我想知道__init__和__call__方法之间的区别。

例如:

class test:

  def __init__(self):
    self.a = 10

  def __call__(self): 
    b = 20

当前回答

__call__使类的实例可调用。 为什么需要它?

从技术上讲,__init__在对象创建时由__new__调用一次,以便可以初始化它。

但是在许多情况下,您可能想要重新定义对象,例如您已经完成了对象,并且可能发现需要一个新对象。使用__call__,你可以重新定义相同的对象,就像它是新的一样。

这只是一个案例,可能还有更多。

其他回答

我们可以使用调用方法来使用其他类方法作为静态方法。

class _Callable:
    def __init__(self, anycallable):
        self.__call__ = anycallable

class Model:

    def get_instance(conn, table_name):

        """ do something"""

    get_instance = _Callable(get_instance)

provs_fac = Model.get_instance(connection, "users")  

方法用于使对象像函数一样工作。

>>> class A:
...     def __init__(self):
...         print "From init ... "
... 
>>> a = A()
From init ... 
>>> a()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: A instance has no __call__ method

<*There is no __call__ method so it doesn't act like function and throws error.*>

>>> 
>>> class B:
...     def __init__(self):
...         print "From init ... "
...     def __call__(self):
...         print "From call it is a function ... "
... 
>>> b = B()
From init ... 
>>> b()
From call it is a function... 
>>> 

<* __call__ method made object "b" to act like function *>

我们也可以把它传递给一个类变量。

class B:
    a = A()
    def __init__(self):
       print "From init ... "

定义自定义__call__()方法允许将类的实例作为函数调用,而不总是修改实例本身。

In [1]: class A:
   ...:     def __init__(self):
   ...:         print "init"
   ...:         
   ...:     def __call__(self):
   ...:         print "call"
   ...:         
   ...:         

In [2]: a = A()
init

In [3]: a()
call

因此,当你创建任何类的实例并初始化实例变量时,__init__也会被调用。

例子:

class User:

    def __init__(self,first_n,last_n,age):
        self.first_n = first_n
        self.last_n = last_n
        self.age = age

user1 = User("Jhone","Wrick","40")

当你像调用其他函数一样调用对象时,会调用__call__。

例子:

class USER:
    def __call__(self,arg):
        "todo here"
         print(f"I am in __call__ with arg : {arg} ")


user1=USER()
user1("One") #calling the object user1 and that's gonna call __call__ dunder functions

我将尝试用一个例子来解释这一点,假设您想从斐波那契数列中输出固定数量的项。记住斐波那契数列的前两项都是1。例:1,1,2,3,5,8,13 ....

您希望包含斐波那契数的列表只初始化一次,然后更新。现在我们可以使用__call__函数了。阅读@mudit verma的回答。这就像你希望对象作为函数可调用,但不是每次调用时都重新初始化。

Eg:

class Recorder:
    def __init__(self):
        self._weights = []
        for i in range(0, 2):
            self._weights.append(1)
        print self._weights[-1]
        print self._weights[-2]
        print "no. above is from __init__"

    def __call__(self, t):
        self._weights = [self._weights[-1], self._weights[-1] + self._weights[-2]]
        print self._weights[-1]
        print "no. above is from __call__"

weight_recorder = Recorder()
for i in range(0, 10):
    weight_recorder(i)

输出结果为:

1
1
no. above is from __init__
2
no. above is from __call__
3
no. above is from __call__
5
no. above is from __call__
8
no. above is from __call__
13
no. above is from __call__
21
no. above is from __call__
34
no. above is from __call__
55
no. above is from __call__
89
no. above is from __call__
144
no. above is from __call__

如果你观察到输出__init__只被调用了一次,那就是类第一次实例化的时候,后来对象被调用而没有重新初始化。