60;
                double minutesRounded = Math.Round(minutesPrecise, 0);
                int seconds = Convert.ToInt32((minutesRounded * 60) - secondsRemaining);
                Console.Write($"\rProcess will resume in {minutesRounded}:{String.Format("{0:D2}", -seconds)} ");
                Thread.Sleep(1000);
            }
            Console.WriteLine("");

如果你只打印“\r”到控制台，光标会回到当前行的开头，然后你可以重写它。这应该可以达到目的:

for(int i = 0; i < 100; ++i)
{
    Console.Write("\r{0}%   ", i);
}

注意数字后面的几个空格，以确保之前的任何内容都被擦除。 还要注意使用Write()而不是WriteLine()，因为您不想在行末添加“\n”。

如果你想让生成的文件看起来很酷，这是可行的。

                int num = 1;
                var spin = new ConsoleSpinner();
                Console.ForegroundColor = ConsoleColor.Green;
                Console.Write("");
                while (true)
                {
                    spin.Turn();
                    Console.Write("\r{0} Generating Files ", num);
                    num++;
                }

这是我从下面的一些答案得到的方法，并修改了它

public class ConsoleSpinner
    {
        int counter;

        public void Turn()
        {
            counter++;
            switch (counter % 4)
            {
                case 0: Console.Write("."); counter = 0; break;
                case 1: Console.Write(".."); break;
                case 2: Console.Write("..."); break;
                case 3: Console.Write("...."); break;
                case 4: Console.Write("\r"); break;
            }
            Thread.Sleep(100);
            Console.SetCursorPosition(23, Console.CursorTop);
        }
    }

这是另一个选项:D

class Program
{
    static void Main(string[] args)
    {
        Console.Write("Working... ");
        int spinIndex = 0;
        while (true)
        {
            // obfuscate FTW! Let's hope overflow is disabled or testers are impatient
            Console.Write("\b" + @"/-\|"[(spinIndex++) & 3]);
        }
    }
}