我想知道__init__和__call__方法之间的区别。

例如:

class test:

  def __init__(self):
    self.a = 10

  def __call__(self): 
    b = 20

当前回答

方法用于使对象像函数一样工作。

>>> class A:
...     def __init__(self):
...         print "From init ... "
... 
>>> a = A()
From init ... 
>>> a()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: A instance has no __call__ method

<*There is no __call__ method so it doesn't act like function and throws error.*>

>>> 
>>> class B:
...     def __init__(self):
...         print "From init ... "
...     def __call__(self):
...         print "From call it is a function ... "
... 
>>> b = B()
From init ... 
>>> b()
From call it is a function... 
>>> 

<* __call__ method made object "b" to act like function *>

我们也可以把它传递给一个类变量。

class B:
    a = A()
    def __init__(self):
       print "From init ... "

其他回答

>>> class A:
...     def __init__(self):
...         print "From init ... "
... 
>>> a = A()
From init ... 
>>> a()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: A instance has no __call__ method
>>> 
>>> class B:
...     def __init__(self):
...         print "From init ... "
...     def __call__(self):
...         print "From call ... "
... 
>>> b = B()
From init ... 
>>> b()
From call ... 
>>> 

定义自定义__call__()方法允许将类的实例作为函数调用,而不总是修改实例本身。

In [1]: class A:
   ...:     def __init__(self):
   ...:         print "init"
   ...:         
   ...:     def __call__(self):
   ...:         print "call"
   ...:         
   ...:         

In [2]: a = A()
init

In [3]: a()
call

__init__是Python类中的一个特殊方法,它是类的构造函数方法。每当构造类的对象时调用它,或者我们可以说它初始化了一个新对象。 例子:

    In [4]: class A:
   ...:     def __init__(self, a):
   ...:         print(a)
   ...:
   ...: a = A(10) # An argument is necessary
10

如果我们使用A(),它会给出一个错误 TypeError: __init__()缺少一个必需的位置参数:'a',因为它需要一个参数a,因为__init__。

……

当在Class中实现__call__时,可以帮助我们将Class实例作为函数调用调用。

例子:

In [6]: class B:
   ...:     def __call__(self,b):
   ...:         print(b)
   ...:
   ...: b = B() # Note we didn't pass any arguments here
   ...: b(20)   # Argument passed when the object is called
   ...:
20

这里如果我们使用B(),它运行得很好,因为它在这里没有__init__函数。

第一个用于初始化新创建的对象,并接收用于初始化的参数:

class Foo:
    def __init__(self, a, b, c):
        # ...

x = Foo(1, 2, 3) # __init__

第二部分实现函数调用操作符。

class Foo:
    def __call__(self, a, b, c):
        # ...

x = Foo()
x(1, 2, 3) # __call__

我将尝试用一个例子来解释这一点,假设您想从斐波那契数列中输出固定数量的项。记住斐波那契数列的前两项都是1。例:1,1,2,3,5,8,13 ....

您希望包含斐波那契数的列表只初始化一次,然后更新。现在我们可以使用__call__函数了。阅读@mudit verma的回答。这就像你希望对象作为函数可调用,但不是每次调用时都重新初始化。

Eg:

class Recorder:
    def __init__(self):
        self._weights = []
        for i in range(0, 2):
            self._weights.append(1)
        print self._weights[-1]
        print self._weights[-2]
        print "no. above is from __init__"

    def __call__(self, t):
        self._weights = [self._weights[-1], self._weights[-1] + self._weights[-2]]
        print self._weights[-1]
        print "no. above is from __call__"

weight_recorder = Recorder()
for i in range(0, 10):
    weight_recorder(i)

输出结果为:

1
1
no. above is from __init__
2
no. above is from __call__
3
no. above is from __call__
5
no. above is from __call__
8
no. above is from __call__
13
no. above is from __call__
21
no. above is from __call__
34
no. above is from __call__
55
no. above is from __call__
89
no. above is from __call__
144
no. above is from __call__

如果你观察到输出__init__只被调用了一次,那就是类第一次实例化的时候,后来对象被调用而没有重新初始化。