你应该看看OGX。List，它内置了过滤方法，并扩展了标准javascript数组(以及分组、排序和查找)。下面是它为过滤器支持的操作符列表:

'eq' //Equal to
'eqjson' //For deep objects, JSON comparison, equal to
'neq' //Not equal to
'in' //Contains
'nin' //Doesn't contain
'lt' //Lesser than
'lte' //Lesser or equal to
'gt' //Greater than
'gte' //Greater or equal to
'btw' //Between, expects value to be array [_from_, _to_]
'substr' //Substring mode, equal to, expects value to be array [_from_, _to_, _niddle_]
'regex' //Regex match

你可以这样使用它

  let list = new OGX.List(your_array);
  list.addFilter('price', 'btw', 100, 500);
  list.addFilter('sqft', 'gte', 500);
  let filtered_list = list.filter();

或者这样

  let list = new OGX.List(your_array);
  let filtered_list = list.get({price:{btw:[100,500]}, sqft:{gte:500}});

或者作为一行

   let filtered_list = new OGX.List(your_array).get({price:{btw:[100,500]}, sqft:{gte:500}});

我很惊讶居然没有人发这样的回复:

const filteredHomes = json.homes.filter(x => x.price <= 1000 && x.sqft >= 500 && x.num_of_beds >=2 && x.num_of_baths >= 2.5);

.．.为了便于阅读:

const filteredHomes = json.homes.filter( x => 
  x.price <= 1000 && 
  x.sqft >= 500 && 
  x.num_of_beds >=2 && 
  x.num_of_baths >= 2.5
);

你可以很容易地做到这一点-可能有很多实现可供你选择，但这是我的基本想法(可能有一些格式，你可以用jQuery迭代一个对象，我只是现在想不起来):

function filter(collection, predicate)
{
    var result = new Array();
    var length = collection.length;

    for(var j = 0; j < length; j++)
    {
        if(predicate(collection[j]) == true)
        {
             result.push(collection[j]);
        }
    }

    return result;
}

然后你可以像这样调用这个函数:

filter(json, function(element)
{
    if(element.price <= 1000 && element.sqft >= 500 && element.num_of_beds > 2 && element.num_of_baths > 2.5)
        return true;

    return false;
});

这样，您可以根据定义的任何谓词调用筛选器，甚至可以使用更小的筛选器进行多次筛选。

var filterHome = homes.filter(home =>
  return (home.price <= 999 &&
         home.num_of_baths >= 2.5 &&
         home.num_of_beds >=2 &&
         home.sqft >= 998));
console.log(filterHome);

你可以用这个函数。更多的细节可以在这里找到，因为我们过滤的数据基于你有条件返回真或假，它将收集数据在不同的数组，所以你的实际数组将不会被修改。

@JGreig请调查一下。

使用数组过滤数据

const pickupData = [
    {
      id: 2876635,
      pickup_location: "6311cdacf6b493647d86",
      address_type: null,
      address: "999, Jagarati",``
      address_2: "Vihar",
      updated_address: false,
      old_address: "",
      old_address2: "",
      city: "Meerut",
      state: "Uttar Pradesh",
      country: "India",
      pin_code: "250001",
      email: "938@gmail.com",
      is_first_mile_pickup: 0,
      phone: "76898",
      name: "Aa",
      company_id: 2889808,
      gstin: null,
      vendor_name: null,
      status: 2,
      phone_verified: 1,
      lat: null,
      long: null,
      warehouse_code: null,
      alternate_phone: null,
      rto_address_id: 2867270,
      lat_long_status: 0,
      new: 1,
      associated_rto_address: null
    },
    {
      id: 2872407,
      pickup_location: "6311cdad490cf6b493647d82",
      address_type: null,
      address: "Nagar",
      address_2: "Delhi",
      updated_address: false,
      old_address: "",
      old_address2: "",
      city: "Bijnor",
      state: "Uttar Pradesh",
      country: "India",
      pin_code: "246701",
      email: "ima@gmail.com",
      is_first_mile_pickup: 0,
      phone: "75398",
      name: "Amit Sharma",
      company_id: 2889808,
      gstin: null,
      vendor_name: null,
      status: 1,
      phone_verified: 1,
      lat: null,
      long: null,
      warehouse_code: null,
      alternate_phone: null,
      rto_address_id: 2867270,
      lat_long_status: 0,
      new: 1,
      associated_rto_address: null
    }
  ];

const shiprocketData = [ { line1: "999, Jagarati", line2: "Vihar", city: "Meerut", state: "Uttar Pradesh", pincode: 250001, country: "India", isCurrent: true, _id: "6311cdad490cf6b3647d86" }, { line1: "999, Jagarati", line2: "Vihar", city: "Meerut", state: "Uttar Pradesh", pincode: 250001, country: "India", isCurrent: true, _id: "6311cdad490cb493647d82" }, { line1: "999, Jagarati", line2: "Vihar", city: "Meerut", state: "Uttar Pradesh", pincode: 250001, country: "India", isCurrent: true, _id: "6311cdad490cf693647d89" } ];

const updatedData = () => {
    const data = pickupData.filter(
      (item, index) =>
        item.pickup_location === shiprocketData.map((item) => item._id)[index]
    );
    return console.log(data);
  };

或者您可以简单地使用$。Each(它也适用于对象，而不仅仅是数组)，并像这样构建一个新数组:

var json = {
    'homes': [{
            "home_id": "1",
            "price": "925",
            "sqft": "1100",
            "num_of_beds": "2",
            "num_of_baths": "2.0",
        }, {
            "home_id": "2",
            "price": "1425",
            "sqft": "1900",
            "num_of_beds": "4",
            "num_of_baths": "2.5",
        },
        // ... (more homes) ...     
        {
            "home_id": "3-will-be-matched",
            "price": "925",
            "sqft": "1000",
            "num_of_beds": "2",
            "num_of_baths": "2.5",
        },
    ]
}

var homes = [];
$.each(json.homes, function(){
    if (this.price <= 1000
        && this.sqft >= 500
        && this.num_of_beds >= 2
        && this.num_of_baths >= 2.5
    ) {
        homes.push(this);
    }
});