我将此字符串存储在变量中：
IN="bla@some.com;john@home.com"
现在，我想将字符串拆分为：；分隔符，以便我可以：
ADDR1="bla@some.com"
ADDR2="john@home.com"
我不一定需要ADDR1和ADDR2变量。如果它们是数组的元素，那就更好了。
根据以下答案的建议，我最终得出了以下结论，这就是我想要的：
#!/usr/bin/env bash
IN="bla@some.com;john@home.com"
mails=$(echo $IN | tr ";" "\n")
for addr in $mails
do
echo "> [$addr]"
done
输出：
> [bla@some.com]
> [john@home.com]
有一个解决方案涉及将Internal_field_separator（IFS）设置为；。我不确定这个答案发生了什么，如何将IFS重置为默认值？
回复：IFS解决方案，我尝试了这个，它奏效了，我保留了旧的IFS，然后恢复它：
IN="bla@some.com;john@home.com"
OIFS=$IFS
IFS=';'
mails2=$IN
for x in $mails2
do
echo "> [$x]"
done
IFS=$OIFS
顺便说一下，当我尝试
mails2=($IN)
在循环中打印时，我只得到了第一个字符串，$in周围没有括号，它可以工作。
除了已经提供的精彩答案之外，如果只是打印数据的问题，您可以考虑使用awk：
awk -F";" '{for (i=1;i<=NF;i++) printf("> [%s]\n", $i)}' <<< "$IN"
这将字段分隔符设置为；，以便它可以用for循环遍历字段并相应地打印。
Test
$ IN="bla@some.com;john@home.com"
$ awk -F";" '{for (i=1;i<=NF;i++) printf("> [%s]\n", $i)}' <<< "$IN"
> [bla@some.com]
> [john@home.com]
使用另一个输入：
$ awk -F";" '{for (i=1;i<=NF;i++) printf("> [%s]\n", $i)}' <<< "a;b;c d;e_;f"
> [a]
> [b]
> [c d]
> [e_]
> [f]
编辑：对不起，我在SO上读到POSIX需要perl，所以我认为使用它是合法的。但在unix.stackexchange.com上，一些用户表示perl不是POSIX规范的一部分。
我的解决方案：一个使用perl的拆分来完成工作的函数。
详细评论如下：
#!/bin/bash
# This function is a wrapper for Perl's split.\
# \
# Since we cannot return an array like in Perl,
# it takes the name of the resulting array as last
# argument.\
# \
# See https://perldoc.perl.org/functions/split for usage info
# and examples.\
# \
# If you provide a Perl regexp that contains e. g. an escaped token like \b,
# space(s) and/or capture group(s), it must be quoted, and e. g. /\b/ must
# be single-quoted.\
# Thus, it's best to generally single-quote a Perl regexp.
function split # Args: <Element separator regexp> <string> <array name>
{
(($# != 3)) && echo "${FUNCNAME[0]}: Wrong number of arguments, returning." && return 1
local elementSepRE=$1
local string=$2
local -n array=$3
local element i=0
# Attention! read does Word Splitting on each line!
# I must admit I didn't know that so far.
# This removes leading and trailing spaces, exactly
# what we don't want.
# Thus, we set IFS locally to newline only.
local IFS=$'\n'
while read element; do
# As opposed to array+=($element),
# this preserves leading and trailing spaces.
array[i++]=$element
done <<<$(_perl_split)
}
# This function calls Perl's split function and prints the elements of the
# resulting array on separate lines.\
# It uses the caller's $elementSepRE and $string.
function _perl_split
{
# A heredoc is a great way of embedding a Perl script.
# N.B.: - Shell variables get expanded.
# - Thus:
# - They must be quoted.
# - Perl scalar variables must be escaped.
# - The backslash of \n must be escaped to protect it.
# - Instead of redirecting a single heredoc to perl, we may
# use multiple heredocs with cat within a command group and
# pipe the result to perl.
# This enables us to conditionally add certain lines of code.
{
cat <<-END
my \$elementSepRE=q($elementSepRE);
END
# If $elementSepRE is a literal Perl regexp, qr must be applied
# to it in order to use it.
# N.B.: We cannot write this condition in Perl because when perl
# compiles the script, all statements are checked for validity,
# no matter if they will actually be executed or not.
# And if $elementSepRE was e. g. == ', the line below – although
# not to be executed – would give an error because of an unterminated
# single-quoted string.
[[ $elementSepRE =~ ^m?/ && $elementSepRE =~ /[msixpodualn]*$ ]] && cat <<-END
\$elementSepRE=qr$elementSepRE;
END
cat <<-END
my @array=split(\$elementSepRE, q($string));
print(\$_ . "\\n") for (@array);
END
} | perl
}
对于那些一眼就知道发生了什么的人来说，这一点没有任何评论；）
#!/bin/bash
# This function is a wrapper for Perl's split.\
# \
# Since we cannot return an array like in Perl,
# it takes the name of the resulting array as last
# argument.\
# \
# See https://perldoc.perl.org/functions/split for usage info
# and examples.\
# \
# If you provide a Perl regexp that contains e. g. an escaped token like \b,
# space(s) and/or capture group(s), it must be quoted, and e. g. /\b/ must
# be single-quoted.\
# Thus, it's best to generally single-quote a Perl regexp.
function split # Args: <Element separator regexp> <string> <array name>
{
(($# != 3)) && echo "${FUNCNAME[0]}: Wrong number of arguments, returning." && return 1
local elementSepRE=$1
local string=$2
local -n array=$3
local element i=0
local IFS=$'\n'
while read element; do
array[i++]=$element
done <<<$(_perl_split)
}
function _perl_split
{
{
cat <<-END
my \$elementSepRE=q($elementSepRE);
END
[[ $elementSepRE =~ ^m?/ && $elementSepRE =~ /[msixpodualn]*$ ]] && cat <<-END
\$elementSepRE=qr$elementSepRE;
END
cat <<-END
my @array=split(\$elementSepRE, q($string));
print(\$_ . "\\n") for (@array);
END
} | perl
}
在Bash中，这是一种防弹的方式，即使您的变量包含换行符，也可以使用：
IFS=';' read -d '' -ra array < <(printf '%s;\0' "$in")
看：
$ in=$'one;two three;*;there is\na newline\nin this field'
$ IFS=';' read -d '' -ra array < <(printf '%s;\0' "$in")
$ declare -p array
declare -a array='([0]="one" [1]="two three" [2]="*" [3]="there is
a newline
in this field")'
这项工作的诀窍是使用带有空分隔符的-d选项read（delimiter），这样read就被迫读取它所输入的所有内容。而且，由于printf，我们将read与中变量的内容完全匹配，没有换行符。注意，我们还在printf中放置分隔符，以确保传递给读取的字符串具有尾随分隔符。如果没有它，read将删除可能的尾随空字段：
$ in='one;two;three;' # there's an empty field
$ IFS=';' read -d '' -ra array < <(printf '%s;\0' "$in")
$ declare -p array
declare -a array='([0]="one" [1]="two" [2]="three" [3]="")'
保留后面的空字段。
Bash≥4.4的更新
从Bash 4.4开始，内置映射文件（也称为readarray）支持-d选项来指定分隔符。因此，另一种规范方法是：
mapfile -d ';' -t array < <(printf '%s;' "$in")
