我有以下JavaScript数组的房地产家对象:

var json = {
    'homes': [{
            "home_id": "1",
            "price": "925",
            "sqft": "1100",
            "num_of_beds": "2",
            "num_of_baths": "2.0",
        }, {
            "home_id": "2",
            "price": "1425",
            "sqft": "1900",
            "num_of_beds": "4",
            "num_of_baths": "2.5",
        },
        // ... (more homes) ...     
    ]
}

var xmlhttp = eval('(' + json + ')');
homes = xmlhttp.homes;

我想做的是能够对对象执行筛选,以返回“home”对象的子集。

例如,我希望能够基于:price、sqft、num_of_beds和num_of_baths进行过滤。

我如何在JavaScript中执行下面的伪代码:

var newArray = homes.filter(
    price <= 1000 & 
    sqft >= 500 & 
    num_of_beds >=2 & 
    num_of_baths >= 2.5 );

注意,语法不必完全像上面那样。这只是一个例子。


当前回答

使用数组过滤数据

const pickupData = [
    {
      id: 2876635,
      pickup_location: "6311cdacf6b493647d86",
      address_type: null,
      address: "999, Jagarati",``
      address_2: "Vihar",
      updated_address: false,
      old_address: "",
      old_address2: "",
      city: "Meerut",
      state: "Uttar Pradesh",
      country: "India",
      pin_code: "250001",
      email: "938@gmail.com",
      is_first_mile_pickup: 0,
      phone: "76898",
      name: "Aa",
      company_id: 2889808,
      gstin: null,
      vendor_name: null,
      status: 2,
      phone_verified: 1,
      lat: null,
      long: null,
      warehouse_code: null,
      alternate_phone: null,
      rto_address_id: 2867270,
      lat_long_status: 0,
      new: 1,
      associated_rto_address: null
    },
    {
      id: 2872407,
      pickup_location: "6311cdad490cf6b493647d82",
      address_type: null,
      address: "Nagar",
      address_2: "Delhi",
      updated_address: false,
      old_address: "",
      old_address2: "",
      city: "Bijnor",
      state: "Uttar Pradesh",
      country: "India",
      pin_code: "246701",
      email: "ima@gmail.com",
      is_first_mile_pickup: 0,
      phone: "75398",
      name: "Amit Sharma",
      company_id: 2889808,
      gstin: null,
      vendor_name: null,
      status: 1,
      phone_verified: 1,
      lat: null,
      long: null,
      warehouse_code: null,
      alternate_phone: null,
      rto_address_id: 2867270,
      lat_long_status: 0,
      new: 1,
      associated_rto_address: null
    }
  ];

const shiprocketData = [ { line1: "999, Jagarati", line2: "Vihar", city: "Meerut", state: "Uttar Pradesh", pincode: 250001, country: "India", isCurrent: true, _id: "6311cdad490cf6b3647d86" }, { line1: "999, Jagarati", line2: "Vihar", city: "Meerut", state: "Uttar Pradesh", pincode: 250001, country: "India", isCurrent: true, _id: "6311cdad490cb493647d82" }, { line1: "999, Jagarati", line2: "Vihar", city: "Meerut", state: "Uttar Pradesh", pincode: 250001, country: "India", isCurrent: true, _id: "6311cdad490cf693647d89" } ];

const updatedData = () => {
    const data = pickupData.filter(
      (item, index) =>
        item.pickup_location === shiprocketData.map((item) => item._id)[index]
    );
    return console.log(data);
  };

其他回答

你可以使用jQuery.grep()自jQuery 1.0:

$.grep(homes, function (h) {
  return h.price <= 1000
    && h.sqft >= 500
    && h.num_of_beds >= 2
    && h.num_of_baths >= 2.5
});

你可以使用forEach

const filterOutputs = [];
json.homes.forEach((home) => {
if (
parseInt(home.price) <= 1000 &&
parseInt(home.sqft) >= 500 &&
parseInt(home.num_of_beds) >= 2 &&
parseInt(home.num_of_baths) >= 2
) {
filterOutputs.push(home);
}
});

console.log(filterOutputs);
const y = 'search text';
const a = [{key: "x", "val: "y"},  {key: "d", "val: "z"}]
const data = a.filter(res => {
        return(JSON.stringify(res).toLocaleLowerCase()).match(y.toLocaleLowerCase());
});

你可以很容易地做到这一点-可能有很多实现可供你选择,但这是我的基本想法(可能有一些格式,你可以用jQuery迭代一个对象,我只是现在想不起来):

function filter(collection, predicate)
{
    var result = new Array();
    var length = collection.length;

    for(var j = 0; j < length; j++)
    {
        if(predicate(collection[j]) == true)
        {
             result.push(collection[j]);
        }
    }

    return result;
}

然后你可以像这样调用这个函数:

filter(json, function(element)
{
    if(element.price <= 1000 && element.sqft >= 500 && element.num_of_beds > 2 && element.num_of_baths > 2.5)
        return true;

    return false;
});

这样,您可以根据定义的任何谓词调用筛选器,甚至可以使用更小的筛选器进行多次筛选。

或者您可以简单地使用$。Each(它也适用于对象,而不仅仅是数组),并像这样构建一个新数组:

var json = {
    'homes': [{
            "home_id": "1",
            "price": "925",
            "sqft": "1100",
            "num_of_beds": "2",
            "num_of_baths": "2.0",
        }, {
            "home_id": "2",
            "price": "1425",
            "sqft": "1900",
            "num_of_beds": "4",
            "num_of_baths": "2.5",
        },
        // ... (more homes) ...     
        {
            "home_id": "3-will-be-matched",
            "price": "925",
            "sqft": "1000",
            "num_of_beds": "2",
            "num_of_baths": "2.5",
        },
    ]
}

var homes = [];
$.each(json.homes, function(){
    if (this.price <= 1000
        && this.sqft >= 500
        && this.num_of_beds >= 2
        && this.num_of_baths >= 2.5
    ) {
        homes.push(this);
    }
});