我正在开发一个应用程序在Android操作系统。我不知道如何检查位置服务是否启用。
我需要一个方法,如果它们被启用,返回“true”,如果没有“false”(所以在最后一种情况下,我可以显示一个对话框来启用它们)。
我正在开发一个应用程序在Android操作系统。我不知道如何检查位置服务是否启用。
我需要一个方法,如果它们被启用,返回“true”,如果没有“false”(所以在最后一种情况下,我可以显示一个对话框来启用它们)。
当前回答
private boolean isGpsEnabled()
{
LocationManager service = (LocationManager) getSystemService(LOCATION_SERVICE);
return service.isProviderEnabled(LocationManager.GPS_PROVIDER)&&service.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
}
其他回答
是的,你可以检查以下是代码:
public boolean isGPSEnabled(Context mContext)
{
LocationManager lm = (LocationManager)
mContext.getSystemService(Context.LOCATION_SERVICE);
return lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
}
在manifest文件中的权限下:
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
你可以请求位置更新并同时显示对话框,就像GoogleMaps一样。代码如下:
googleApiClient = new GoogleApiClient.Builder(getActivity())
.addApi(LocationServices.API)
.addConnectionCallbacks(this)
.addOnConnectionFailedListener(this).build();
googleApiClient.connect();
LocationRequest locationRequest = LocationRequest.create();
locationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
locationRequest.setInterval(30 * 1000);
locationRequest.setFastestInterval(5 * 1000);
LocationSettingsRequest.Builder builder = new LocationSettingsRequest.Builder()
.addLocationRequest(locationRequest);
builder.setAlwaysShow(true); //this is the key ingredient
PendingResult<LocationSettingsResult> result = LocationServices.SettingsApi.checkLocationSettings(googleApiClient, builder.build());
result.setResultCallback(new ResultCallback<LocationSettingsResult>() {
@Override
public void onResult(LocationSettingsResult result) {
final Status status = result.getStatus();
final LocationSettingsStates state = result.getLocationSettingsStates();
switch (status.getStatusCode()) {
case LocationSettingsStatusCodes.SUCCESS:
// All location settings are satisfied. The client can initialize location
// requests here.
break;
case LocationSettingsStatusCodes.RESOLUTION_REQUIRED:
// Location settings are not satisfied. But could be fixed by showing the user
// a dialog.
try {
// Show the dialog by calling startResolutionForResult(),
// and check the result in onActivityResult().
status.startResolutionForResult(getActivity(), 1000);
} catch (IntentSender.SendIntentException ignored) {}
break;
case LocationSettingsStatusCodes.SETTINGS_CHANGE_UNAVAILABLE:
// Location settings are not satisfied. However, we have no way to fix the
// settings so we won't show the dialog.
break;
}
}
});
}
如果需要更多信息,请检查LocationRequest类。
到2020年
最近,最好和最短的方法是
@SuppressWarnings("deprecation")
public static Boolean isLocationEnabled(Context context) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
// This is a new method provided in API 28
LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
return lm.isLocationEnabled();
} else {
// This was deprecated in API 28
int mode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
Settings.Secure.LOCATION_MODE_OFF);
return (mode != Settings.Secure.LOCATION_MODE_OFF);
}
}
您可以使用此代码引导用户到设置,在那里他们可以启用GPS:
locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
if( !locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) ) {
new AlertDialog.Builder(context)
.setTitle(R.string.gps_not_found_title) // GPS not found
.setMessage(R.string.gps_not_found_message) // Want to enable?
.setPositiveButton(R.string.yes, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialogInterface, int i) {
owner.startActivity(new Intent(android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS));
}
})
.setNegativeButton(R.string.no, null)
.show();
}
这是一个非常有用的方法,如果启用了Location服务,它将返回“true”:
public static boolean locationServicesEnabled(Context context) {
LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
boolean gps_enabled = false;
boolean net_enabled = false;
try {
gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
} catch (Exception ex) {
Log.e(TAG,"Exception gps_enabled");
}
try {
net_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
} catch (Exception ex) {
Log.e(TAG,"Exception network_enabled");
}
return gps_enabled || net_enabled;
}