能用最简单的方法做吗

private boolean isLocationEnabled(Context context){
int mode =Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
                        Settings.Secure.LOCATION_MODE_OFF);
                final boolean enabled = (mode != android.provider.Settings.Secure.LOCATION_MODE_OFF);
return enabled;
}

kotlin的

 private fun isLocationEnabled(mContext: Context): Boolean {
    val lm = mContext.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return lm.isProviderEnabled(LocationManager.GPS_PROVIDER) || lm.isProviderEnabled(
            LocationManager.NETWORK_PROVIDER)
 }

对话框

private fun showLocationIsDisabledAlert() {
    alert("We can't show your position because you generally disabled the location service for your device.") {
        yesButton {
        }
        neutralPressed("Settings") {
            startActivity(Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS))
        }
    }.show()
}

像这样调用

 if (!isLocationEnabled(this.context)) {
        showLocationIsDisabledAlert()
 }

提示:对话框需要以下导入(android studio应该为你处理这个)

import org.jetbrains.anko.alert
import org.jetbrains.anko.noButton

在清单中，您需要以下权限

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>

我使用下面的代码来检查:

public static boolean isLocationEnabled(Context context) {
    int locationMode = 0;
    String locationProviders;

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
        try {
            locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);

        } catch (SettingNotFoundException e) {
            e.printStackTrace();
            return false;
        }

        return locationMode != Settings.Secure.LOCATION_MODE_OFF;

    }else{
        locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
        return !TextUtils.isEmpty(locationProviders);
    }


} 

You can also use extension function.
------------------------------------

fun Context.isLocationEnabled(): Boolean{
val locationManager = getSystemService(Context.LOCATION_SERVICE) as LocationManager
return LocationManagerCompat.isLocationEnabled(locationManager)}

我使用这样的方式NETWORK_PROVIDER，但你可以添加和GPS。

LocationManager locationManager;

在onCreate中

   isLocationEnabled();
   if(!isLocationEnabled()) {
        AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
        builder.setTitle(R.string.network_not_enabled)
                .setMessage(R.string.open_location_settings)
                .setPositiveButton(R.string.yes,
                        new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                                startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                            }
                        })
                .setNegativeButton(R.string.cancel,
                        new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                                dialog.cancel();
                            }
                        });
        AlertDialog alert = builder.create();
        alert.show();
    } 

检查方法

protected boolean isLocationEnabled(){
    String le = Context.LOCATION_SERVICE;
    locationManager = (LocationManager) getSystemService(le);
    if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
        return false;
    } else {
        return true;
    }
}

如果没有启用任何提供程序，则“passive”是返回的最佳提供程序。 参见https://stackoverflow.com/a/4519414/621690

    public boolean isLocationServiceEnabled() {
        LocationManager lm = (LocationManager)
                this.getSystemService(Context.LOCATION_SERVICE);
        String provider = lm.getBestProvider(new Criteria(), true);
        return (StringUtils.isNotBlank(provider) &&
                !LocationManager.PASSIVE_PROVIDER.equals(provider));
    }