这里是工作提琴，在IE8使用jquery MAP函数工作良好

http://jsfiddle.net/533135/Cj4j7/

json.HOMES = $.map(json.HOMES, function(val, key) {
    if (Number(val.price) <= 1000
            && Number(val.sqft) >= 500
            && Number(val.num_of_beds) >=2
            && Number(val.num_of_baths ) >= 2.5)
        return val;
});

const y = 'search text';
const a = [{key: "x", "val: "y"},  {key: "d", "val: "z"}]
const data = a.filter(res => {
        return(JSON.stringify(res).toLocaleLowerCase()).match(y.toLocaleLowerCase());
});

你可以很容易地做到这一点-可能有很多实现可供你选择，但这是我的基本想法(可能有一些格式，你可以用jQuery迭代一个对象，我只是现在想不起来):

function filter(collection, predicate)
{
    var result = new Array();
    var length = collection.length;

    for(var j = 0; j < length; j++)
    {
        if(predicate(collection[j]) == true)
        {
             result.push(collection[j]);
        }
    }

    return result;
}

然后你可以像这样调用这个函数:

filter(json, function(element)
{
    if(element.price <= 1000 && element.sqft >= 500 && element.num_of_beds > 2 && element.num_of_baths > 2.5)
        return true;

    return false;
});

这样，您可以根据定义的任何谓词调用筛选器，甚至可以使用更小的筛选器进行多次筛选。

我更喜欢下划线框架。它提出了许多有用的对象操作。 你的任务:

var newArray = homes.filter(
    price <= 1000 & 
    sqft >= 500 &
    num_of_beds >=2 & 
    num_of_baths >= 2.5);

可以像这样覆盖:

var newArray = _.filter (homes, function(home) {
    return home.price<=1000 && sqft>=500 && num_of_beds>=2 && num_of_baths>=2.5;
});

希望对大家有用!

或者您可以简单地使用$。Each(它也适用于对象，而不仅仅是数组)，并像这样构建一个新数组:

var json = {
    'homes': [{
            "home_id": "1",
            "price": "925",
            "sqft": "1100",
            "num_of_beds": "2",
            "num_of_baths": "2.0",
        }, {
            "home_id": "2",
            "price": "1425",
            "sqft": "1900",
            "num_of_beds": "4",
            "num_of_baths": "2.5",
        },
        // ... (more homes) ...     
        {
            "home_id": "3-will-be-matched",
            "price": "925",
            "sqft": "1000",
            "num_of_beds": "2",
            "num_of_baths": "2.5",
        },
    ]
}

var homes = [];
$.each(json.homes, function(){
    if (this.price <= 1000
        && this.sqft >= 500
        && this.num_of_beds >= 2
        && this.num_of_baths >= 2.5
    ) {
        homes.push(this);
    }
});

我看到有一种情况没有被覆盖，也许有人会像我一样寻找匹配的情况。情况下，当有人想要过滤属性值，这是字符串或数字使用过滤作为“where matches”条件，让我们说通过城市名称等。换句话说，就像Query:返回ALL homes数组WHERE city = "Chicago"。解决方法很简单:

  const filterByPropertyValue = (cityName) => {
    let filteredItems = homes.filter((item) => item.city === cityName);
    console.log("FILTERED HOMES BY CITY:", filteredItems);
  }

如果你需要通过编程或在HTML中循环/映射数组或通过提供'city'值来触发它(你也可以提供数组，只需要在函数中添加它来重用函数):

            <button
              onClick={() => {
                filterByPropertyValue("Chicago");
              }}
            >
              Chicago Homes Only
            </button>

假设JSON添加了城市属性:

'homes': [{
        "home_id": "1",
        "price": "925",
        "sqft": "1100",
        "num_of_beds": "2",
        "num_of_baths": "2.0",
        "city":"Chicago",
    }, {
        "home_id": "2",
        "price": "1425",
        "sqft": "1900",
        "num_of_beds": "4",
        "num_of_baths": "2.5",
        "city":"Chicago",
    },
    // ... (more homes) ...     
    {
        "home_id": "3-will-be-matched",
        "price": "925",
        "sqft": "1000",
        "num_of_beds": "2",
        "num_of_baths": "2.5",
        "city":"Atlanta",
    },
]