是否有一种方法显示所有枚举作为他们的字符串值在swagger而不是他们的int值?

我希望能够提交POST动作,并根据它们的字符串值放置枚举,而不必每次都查看enum。

我尝试了DescribeAllEnumsAsStrings,但服务器然后接收字符串而不是enum值,这不是我们要寻找的。

有人解决了吗?

编辑:

public class Letter 
{
    [Required]
    public string Content {get; set;}

    [Required]
    [EnumDataType(typeof(Priority))]
    public Priority Priority {get; set;}
}


public class LettersController : ApiController
{
    [HttpPost]
    public IHttpActionResult SendLetter(Letter letter)
    {
        // Validation not passing when using DescribeEnumsAsStrings
        if (!ModelState.IsValid)
            return BadRequest("Not valid")

        ..
    }

    // In the documentation for this request I want to see the string values of the enum before submitting: Low, Medium, High. Instead of 0, 1, 2
    [HttpGet]
    public IHttpActionResult GetByPriority (Priority priority)
    {

    }
}


public enum Priority
{
    Low, 
    Medium,
    High
}

当前回答

.Net Core 3.0

   using Newtonsoft.Json.Converters;

 services
    .AddMvc(options =>
    {
     options.EnableEndpointRouting = false;
     })
    .AddNewtonsoftJson(options => options.SerializerSettings.Converters.Add(new StringEnumConverter()))

其他回答

.NET CORE 3.1和SWAGGER 5

如果你需要一个简单的解决方案来选择性地使枚举作为字符串传递:

using System.Text.Json.Serialization;


[JsonConverter(typeof(JsonStringEnumConverter))]
public enum MyEnum
{
    A, B
}

注意,我们使用System.Text.Json.Serialization命名空间,而不是Newtonsoft.Json!

要在swagger中以字符串形式显示枚举,请在ConfigureServices中添加以下行来配置JsonStringEnumConverter:

services.AddControllers().AddJsonOptions(options =>
            options.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()));

如果你想以字符串和int值的形式显示枚举,你可以尝试创建一个EnumSchemaFilter来改变模式,如下所示:

public class EnumSchemaFilter : ISchemaFilter
{
    public void Apply(OpenApiSchema model, SchemaFilterContext context)
    {
        if (context.Type.IsEnum)
        {
            model.Enum.Clear();
            Enum.GetNames(context.Type)
                .ToList()
                .ForEach(name => model.Enum.Add(new OpenApiString($"{Convert.ToInt64(Enum.Parse(context.Type, name))} = {name}")));
        }
    }
}

配置SwaggerGen使用上面的SchemaFilter:

services.AddSwaggerGen(c =>
        {
            c.SwaggerDoc("v1", new OpenApiInfo
            {
                Version = "v1",
                Title = "ToDo API",
                Description = "A simple example ASP.NET Core Web API",
                TermsOfService = new Uri("https://example.com/terms"),
                Contact = new OpenApiContact
                {
                    Name = "Shayne Boyer",
                    Email = string.Empty,
                    Url = new Uri("https://twitter.com/spboyer"),
                },
                License = new OpenApiLicense
                {
                    Name = "Use under LICX",
                    Url = new Uri("https://example.com/license"),
                }
            });
              
            c.SchemaFilter<EnumSchemaFilter>();
        });

我已经修改了Hosam Rehani的答案,以使用可空枚举和枚举的收集。只有当属性的名称与其类型完全一致时,前面的答案才有效。下面的代码解决了所有这些问题。

它适用于。net core 3。X和swagger。

在某些情况下,不搜索enum类型两次会更有效。

class SwaggerAddEnumDescriptions : IDocumentFilter
{
    public void Apply(OpenApiDocument swaggerDoc, DocumentFilterContext context)
    {
        // add enum descriptions to result models
        foreach (var property in swaggerDoc.Components.Schemas.Where(x => x.Value?.Enum?.Count > 0))
        {
            IList<IOpenApiAny> propertyEnums = property.Value.Enum;
            if (propertyEnums != null && propertyEnums.Count > 0)
            {
                property.Value.Description += DescribeEnum(propertyEnums, property.Key);
            }
        }

        // add enum descriptions to input parameters
        foreach (var pathItem in swaggerDoc.Paths)
        {
            DescribeEnumParameters(pathItem.Value.Operations, swaggerDoc, context.ApiDescriptions, pathItem.Key);
        }
    }

    private void DescribeEnumParameters(IDictionary<OperationType, OpenApiOperation> operations, OpenApiDocument swaggerDoc, IEnumerable<ApiDescription> apiDescriptions, string path)
    {
        path = path.Trim('/');
        if (operations != null)
        {
            var pathDescriptions = apiDescriptions.Where(a => a.RelativePath == path);
            foreach (var oper in operations)
            {
                var operationDescription = pathDescriptions.FirstOrDefault(a => a.HttpMethod.Equals(oper.Key.ToString(), StringComparison.InvariantCultureIgnoreCase));
                foreach (var param in oper.Value.Parameters)
                {
                    var parameterDescription = operationDescription.ParameterDescriptions.FirstOrDefault(a => a.Name == param.Name);
                    if (parameterDescription != null && TryGetEnumType(parameterDescription.Type, out Type enumType))
                    {
                        var paramEnum = swaggerDoc.Components.Schemas.FirstOrDefault(x => x.Key == enumType.Name);
                        if (paramEnum.Value != null)
                        {
                            param.Description += DescribeEnum(paramEnum.Value.Enum, paramEnum.Key);
                        }
                    }
                }
            }
        }
    }

    bool TryGetEnumType(Type type, out Type enumType)
    {
        if (type.IsEnum)
        {
            enumType = type;
            return true;
        }
        else if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(Nullable<>))
        {
            var underlyingType = Nullable.GetUnderlyingType(type);
            if (underlyingType != null && underlyingType.IsEnum == true)
            {
                enumType = underlyingType;
                return true;
            }
        }
        else
        {
            Type underlyingType = GetTypeIEnumerableType(type);
            if (underlyingType != null && underlyingType.IsEnum)
            {
                enumType = underlyingType;
                return true;
            }
            else
            {
                var interfaces = type.GetInterfaces();
                foreach (var interfaceType in interfaces)
                {
                    underlyingType = GetTypeIEnumerableType(interfaceType);
                    if (underlyingType != null && underlyingType.IsEnum)
                    {
                        enumType = underlyingType;
                        return true;
                    }
                }
            }
        }

        enumType = null;
        return false;
    }

    Type GetTypeIEnumerableType(Type type)
    {
        if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(IEnumerable<>))
        {
            var underlyingType = type.GetGenericArguments()[0];
            if (underlyingType.IsEnum)
            {
                return underlyingType;
            }
        }

        return null;
    }

    private Type GetEnumTypeByName(string enumTypeName)
    {
        return AppDomain.CurrentDomain
            .GetAssemblies()
            .SelectMany(x => x.GetTypes())
            .FirstOrDefault(x => x.Name == enumTypeName);
    }

    private string DescribeEnum(IList<IOpenApiAny> enums, string proprtyTypeName)
    {
        List<string> enumDescriptions = new List<string>();
        var enumType = GetEnumTypeByName(proprtyTypeName);
        if (enumType == null)
            return null;

        foreach (OpenApiInteger enumOption in enums)
        {
            int enumInt = enumOption.Value;

            enumDescriptions.Add(string.Format("{0} = {1}", enumInt, Enum.GetName(enumType, enumInt)));
        }

        return string.Join(", ", enumDescriptions.ToArray());
    }
}

添加c.DocumentFilter< swaggeraddenumdescripts> ();在Startup.cs中配置。

asp.net core 3

using System.Text.Json.Serialization;

public class Startup
{
    public void ConfigureServices(IServiceCollection services)
    {
         services.AddControllers().AddJsonOptions(options =>
             options.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()));

但是Swashbuckle Version 5.0.0-rc4似乎还没有准备好支持这个功能。所以我们需要在Swashbuckle配置文件中使用一个选项(已弃用),直到它像Newtonsoft库一样支持和反映它。

public void ConfigureServices(IServiceCollection services)
{ 
      services.AddSwaggerGen(c =>
      {
            c.DescribeAllEnumsAsStrings();

这个答案和其他答案之间的区别是只使用Microsoft JSON库而不是Newtonsoft。

如果你使用牛顿。Json然后使用这个

using Newtonsoft.Json.Converters;


[JsonConverter(typeof(StringEnumConverter))]
public enum MyEnum
{
    A, B
}

如果你正在使用System.Text.Json.Serialization

using System.Text.Json.Serialization;


[JsonConverter(typeof(JsonStringEnumConverter))]
public enum MyEnum
{
    A, B
}