是否有一种方法显示所有枚举作为他们的字符串值在swagger而不是他们的int值?
我希望能够提交POST动作，并根据它们的字符串值放置枚举，而不必每次都查看enum。
我尝试了DescribeAllEnumsAsStrings，但服务器然后接收字符串而不是enum值，这不是我们要寻找的。
有人解决了吗?
编辑:
public class Letter
{
[Required]
public string Content {get; set;}
[Required]
[EnumDataType(typeof(Priority))]
public Priority Priority {get; set;}
}
public class LettersController : ApiController
{
[HttpPost]
public IHttpActionResult SendLetter(Letter letter)
{
// Validation not passing when using DescribeEnumsAsStrings
if (!ModelState.IsValid)
return BadRequest("Not valid")
..
}
// In the documentation for this request I want to see the string values of the enum before submitting: Low, Medium, High. Instead of 0, 1, 2
[HttpGet]
public IHttpActionResult GetByPriority (Priority priority)
{
}
}
public enum Priority
{
Low,
Medium,
High
}
在。net 6与NSwag和System.Text.Json为我工作:
services.AddControllersWithViews()
.AddJsonOptions(o => o.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()))
and
services.AddOpenApiDocument(configure =>
{
...
configure.GenerateEnumMappingDescription = true;
});
它接受int-s和字符串，在open-api和.ts客户端生成带有名称的枚举，并在SwaggerUI中显示带有名称的枚举
export enum PaymentDirection {
Input = "Input",
Output = "Output",
}
为了生成有名称和值的枚举，可以使用此解决方案。
先决条件:
你正在使用NSwag或Openapi-generator来生成API客户端
你有一个旧的Web Api项目(pre . net Core)并使用Swashbuckle。WebApi包
SchemaFilter登记:
GlobalConfiguration.Configuration
.EnableSwagger("/swagger", c =>
{
c.SchemaFilter<EnumSchemaFilter>();
});
EnumSchemaFilter:
public class EnumSchemaFilter : ISchemaFilter
{
public void Apply(Schema schema, SchemaRegistry schemaRegistry, Type type)
{
var enumProperties = schema.properties?.Where(p => p.Value.@enum != null);
if(enumProperties != null)
{
foreach (var property in enumProperties)
{
var array = Enum.GetNames(type.GetProperty(property.Key).PropertyType).ToArray();
property.Value.vendorExtensions.Add("x-enumNames", array); // NSwag
property.Value.vendorExtensions.Add("x-enum-varnames", array); // Openapi-generator
}
}
}
}
在。net 6与NSwag和System.Text.Json为我工作:
services.AddControllersWithViews()
.AddJsonOptions(o => o.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()))
and
services.AddOpenApiDocument(configure =>
{
...
configure.GenerateEnumMappingDescription = true;
});
它接受int-s和字符串，在open-api和.ts客户端生成带有名称的枚举，并在SwaggerUI中显示带有名称的枚举
export enum PaymentDirection {
Input = "Input",
Output = "Output",
}
asp.net core 3
using System.Text.Json.Serialization;
public class Startup
{
public void ConfigureServices(IServiceCollection services)
{
services.AddControllers().AddJsonOptions(options =>
options.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()));
但是Swashbuckle Version 5.0.0-rc4似乎还没有准备好支持这个功能。所以我们需要在Swashbuckle配置文件中使用一个选项(已弃用)，直到它像Newtonsoft库一样支持和反映它。
public void ConfigureServices(IServiceCollection services)
{
services.AddSwaggerGen(c =>
{
c.DescribeAllEnumsAsStrings();
这个答案和其他答案之间的区别是只使用Microsoft JSON库而不是Newtonsoft。
如果有人感兴趣，我已经修改了代码的工作
.NET CORE 3和Swagger V5
public class SwaggerAddEnumDescriptions : IDocumentFilter
{
public void Apply(OpenApiDocument swaggerDoc, DocumentFilterContext context)
{
// add enum descriptions to result models
foreach (var property in swaggerDoc.Components.Schemas.Where(x => x.Value?.Enum?.Count > 0))
{
IList<IOpenApiAny> propertyEnums = property.Value.Enum;
if (propertyEnums != null && propertyEnums.Count > 0)
{
property.Value.Description += DescribeEnum(propertyEnums, property.Key);
}
}
// add enum descriptions to input parameters
foreach (var pathItem in swaggerDoc.Paths.Values)
{
DescribeEnumParameters(pathItem.Operations, swaggerDoc);
}
}
private void DescribeEnumParameters(IDictionary<OperationType, OpenApiOperation> operations, OpenApiDocument swaggerDoc)
{
if (operations != null)
{
foreach (var oper in operations)
{
foreach (var param in oper.Value.Parameters)
{
var paramEnum = swaggerDoc.Components.Schemas.FirstOrDefault(x => x.Key == param.Name);
if (paramEnum.Value != null)
{
param.Description += DescribeEnum(paramEnum.Value.Enum, paramEnum.Key);
}
}
}
}
}
private Type GetEnumTypeByName(string enumTypeName)
{
return AppDomain.CurrentDomain
.GetAssemblies()
.SelectMany(x => x.GetTypes())
.FirstOrDefault(x => x.Name == enumTypeName);
}
private string DescribeEnum(IList<IOpenApiAny> enums, string proprtyTypeName)
{
List<string> enumDescriptions = new List<string>();
var enumType = GetEnumTypeByName(proprtyTypeName);
if (enumType == null)
return null;
foreach (IOpenApiAny enumOption in enums)
{
if (enumOption is OpenApiString @string)
{
string enumString = @string.Value;
enumDescriptions.Add(string.Format("{0} = {1}", (int)Enum.Parse(enumType, enumString), enumString));
}
else if (enumOption is OpenApiInteger integer)
{
int enumInt = integer.Value;
enumDescriptions.Add(string.Format("{0} = {1}", enumInt, Enum.GetName(enumType, enumInt)));
}
}
return string.Join(", ", enumDescriptions.ToArray());
}
}
