我想根据谓词筛选java.util.Collection。
当前回答
JFilter http://code.google.com/p/jfilter/最适合您的需求。
JFilter是一个简单、高性能的开源库,用于查询Java bean集合。
关键特性
Support of collection (java.util.Collection, java.util.Map and Array) properties. Support of collection inside collection of any depth. Support of inner queries. Support of parameterized queries. Can filter 1 million records in few 100 ms. Filter ( query) is given in simple json format, it is like Mangodb queries. Following are some examples. { "id":{"$le":"10"} where object id property is less than equals to 10. { "id": {"$in":["0", "100"]}} where object id property is 0 or 100. {"lineItems":{"lineAmount":"1"}} where lineItems collection property of parameterized type has lineAmount equals to 1. { "$and":[{"id": "0"}, {"billingAddress":{"city":"DEL"}}]} where id property is 0 and billingAddress.city property is DEL. {"lineItems":{"taxes":{ "key":{"code":"GST"}, "value":{"$gt": "1.01"}}}} where lineItems collection property of parameterized type which has taxes map type property of parameteriszed type has code equals to GST value greater than 1.01. {'$or':[{'code':'10'},{'skus': {'$and':[{'price':{'$in':['20', '40']}}, {'code':'RedApple'}]}}]} Select all products where product code is 10 or sku price in 20 and 40 and sku code is "RedApple".
其他回答
让我们看看如何使用Eclipse Collections筛选内置JDK List和MutableList。
List<Integer> jdkList = Arrays.asList(1, 2, 3, 4, 5);
MutableList<Integer> ecList = Lists.mutable.with(1, 2, 3, 4, 5);
如果希望过滤小于3的数字,则会得到以下输出。
List<Integer> selected = Lists.mutable.with(1, 2);
List<Integer> rejected = Lists.mutable.with(3, 4, 5);
下面介绍如何使用Java 8 lambda作为Predicate进行筛选。
Assert.assertEquals(selected, Iterate.select(jdkList, each -> each < 3));
Assert.assertEquals(rejected, Iterate.reject(jdkList, each -> each < 3));
Assert.assertEquals(selected, ecList.select(each -> each < 3));
Assert.assertEquals(rejected, ecList.reject(each -> each < 3));
下面介绍如何使用匿名内部类作为Predicate进行筛选。
Predicate<Integer> lessThan3 = new Predicate<Integer>()
{
public boolean accept(Integer each)
{
return each < 3;
}
};
Assert.assertEquals(selected, Iterate.select(jdkList, lessThan3));
Assert.assertEquals(selected, ecList.select(lessThan3));
下面是一些使用Predicates工厂过滤JDK列表和Eclipse Collections mutabllists的替代方案。
Assert.assertEquals(selected, Iterate.select(jdkList, Predicates.lessThan(3)));
Assert.assertEquals(selected, ecList.select(Predicates.lessThan(3)));
下面是一个不为谓词分配对象的版本,而是使用Predicates2工厂,并使用selectWith方法接受Predicate2。
Assert.assertEquals(
selected, ecList.selectWith(Predicates2.<Integer>lessThan(), 3));
有时你想过滤一个消极的条件。在Eclipse Collections中有一个特殊的方法叫做reject。
Assert.assertEquals(rejected, Iterate.reject(jdkList, lessThan3));
Assert.assertEquals(rejected, ecList.reject(lessThan3));
方法分区将返回两个集合,包含Predicate选择和拒绝的元素。
PartitionIterable<Integer> jdkPartitioned = Iterate.partition(jdkList, lessThan3);
Assert.assertEquals(selected, jdkPartitioned.getSelected());
Assert.assertEquals(rejected, jdkPartitioned.getRejected());
PartitionList<Integer> ecPartitioned = gscList.partition(lessThan3);
Assert.assertEquals(selected, ecPartitioned.getSelected());
Assert.assertEquals(rejected, ecPartitioned.getRejected());
注意:我是Eclipse Collections的提交者。
这里有一些非常棒的答案。对我来说,我想让事情尽可能简单易懂:
public abstract class AbstractFilter<T> {
/**
* Method that returns whether an item is to be included or not.
* @param item an item from the given collection.
* @return true if this item is to be included in the collection, false in case it has to be removed.
*/
protected abstract boolean excludeItem(T item);
public void filter(Collection<T> collection) {
if (CollectionUtils.isNotEmpty(collection)) {
Iterator<T> iterator = collection.iterator();
while (iterator.hasNext()) {
if (excludeItem(iterator.next())) {
iterator.remove();
}
}
}
}
}
我的回答建立在Kevin Wong的基础上,这里是一个使用spring中的CollectionUtils和Java 8 lambda表达式的一行程序。
CollectionUtils.filter(list, p -> ((Person) p).getAge() > 16);
这是我见过的最简洁易读的方法(不使用基于方面的库)。
Spring CollectionUtils可从Spring版本4.0.2获得。请记住,您需要JDK 1.8和语言级别8+。
设置:
public interface Predicate<T> {
public boolean filter(T t);
}
void filterCollection(Collection<T> col, Predicate<T> predicate) {
for (Iterator i = col.iterator(); i.hasNext();) {
T obj = i.next();
if (predicate.filter(obj)) {
i.remove();
}
}
}
的用法:
List<MyObject> myList = ...;
filterCollection(myList, new Predicate<MyObject>() {
public boolean filter(MyObject obj) {
return obj.shouldFilter();
}
});
您确定要筛选Collection本身,而不是迭代器吗?
看到org.apache.commons.collections.iterators.FilterIterator
或者使用apache commons的第四版org.apache.commons.collections4.iterators.FilterIterator
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