**

The simplest way to search a specific value in an Array of Object
--------------------------------------------------------------------

filter() -> uses a callback function the return value of which decides what will be returned in the filtered array. If the return value is true, the item is included in the resultant array.

includes() -> searches for something in an array of items using == equality
**

       const words = [{id:1,name:"tim"},{id:2,name:"morgon"}]
        
          function searchHandler(enteredString){
          const formatedString = enteredString.toLowerCase();
          const result = words.filter(data=> data?.name?.includes(formatedString));
          console.log(result);
    }

你应该看看OGX。List，它内置了过滤方法，并扩展了标准javascript数组(以及分组、排序和查找)。下面是它为过滤器支持的操作符列表:

'eq' //Equal to
'eqjson' //For deep objects, JSON comparison, equal to
'neq' //Not equal to
'in' //Contains
'nin' //Doesn't contain
'lt' //Lesser than
'lte' //Lesser or equal to
'gt' //Greater than
'gte' //Greater or equal to
'btw' //Between, expects value to be array [_from_, _to_]
'substr' //Substring mode, equal to, expects value to be array [_from_, _to_, _niddle_]
'regex' //Regex match

你可以这样使用它

  let list = new OGX.List(your_array);
  list.addFilter('price', 'btw', 100, 500);
  list.addFilter('sqft', 'gte', 500);
  let filtered_list = list.filter();

或者这样

  let list = new OGX.List(your_array);
  let filtered_list = list.get({price:{btw:[100,500]}, sqft:{gte:500}});

或者作为一行

   let filtered_list = new OGX.List(your_array).get({price:{btw:[100,500]}, sqft:{gte:500}});

var filterHome = homes.filter(home =>
  return (home.price <= 999 &&
         home.num_of_baths >= 2.5 &&
         home.num_of_beds >=2 &&
         home.sqft >= 998));
console.log(filterHome);

你可以用这个函数。更多的细节可以在这里找到，因为我们过滤的数据基于你有条件返回真或假，它将收集数据在不同的数组，所以你的实际数组将不会被修改。

@JGreig请调查一下。

用于搜索数组中对象的所有属性的高级代码

b=[]; 
yourArray.forEach(x => {
      Object.keys(x).forEach(i => {if (x[i].match('5') && !b.filter(y => y === x).length) { b.push(x) }})
    });
console.log(b)

你可以自己实现一个过滤方法来满足你的需求，下面是如何实现的:

function myfilter(array, test){
    var passedTest =[];
    for (var i = 0; i < array.length; i++) {
       if(test( array[i]))
          passedTest.push(array[i]);
    }

    return passedTest;
}

var passedHomes = myfilter(homes,function(currentHome){
     return ((currentHome.price <= 1000 )&& (currentHome.sqft >= 500 )&&(currentHome.num_of_beds >=2 )&&(currentHome.num_of_baths >= 2.5));
});

希望有帮助!

你可以使用forEach

const filterOutputs = [];
json.homes.forEach((home) => {
if (
parseInt(home.price) <= 1000 &&
parseInt(home.sqft) >= 500 &&
parseInt(home.num_of_beds) >= 2 &&
parseInt(home.num_of_baths) >= 2
) {
filterOutputs.push(home);
}
});

console.log(filterOutputs);