function str_split(string, length = 1) {
    if (0 >= length)
        length = 1;
    
    if (length == 1)
        return string.split('');

    var string_size = string.length;
    var result = [];

    for (let i = 0; i < string_size / length; i++)
        result[i] = string.substr(i * length, length);

    return result;
}

str_split(str, 3)

基准测试:http://jsben.ch/HkjlU(不同浏览器的结果不同)

结果(Chrome 104)

var str = 'abcdefghijkl';
var res = str.match(/.../g)
console.log(res)

这里点的数量决定了你想在每个单词中包含多少文本。

如果你不想使用正则表达式…

var chunks = [];

for (var i = 0, charsLength = str.length; i < charsLength; i += 3) {
    chunks.push(str.substring(i, i + 3));
}

jsFiddle。

.．.否则正则表达式的解决方案是相当好的:)

我最喜欢的答案是gouder hicham的。但我稍微修改了一下，让它更有意义。

let myString = "Able was I ere I saw elba";

let splitString = [];
for (let i = 0; i < myString.length; i = i + 3) {
    splitString.push(myString.slice(i, i + 3));
}

console.log(splitString);

下面是该代码的一个功能化版本。

function stringSplitter(myString, chunkSize) {
    let splitString = [];
    for (let i = 0; i < myString.length; i = i + chunkSize) {
        splitString.push(myString.slice(i, i + chunkSize));
    }
    return splitString;
}

以及函数的用法:

let myString = "Able was I ere I saw elba";
let mySplitString = stringSplitter(myString, 3);
console.log(mySplitString);

结果是:

>(9) ['Abl', 'e w', 'as ', 'I e', 're ', 'I s', 'aw ', 'elb', 'a']

我的解决方案(ES6语法):

const source = "8d7f66a9273fc766cd66d1d";
const target = [];
for (
    const array = Array.from(source);
    array.length;
    target.push(array.splice(0,2).join(''), 2));

我们甚至可以这样创建一个函数:

function splitStringBySegmentLength(source, segmentLength) {
    if (!segmentLength || segmentLength < 1) throw Error('Segment length must be defined and greater than/equal to 1');
    const target = [];
    for (
        const array = Array.from(source);
        array.length;
        target.push(array.splice(0,segmentLength).join('')));
    return target;
}

然后你可以以一种可重用的方式轻松地调用函数:

const source = "8d7f66a9273fc766cd66d1d";
const target = splitStringBySegmentLength(source, 2);

干杯

str.match(/.{3}/g); // => ['abc', 'def', 'ghi', 'jkl']