迁移到AndroidX并使用

implementation 'androidx.appcompat:appcompat:1.3.0'

并使用LocationManagerCompat

在Java中

private boolean isLocationEnabled(Context context) {
    LocationManager locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    return LocationManagerCompat.isLocationEnabled(locationManager);
}

在Kotlin

private fun isLocationEnabled(context: Context): Boolean {
    val locationManager = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return LocationManagerCompat.isLocationEnabled(locationManager)
}

如果你正在使用AndroidX，使用下面的代码来检查位置服务是否启用:

fun isNetworkServiceEnabled(context: Context) = LocationManagerCompat.isLocationEnabled(context.getSystemService(LocationManager::class.java))

如果没有启用任何提供程序，则“passive”是返回的最佳提供程序。 参见https://stackoverflow.com/a/4519414/621690

    public boolean isLocationServiceEnabled() {
        LocationManager lm = (LocationManager)
                this.getSystemService(Context.LOCATION_SERVICE);
        String provider = lm.getBestProvider(new Criteria(), true);
        return (StringUtils.isNotBlank(provider) &&
                !LocationManager.PASSIVE_PROVIDER.equals(provider));
    }

    LocationManager lm = (LocationManager)this.getSystemService(Context.LOCATION_SERVICE);
    boolean gps_enabled = false;
    boolean network_enabled = false;

    try {
        gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
    } catch(Exception e){
         e.printStackTrace();
    }

    try {
        network_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
    } catch(Exception e){
         e.printStackTrace();
    }

    if(!gps_enabled && !network_enabled) {
        // notify user
        new AlertDialog.Builder(this)
                .setMessage("Please turn on Location to continue")
                .setPositiveButton("Open Location Settings", new DialogInterface.OnClickListener() {
                    @Override
                    public void onClick(DialogInterface paramDialogInterface, int paramInt) {
                        startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                    }

                }).
                setNegativeButton("Cancel",null)
                .show();
    }

到2020年

最近，最好和最短的方法是

@SuppressWarnings("deprecation")
public static Boolean isLocationEnabled(Context context) {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
        // This is a new method provided in API 28
        LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
        return lm.isLocationEnabled();
    } else {
        // This was deprecated in API 28
        int mode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
                Settings.Secure.LOCATION_MODE_OFF);
        return (mode != Settings.Secure.LOCATION_MODE_OFF);
    }
}

在我看来，这个if子句很容易检查位置服务是否可用:

LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
if(!locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) && !locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)) {
        //All location services are disabled

}