当通过lambda表达式传入时，是否有更好的方法来获得属性名?
这是我目前拥有的。
eg.
GetSortingInfo<User>(u => u.UserId);
它只在属性为字符串时才将其转换为成员表达式。因为不是所有的属性都是字符串，我必须使用object，但它会为那些返回一个unaryexpression。
public static RouteValueDictionary GetInfo<T>(this HtmlHelper html,
Expression<Func<T, object>> action) where T : class
{
var expression = GetMemberInfo(action);
string name = expression.Member.Name;
return GetInfo(html, name);
}
private static MemberExpression GetMemberInfo(Expression method)
{
LambdaExpression lambda = method as LambdaExpression;
if (lambda == null)
throw new ArgumentNullException("method");
MemberExpression memberExpr = null;
if (lambda.Body.NodeType == ExpressionType.Convert)
{
memberExpr =
((UnaryExpression)lambda.Body).Operand as MemberExpression;
}
else if (lambda.Body.NodeType == ExpressionType.MemberAccess)
{
memberExpr = lambda.Body as MemberExpression;
}
if (memberExpr == null)
throw new ArgumentException("method");
return memberExpr;
}
假设(TModel作为类)
Expression<Func<TModel, TValue>> expression
检索属性的名称
expression.GetPropertyInfo().Name;
扩展函数:
public static PropertyInfo GetPropertyInfo<TType, TReturn>(this Expression<Func<TType, TReturn>> property)
{
LambdaExpression lambda = property;
var memberExpression = lambda.Body is UnaryExpression expression
? (MemberExpression)expression.Operand
: (MemberExpression)lambda.Body;
return (PropertyInfo)memberExpression.Member;
}
下面是基于这个答案获取PropertyInfo的另一种方法。它消除了对对象实例的需要。
/// <summary>
/// Get metadata of property referenced by expression. Type constrained.
/// </summary>
public static PropertyInfo GetPropertyInfo<TSource, TProperty>(Expression<Func<TSource, TProperty>> propertyLambda)
{
return GetPropertyInfo((LambdaExpression) propertyLambda);
}
/// <summary>
/// Get metadata of property referenced by expression.
/// </summary>
public static PropertyInfo GetPropertyInfo(LambdaExpression propertyLambda)
{
// https://stackoverflow.com/questions/671968/retrieving-property-name-from-lambda-expression
MemberExpression member = propertyLambda.Body as MemberExpression;
if (member == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a method, not a property.",
propertyLambda.ToString()));
PropertyInfo propInfo = member.Member as PropertyInfo;
if (propInfo == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a field, not a property.",
propertyLambda.ToString()));
if(propertyLambda.Parameters.Count() == 0)
throw new ArgumentException(String.Format(
"Expression '{0}' does not have any parameters. A property expression needs to have at least 1 parameter.",
propertyLambda.ToString()));
var type = propertyLambda.Parameters[0].Type;
if (type != propInfo.ReflectedType &&
!type.IsSubclassOf(propInfo.ReflectedType))
throw new ArgumentException(String.Format(
"Expression '{0}' refers to a property that is not from type {1}.",
propertyLambda.ToString(),
type));
return propInfo;
}
它可以这样调用:
var propertyInfo = GetPropertyInfo((User u) => u.UserID);
我最近做了一件非常类似的事情来创建一个类型安全的OnPropertyChanged方法。
下面是一个方法，它将返回表达式的PropertyInfo对象。如果表达式不是属性，则抛出异常。
public PropertyInfo GetPropertyInfo<TSource, TProperty>(
TSource source,
Expression<Func<TSource, TProperty>> propertyLambda)
{
Type type = typeof(TSource);
MemberExpression member = propertyLambda.Body as MemberExpression;
if (member == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a method, not a property.",
propertyLambda.ToString()));
PropertyInfo propInfo = member.Member as PropertyInfo;
if (propInfo == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a field, not a property.",
propertyLambda.ToString()));
if (type != propInfo.ReflectedType &&
!type.IsSubclassOf(propInfo.ReflectedType))
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a property that is not from type {1}.",
propertyLambda.ToString(),
type));
return propInfo;
}
使用源参数，编译器可以对方法调用进行类型推断。您可以执行以下操作
var propertyInfo = GetPropertyInfo(someUserObject, u => u.UserID);
这是一个通用的实现，用于获取struct/class/interface/delegate/array的字段/属性/索引器/方法/扩展方法/委托的字符串名称。我已经测试了静态/实例和非泛型/泛型变体的组合。
//involves recursion
public static string GetMemberName(this LambdaExpression memberSelector)
{
Func<Expression, string> nameSelector = null; //recursive func
nameSelector = e => //or move the entire thing to a separate recursive method
{
switch (e.NodeType)
{
case ExpressionType.Parameter:
return ((ParameterExpression)e).Name;
case ExpressionType.MemberAccess:
return ((MemberExpression)e).Member.Name;
case ExpressionType.Call:
return ((MethodCallExpression)e).Method.Name;
case ExpressionType.Convert:
case ExpressionType.ConvertChecked:
return nameSelector(((UnaryExpression)e).Operand);
case ExpressionType.Invoke:
return nameSelector(((InvocationExpression)e).Expression);
case ExpressionType.ArrayLength:
return "Length";
default:
throw new Exception("not a proper member selector");
}
};
return nameSelector(memberSelector.Body);
}
这个东西也可以写在一个简单的while循环中:
//iteration based
public static string GetMemberName(this LambdaExpression memberSelector)
{
var currentExpression = memberSelector.Body;
while (true)
{
switch (currentExpression.NodeType)
{
case ExpressionType.Parameter:
return ((ParameterExpression)currentExpression).Name;
case ExpressionType.MemberAccess:
return ((MemberExpression)currentExpression).Member.Name;
case ExpressionType.Call:
return ((MethodCallExpression)currentExpression).Method.Name;
case ExpressionType.Convert:
case ExpressionType.ConvertChecked:
currentExpression = ((UnaryExpression)currentExpression).Operand;
break;
case ExpressionType.Invoke:
currentExpression = ((InvocationExpression)currentExpression).Expression;
break;
case ExpressionType.ArrayLength:
return "Length";
default:
throw new Exception("not a proper member selector");
}
}
}
我喜欢递归方法，尽管第二种方法可能更容易阅读。我们可以这样称呼它:
someExpr = x => x.Property.ExtensionMethod()[0]; //or
someExpr = x => Static.Method().Field; //or
someExpr = x => VoidMethod(); //or
someExpr = () => localVariable; //or
someExpr = x => x; //or
someExpr = x => (Type)x; //or
someExpr = () => Array[0].Delegate(null); //etc
string name = someExpr.GetMemberName();
打印最后一个成员。
注意:
对于像a.b.c.这样的链式表达式，将返回“C”。
这并不适用于const，数组索引器或枚举(不可能涵盖所有情况)。
