我有以下JavaScript数组的房地产家对象:

var json = {
    'homes': [{
            "home_id": "1",
            "price": "925",
            "sqft": "1100",
            "num_of_beds": "2",
            "num_of_baths": "2.0",
        }, {
            "home_id": "2",
            "price": "1425",
            "sqft": "1900",
            "num_of_beds": "4",
            "num_of_baths": "2.5",
        },
        // ... (more homes) ...     
    ]
}

var xmlhttp = eval('(' + json + ')');
homes = xmlhttp.homes;

我想做的是能够对对象执行筛选,以返回“home”对象的子集。

例如,我希望能够基于:price、sqft、num_of_beds和num_of_baths进行过滤。

我如何在JavaScript中执行下面的伪代码:

var newArray = homes.filter(
    price <= 1000 & 
    sqft >= 500 & 
    num_of_beds >=2 & 
    num_of_baths >= 2.5 );

注意,语法不必完全像上面那样。这只是一个例子。


当前回答

你可以使用forEach

const filterOutputs = [];
json.homes.forEach((home) => {
if (
parseInt(home.price) <= 1000 &&
parseInt(home.sqft) >= 500 &&
parseInt(home.num_of_beds) >= 2 &&
parseInt(home.num_of_baths) >= 2
) {
filterOutputs.push(home);
}
});

console.log(filterOutputs);

其他回答

你可以自己实现一个过滤方法来满足你的需求,下面是如何实现的:

function myfilter(array, test){
    var passedTest =[];
    for (var i = 0; i < array.length; i++) {
       if(test( array[i]))
          passedTest.push(array[i]);
    }

    return passedTest;
}

var passedHomes = myfilter(homes,function(currentHome){
     return ((currentHome.price <= 1000 )&& (currentHome.sqft >= 500 )&&(currentHome.num_of_beds >=2 )&&(currentHome.num_of_baths >= 2.5));
});

希望有帮助!

这里是工作提琴,在IE8使用jquery MAP函数工作良好

http://jsfiddle.net/533135/Cj4j7/

json.HOMES = $.map(json.HOMES, function(val, key) {
    if (Number(val.price) <= 1000
            && Number(val.sqft) >= 500
            && Number(val.num_of_beds) >=2
            && Number(val.num_of_baths ) >= 2.5)
        return val;
});

你可以使用forEach

const filterOutputs = [];
json.homes.forEach((home) => {
if (
parseInt(home.price) <= 1000 &&
parseInt(home.sqft) >= 500 &&
parseInt(home.num_of_beds) >= 2 &&
parseInt(home.num_of_baths) >= 2
) {
filterOutputs.push(home);
}
});

console.log(filterOutputs);

我很惊讶居然没有人发这样的回复:

const filteredHomes = json.homes.filter(x => x.price <= 1000 && x.sqft >= 500 && x.num_of_beds >=2 && x.num_of_baths >= 2.5);

...为了便于阅读:

const filteredHomes = json.homes.filter( x => 
  x.price <= 1000 && 
  x.sqft >= 500 && 
  x.num_of_beds >=2 && 
  x.num_of_baths >= 2.5
);

我看到有一种情况没有被覆盖,也许有人会像我一样寻找匹配的情况。情况下,当有人想要过滤属性值,这是字符串或数字使用过滤作为“where matches”条件,让我们说通过城市名称等。换句话说,就像Query:返回ALL homes数组WHERE city = "Chicago"。解决方法很简单:

  const filterByPropertyValue = (cityName) => {
    let filteredItems = homes.filter((item) => item.city === cityName);
    console.log("FILTERED HOMES BY CITY:", filteredItems);
  }

如果你需要通过编程或在HTML中循环/映射数组或通过提供'city'值来触发它(你也可以提供数组,只需要在函数中添加它来重用函数):

            <button
              onClick={() => {
                filterByPropertyValue("Chicago");
              }}
            >
              Chicago Homes Only
            </button>

假设JSON添加了城市属性:

'homes': [{
        "home_id": "1",
        "price": "925",
        "sqft": "1100",
        "num_of_beds": "2",
        "num_of_baths": "2.0",
        "city":"Chicago",
    }, {
        "home_id": "2",
        "price": "1425",
        "sqft": "1900",
        "num_of_beds": "4",
        "num_of_baths": "2.5",
        "city":"Chicago",
    },
    // ... (more homes) ...     
    {
        "home_id": "3-will-be-matched",
        "price": "925",
        "sqft": "1000",
        "num_of_beds": "2",
        "num_of_baths": "2.5",
        "city":"Atlanta",
    },
]