可以这样做:

public static class ForEachExtensions
{
    public static void ForEachWithIndex<T>(this IEnumerable<T> enumerable, Action<T, int> handler)
    {
        int idx = 0;
        foreach (T item in enumerable)
            handler(item, idx++);
    }
}

public class Example
{
    public static void Main()
    {
        string[] values = new[] { "foo", "bar", "baz" };

        values.ForEachWithIndex((item, idx) => Console.WriteLine("{0}: {1}", idx, item));
    }
}

这并没有回答您的具体问题，但它确实为您的问题提供了一个解决方案:使用for循环来遍历对象集合。然后您将得到您正在处理的当前索引。

// Untested
for (int i = 0; i < collection.Count; i++)
{
    Console.WriteLine("My index is " + i);
}

我只是遇到了这个问题，但在我的情况下思考这个问题给出了最好的解决方案，与预期的解决方案无关。

It could be quite a common case, basically, I'm reading from one source list and creating objects based on them in a destination list, however, I have to check whether the source items are valid first and want to return the row of any error. At first-glance, I want to get the index into the enumerator of the object at the Current property, however, as I am copying these elements, I implicitly know the current index anyway from the current destination. Obviously it depends on your destination object, but for me it was a List, and most likely it will implement ICollection.

i.e.

var destinationList = new List<someObject>();
foreach (var item in itemList)
{
  var stringArray = item.Split(new char[] { ';', ',' }, StringSplitOptions.RemoveEmptyEntries);

  if (stringArray.Length != 2)
  {
    //use the destinationList Count property to give us the index into the stringArray list
    throw new Exception("Item at row " + (destinationList.Count + 1) + " has a problem.");
  }
  else
  {
    destinationList.Add(new someObject() { Prop1 = stringArray[0], Prop2 = stringArray[1]});
  }
}

我认为，虽然不总是适用，但常常足以值得一提。

不管怎样，关键是有时在你的逻辑中已经有了一个不明显的解决方案……

我对这个问题的解决方案是一个扩展方法WithIndex()，

http://code.google.com/p/ub-dotnet-utilities/source/browse/trunk/Src/Utilities/Extensions/EnumerableExtensions.cs

像这样使用它

var list = new List<int> { 1, 2, 3, 4, 5, 6 };    

var odd = list.WithIndex().Where(i => (i.Item & 1) == 1);
CollectionAssert.AreEqual(new[] { 0, 2, 4 }, odd.Select(i => i.Index));
CollectionAssert.AreEqual(new[] { 1, 3, 5 }, odd.Select(i => i.Item));

只需添加自己的索引。保持简单。

int i = -1;
foreach (var item in Collection)
{
    ++i;
    item.index = i;
}

我就是这么做的，这很简单，但如果你在循环body obj中做了很多。价值，它很快就会过时。

foreach(var obj in collection.Select((item, index) => new { Index = index, Value = item }) {
    string foo = string.Format("Something[{0}] = {1}", obj.Index, obj.Value);
    ...
}