是否有一种方法显示所有枚举作为他们的字符串值在swagger而不是他们的int值?
我希望能够提交POST动作，并根据它们的字符串值放置枚举，而不必每次都查看enum。
我尝试了DescribeAllEnumsAsStrings，但服务器然后接收字符串而不是enum值，这不是我们要寻找的。
有人解决了吗?
编辑:
public class Letter
{
[Required]
public string Content {get; set;}
[Required]
[EnumDataType(typeof(Priority))]
public Priority Priority {get; set;}
}
public class LettersController : ApiController
{
[HttpPost]
public IHttpActionResult SendLetter(Letter letter)
{
// Validation not passing when using DescribeEnumsAsStrings
if (!ModelState.IsValid)
return BadRequest("Not valid")
..
}
// In the documentation for this request I want to see the string values of the enum before submitting: Low, Medium, High. Instead of 0, 1, 2
[HttpGet]
public IHttpActionResult GetByPriority (Priority priority)
{
}
}
public enum Priority
{
Low,
Medium,
High
}
要在swagger中以字符串形式显示枚举，请在ConfigureServices中添加以下行来配置JsonStringEnumConverter:
services.AddControllers().AddJsonOptions(options =>
options.JsonSerializerOptions.Converters.Add(new JsonStringEnumConverter()));
如果你想以字符串和int值的形式显示枚举，你可以尝试创建一个EnumSchemaFilter来改变模式，如下所示:
public class EnumSchemaFilter : ISchemaFilter
{
public void Apply(OpenApiSchema model, SchemaFilterContext context)
{
if (context.Type.IsEnum)
{
model.Enum.Clear();
Enum.GetNames(context.Type)
.ToList()
.ForEach(name => model.Enum.Add(new OpenApiString($"{Convert.ToInt64(Enum.Parse(context.Type, name))} = {name}")));
}
}
}
配置SwaggerGen使用上面的SchemaFilter:
services.AddSwaggerGen(c =>
{
c.SwaggerDoc("v1", new OpenApiInfo
{
Version = "v1",
Title = "ToDo API",
Description = "A simple example ASP.NET Core Web API",
TermsOfService = new Uri("https://example.com/terms"),
Contact = new OpenApiContact
{
Name = "Shayne Boyer",
Email = string.Empty,
Url = new Uri("https://twitter.com/spboyer"),
},
License = new OpenApiLicense
{
Name = "Use under LICX",
Url = new Uri("https://example.com/license"),
}
});
c.SchemaFilter<EnumSchemaFilter>();
});
在这里搜索答案后，我发现了在模式中显示枚举的问题的部分解决方案[SomeEnumString = 0, AnotherEnumString = 1]，但与此相关的所有答案都只是部分正确的，正如@OhWelp在其中一个评论中提到的那样。
下面是。net core的完整解决方案(2、3，目前在6上工作):
public class EnumSchemaFilter : ISchemaFilter
{
public void Apply(OpenApiSchema model, SchemaFilterContext context)
{
if (context.Type.IsEnum)
{
model.Enum.Clear();
var names = Enum.GetNames(context.Type).ToList();
names.ForEach(name => model.Enum.Add(new OpenApiString($"{GetEnumIntegerValue(name, context)} = {name}")));
// the missing piece that will make sure that the new schema will not replace the mock value with a wrong value
// this is the default behavior - the first possible enum value as a default "example" value
model.Example = new OpenApiInteger(GetEnumIntegerValue(names.First(), context));
}
}
private int GetEnumIntegerValue(string name, SchemaFilterContext context) => Convert.ToInt32(Enum.Parse(context.Type, name));
}
在启动/程序中:
services.AddSwaggerGen(options =>
{
options.SchemaFilter<EnumSchemaFilter>();
});
编辑:对代码进行了一些重构，如果你想看到原始版本，它与其余的答案更相似，请检查编辑的年表。
为了生成有名称和值的枚举，可以使用此解决方案。
先决条件:
你正在使用NSwag或Openapi-generator来生成API客户端
你有一个旧的Web Api项目(pre . net Core)并使用Swashbuckle。WebApi包
SchemaFilter登记:
GlobalConfiguration.Configuration
.EnableSwagger("/swagger", c =>
{
c.SchemaFilter<EnumSchemaFilter>();
});
EnumSchemaFilter:
public class EnumSchemaFilter : ISchemaFilter
{
public void Apply(Schema schema, SchemaRegistry schemaRegistry, Type type)
{
var enumProperties = schema.properties?.Where(p => p.Value.@enum != null);
if(enumProperties != null)
{
foreach (var property in enumProperties)
{
var array = Enum.GetNames(type.GetProperty(property.Key).PropertyType).ToArray();
property.Value.vendorExtensions.Add("x-enumNames", array); // NSwag
property.Value.vendorExtensions.Add("x-enum-varnames", array); // Openapi-generator
}
}
}
}
我想在. net Core应用程序中使用rory_za的答案，但我必须对其进行一些修改才能使其工作。下面是我为。net Core设计的实现。
我还修改了它，这样它就不会假设底层类型是int，并在值之间使用了新的行，以便于阅读。
/// <summary>
/// Add enum value descriptions to Swagger
/// </summary>
public class EnumDocumentFilter : IDocumentFilter {
/// <inheritdoc />
public void Apply(SwaggerDocument swaggerDoc, DocumentFilterContext context) {
// add enum descriptions to result models
foreach (var schemaDictionaryItem in swaggerDoc.Definitions) {
var schema = schemaDictionaryItem.Value;
foreach (var propertyDictionaryItem in schema.Properties) {
var property = propertyDictionaryItem.Value;
var propertyEnums = property.Enum;
if (propertyEnums != null && propertyEnums.Count > 0) {
property.Description += DescribeEnum(propertyEnums);
}
}
}
if (swaggerDoc.Paths.Count <= 0) return;
// add enum descriptions to input parameters
foreach (var pathItem in swaggerDoc.Paths.Values) {
DescribeEnumParameters(pathItem.Parameters);
// head, patch, options, delete left out
var possibleParameterisedOperations = new List<Operation> {pathItem.Get, pathItem.Post, pathItem.Put};
possibleParameterisedOperations.FindAll(x => x != null)
.ForEach(x => DescribeEnumParameters(x.Parameters));
}
}
private static void DescribeEnumParameters(IList<IParameter> parameters) {
if (parameters == null) return;
foreach (var param in parameters) {
if (param is NonBodyParameter nbParam && nbParam.Enum?.Any() == true) {
param.Description += DescribeEnum(nbParam.Enum);
} else if (param.Extensions.ContainsKey("enum") && param.Extensions["enum"] is IList<object> paramEnums &&
paramEnums.Count > 0) {
param.Description += DescribeEnum(paramEnums);
}
}
}
private static string DescribeEnum(IEnumerable<object> enums) {
var enumDescriptions = new List<string>();
Type type = null;
foreach (var enumOption in enums) {
if (type == null) type = enumOption.GetType();
enumDescriptions.Add($"{Convert.ChangeType(enumOption, type.GetEnumUnderlyingType())} = {Enum.GetName(type, enumOption)}");
}
return $"{Environment.NewLine}{string.Join(Environment.NewLine, enumDescriptions)}";
}
}
然后将它添加到Startup.cs中的ConfigureServices方法中:
c.DocumentFilter<EnumDocumentFilter>();
